Calculus Volume 1 · free preview

Derivatives and the Shape of a Graph

The first derivative's sign chart reveals where a graph rises and falls, the second derivative's sign chart reveals where it bends up or down, and the two together with asymptotes assemble the complete qualitative graph.

1. Increase, decrease, and local extrema

Increase, decrease, and local extrema

2. Concavity and the second derivative

Concavity and the second derivative

3. The full curve-sketching protocol

The full curve-sketching protocol

4. A worked sketch

A worked sketch

5. Sign chart reading

The derivative f prime is positive on (-3, 0) and negative on (0, 2). What does f do on those intervals?

6. Second derivative and concavity

On an interval, f double prime of x is negative everywhere. What does that say about the graph of f there?

7. Inflection point condition

Which condition identifies an inflection point of f at an interior point c?

8. Cubic local maximum

For f(x) = x^3 - 3x^2 - 9x + 5 with f prime of x = 3(x+1)(x-3), which point is the local maximum?

9. Concavity of the cubic

For the same cubic, f double prime of x = 6x - 6. Where is the graph concave up?

10. Vanishing second derivative at a non-inflection point

The function f(x) = x^4 has f double prime of 0 = 0, yet the origin is NOT an inflection point. Why not?

11. Cubic local maximum value

For f(x) = x^3 - 3x^2 - 9x + 5, the local maximum occurs at x = -1. What is the value f(-1)? Answer with a number.

12. Inflection point location

The graph of f has f double prime of x = 6x - 6. At what x does the inflection point occur? Answer with a number.

13. Sign chart interval count

The real line is partitioned by two critical points, x = -1 and x = 3. How many intervals of constant sign for f prime result? Answer with a number.

14. Decreasing stretch endpoints

The cubic f falls on the interval (-1, 3). What is the length of this decreasing stretch? Answer with a number.

Practice this interactively

Free account · instant grading · spaced review that schedules itself.

Start this course for free