Calculus Volume 3 · free preview
Calculus of Parametric Curves
Differentiating and integrating parametrically defined curves converts slope, arc length, and surface area into integrals with respect to the parameter, using the chain rule to obtain the slope and the speed to obtain arc length.
1. Slope from the parameter
Slope from the parameter
2. Higher derivatives and tangent lines
Higher derivatives and tangent lines
3. Arc length along a parametric curve
Arc length along a parametric curve
4. Surfaces of revolution
Surfaces of revolution
5. Slope of a parametric curve
For x(t) = t squared and y(t) = 2t, what is the slope dy/dx at the parameter value t = 2?
6. Locating a vertical tangent
For a parametric curve, at which parameter values does the curve have a vertical tangent line?
7. Arc length integrand
Which integrand gives the arc length of a parametric curve over the interval from a to b?
8. Arc length of a straight parametrization
For x = 3t and y = 4t on the interval from 0 to 2, what is the arc length?
9. Surface area by revolution
Which expression gives the area of the surface formed by revolving a parametric curve about the x axis?
10. Parametric versus Cartesian setup
For a curve given parametrically, which computation finds the tangent line's slope at a point?
11. Slope at a parameter value
For x(t) = t squared and y(t) = 2t, what is the slope dy/dx at t = 2? Give a decimal number.
12. A second derivative
For x(t) = t squared and y(t) = t cubed, what is the second derivative of y with respect to x at t = 1? Give a decimal number.
13. Length of a straight path
For x = 3t and y = 4t on the interval from 0 to 2, what is the arc length? Give a number.
14. Slope with a linear coordinate
For x(t) = t and y(t) = t squared, what is the slope dy/dx at t = 3? Give a number.
Practice this interactively
Free account · instant grading · spaced review that schedules itself.
Start this course for free