Calculus Volume 1 · free preview

Applied Optimization Problems

Optimization translates a real situation into a function of one variable on a closed interval, whose absolute extrema the closed interval method then locates, and the modeling steps of constraint and domain are where the real work lies.

1. From situation to function

From situation to function

2. Constraints and domains

Constraints and domains

3. Interpreting and verifying

Interpreting and verifying

4. Optimization in economics

Optimization in economics

5. First modeling step

In solving an applied optimization problem, which step comes first?

6. Why the domain matters

Why must the domain of an applied optimization function be checked before differentiating?

7. Box problem optimum

The open box from a 12 unit square sheet has volume V(x) = x(12 - 2x)^2 on [0, 6]. What cut size x maximizes the volume?

8. Fence constraint elimination

A rectangular field against a river uses 100 meters of fence on three sides, area A = x y with 2x + y = 100. What is the area as a function of x alone?

9. Endpoint versus interior optimum

Under what conditions does an applied optimization's optimum occur at an endpoint rather than an interior critical point?

10. Verifying the optimum

In the box problem, besides the endpoint comparison, which additional check certifies x = 2 as a maximum?

11. Box maximum volume

The open box volume V(x) = x(12 - 2x)^2 on [0, 6] is maximized at x = 2. What is the maximum volume? Answer with a number.

12. Fence optimal width

The fenced area A(x) = x(100 - 2x) has derivative 100 - 4x. At what x is the area maximized? Answer with a number.

13. Domain right endpoint

In the box problem the domain of V(x) = x(12 - 2x)^2 is [0, 6]. What is the right endpoint of the domain? Answer with a number.

14. Second derivative check

For A(x) = x(100 - 2x), the second derivative is constant. What is its value? Answer with a number.

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