Multivariable Calculus · free preview

Global Extrema and Boundary Analysis

The extreme value theorem for continuous functions on closed bounded regions, boundary optimization by parametrization, and the complete recipe for absolute maxima and minima.

1. Closed bounded regions guarantee champions

Closed bounded regions guarantee champions

2. The boundary is a one-variable problem in disguise

The boundary is a one-variable problem in disguise

3. The complete recipe on a worked example

The complete recipe on a worked example

4. Why the recipe is complete

Why the recipe is complete

5. Reading the extreme value theorem

Which condition guarantees that a continuous function attains an absolute maximum and minimum on a region?

6. Sweeping a circular boundary

On the rim of the disk x2+y2≤4x^2 + y^2 \le 4, parametrized as (2cos⁡t,2sin⁡t)(2\cos t, 2\sin t), what does f(x,y)=x2+y2−2xf(x, y) = x^2 + y^2 - 2x become?

7. Completing the comparison

With candidates (1,0)(1,0) at value −1-1, (2,0)(2,0) at value 00 and (−2,0)(-2,0) at value 88 for f=x2+y2−2xf = x^2 + y^2 - 2x on the disk of radius 22, what are the absolute extrema?

8. A rectangle edge candidate

The rectangle 0≤x≤20 \le x \le 2, 0≤y≤10 \le y \le 1 has its top edge at y=1y = 1. Restricting f(x,y)=x+2yf(x, y) = x + 2y to that edge gives a one-variable function g(x)=x+2g(x) = x + 2. Give the maximum value of gg on the edge, as a plain number.

9. Counting candidates on a triangle

A triangular region's boundary consists of ee edges and cc corner points. Give e+ce + c, the number of boundary sweeps plus corner candidates, as a plain number.

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