微积分I(标准路径) · free preview

§1.6 The second derivative

函数的导数如何告诉我们该函数在某个区间上是递增还是递减?

1. Introduction

Introduction

2. Increasing or decreasing

Increasing or decreasing

3. The Second Derivative

The Second Derivative

4. Concavity

Concavity

5. Summary

Summary

6. Computing acceleration from position

An object has position s(t)s(t), velocity v(t)=s′(t)v(t) = s'(t), and acceleration a(t)a(t). Which formula gives a(t)a(t) from ss?

7. Reading position, slope, and bend together

A twice differentiable function satisfies f(2)=−3f(2) = -3, f′(2)=1.5f'(2) = 1.5, and f′′(2)=−0.25f''(2) = -0.25. Near x=2x = 2 the graph of ff is

8. Velocity and acceleration signs together

A car's position function has v(t)>0v(t) \gt 0 and a(t)<0a(t) \lt 0 on some interval. What is the car doing there?

9. Second derivative by central difference

For a potato's temperature, central differences gave F′(20)≈3.645F'(20) \approx 3.645 and F′(40)≈1.515F'(40) \approx 1.515 degrees per minute. Estimate F′′(30)F''(30) with a central difference, rounded to four decimals, in degrees per minute per minute.

10. Bungee jumper rising rate

A bungee jumper's height satisfies h(4)=55.5h(4) = 55.5 and h(5)=69.8h(5) = 69.8 feet. Estimate h′(4.5)h'(4.5) in feet per second using a central difference over [4,5][4, 5], rounded to one decimal.

11. Rising velocity forces positive second derivative

If s′s' is increasing on an interval, then s′′>0s'' \gt 0 on that interval.

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