微积分I(标准路径) · free preview

§1.1 How do we measure velocity?

运动物体的平均速度与其位置函数的值之间有什么联系?

1. Introduction

Introduction

2. Position and average velocity

Position and average velocity

3. Instantaneous Velocity

Instantaneous Velocity

4. Summary

Summary

5. The position functio…

The position function for a falling ball is given by s(t)=16−16t2s(t) = 16 - 16t^2 (where ss is measured in feet and tt in seconds).

  • Find an expression for the average velocity of the ball on a time interval of the form [0.5,0.5+h][0.5, 0.5+h] where −0.5<h<0.5-0.5 \lt h \lt 0.5 and h≠0h \ne 0. - Use this expression to compute the average velocity on [0.5,0.75][0.5,0.75] and [0.4,0.5][0.4,0.5]. - Make a conjecture about the instantaneous velocity at t=0.5t = 0.5.

6. Average velocity on a falling-ball interval

A ball's height in feet is s(t)=64−16(t−1)2s(t) = 64 - 16(t-1)^2 with tt in seconds. What is the average velocity of the ball on the interval [1.5,2][1.5, 2]?

7. Instantaneous velocity at the peak

For the same ball with s(t)=64−16(t−1)2s(t) = 64 - 16(t-1)^2, the ball reaches its highest point at t=1t = 1. What is the instantaneous velocity of the ball at t=1t = 1?

8. Meaning of an average velocity value

A computation shows that the average velocity of the ball on [0.4,0.8][0.4, 0.8] equals 12.812.8 ft/sec. What does this number tell you?

9. One average velocity from the table

For the ball with s(t)=64−16(t−1)2s(t) = 64 - 16(t-1)^2, compute the average velocity on the interval [0.7,0.8][0.7, 0.8]. Round to the nearest integer and give the number of feet per second.

10. Release height of the ball

The ball's height is s(t)=64−16(t−1)2s(t) = 64 - 16(t-1)^2 feet at time tt seconds, and the ball is released at t=0t = 0. How many feet above the ground is the ball at the moment it is released?

11. Sign of velocity and direction of motion

If the instantaneous velocity of a moving object is negative at some time, then the object's position is decreasing at that instant.

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