Calculus Volume 3 · free preview

Calculus of Parametric Curves

Differentiating and integrating parametrically defined curves converts slope, arc length, and surface area into integrals with respect to the parameter, using the chain rule to obtain the slope and the speed to obtain arc length.

1. Slope from the parameter

Slope from the parameter

2. Higher derivatives and tangent lines

Higher derivatives and tangent lines

3. Arc length along a parametric curve

Arc length along a parametric curve

4. Surfaces of revolution

Surfaces of revolution

5. Slope of a parametric curve

For x(t) = t squared and y(t) = 2t, what is the slope dy/dx at the parameter value t = 2?

6. Locating a vertical tangent

For a parametric curve, at which parameter values does the curve have a vertical tangent line?

7. Arc length integrand

Which integrand gives the arc length of a parametric curve over the interval from a to b?

8. Arc length of a straight parametrization

For x = 3t and y = 4t on the interval from 0 to 2, what is the arc length?

9. Surface area by revolution

Which expression gives the area of the surface formed by revolving a parametric curve about the x axis?

10. Parametric versus Cartesian setup

For a curve given parametrically, which computation finds the tangent line's slope at a point?

11. Slope at a parameter value

For x(t) = t squared and y(t) = 2t, what is the slope dy/dx at t = 2? Give a decimal number.

12. A second derivative

For x(t) = t squared and y(t) = t cubed, what is the second derivative of y with respect to x at t = 1? Give a decimal number.

13. Length of a straight path

For x = 3t and y = 4t on the interval from 0 to 2, what is the arc length? Give a number.

14. Slope with a linear coordinate

For x(t) = t and y(t) = t squared, what is the slope dy/dx at t = 3? Give a number.

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