Calculus Volume 1 · free preview

Related Rates

When linked quantities all change with time, differentiating the constraint equation with respect to time produces an equation among their rates, solvable for any one rate from the others.

1. Constraints among changing quantities

Constraints among changing quantities

2. The solution procedure

The solution procedure

3. Reading the geometry

Reading the geometry

4. The shadow template

The shadow template

5. The key differentiation step

In a related rates problem where variables x and y both depend on time t, what does differentiating the constraint x^2 + y^2 = 25 with respect to t produce?

6. When to substitute values

At which step of the related rates procedure should the numerical values at the instant of interest be substituted?

7. Ladder problem rate

A 5 meter ladder slides down a wall, the foot moving outward at dx/dt = 0.3 meters per second. When the foot is x = 3 meters out, the top is y = 4 meters high. How fast is the top moving?

8. Balloon radius rate

A spherical balloon is inflated at dV/dt = 10 cubic centimeters per second. Using dV/dt = 4 pi r^2 dr/dt, how fast is the radius growing when r = 5 centimeters?

9. Negative rate meaning

In a related rates solution, one quantity's rate comes out negative, say dV/dt = -5 cubic centimeters per second for a draining tank. What does the negative sign mean?

10. Which rate is asked for

A related rates problem states dV/dt = 10 and asks for dr/dt at r = 5. Which quantity's rate is the unknown?

11. Cone volume derivative

The volume of a cone is V = (1/3) pi r^2 h. If the radius is constant and only the height changes, dV/dt equals a constant times dh/dt. That constant is pi r^2 over what number? Answer with a number.

12. Instant value in the ladder

In the ladder problem with x^2 + y^2 = 25, when x = 3 the corresponding height y of the top equals what number? Answer with a number.

13. Rate units

A related rates equation balances 2x dx/dt against 2y dy/dt, where x and y are in meters. What unit must dx/dt carry? Answer like meters per second.

14. Boat rope setup

A boat is pulled by a rope of length L toward a dock, with horizontal distance x from the dock and the rope arriving from a point 8 meters above the water. The constraint is x^2 + 64 = L^2. Differentiating gives 2x dx/dt equal to what expression in L and dL/dt? Answer like 2L dL/dt.

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