Elementary Algebra 2e · free preview

1.4 Multiply and Divide Integers

Learning objectives: Multiply integers; Divide integers; Simplify expressions with integers; Evaluate variable expressions with integers; Translate English phrases to algebraic expressions; Use integers in applications

1. Learning objectives

Learning objectives

Learning objectives

  • Multiply integers
  • Divide integers
  • Simplify expressions with integers
  • Evaluate variable expressions with integers
  • Translate English phrases to algebraic expressions
  • Use integers in applications

2. Multiply Integers

Multiply Integers

Since multiplication is mathematical shorthand for repeated addition, our model can easily be applied to show multiplication of integers. Let’s look at this concrete model to see what patterns we notice. We will use the same examples that we used for addition and subtraction. Here, we will use the model just to help us discover the pattern.

We remember that a⋅ba\cdot{}b means add a, b times.

The next two examples are more interesting.

What does it mean to multiply 5 by −3?-3? It means subtract 5, 3 times. Looking at subtraction as “taking away,” it means to take away 5, 3 times. But there is nothing to take away, so we start by adding neutral pairs on the workspace. Then we take away 5 three times.

In summary:

5⋅3=15−5(3)=−155(−3)=−15(−5)(−3)=15\begin{array}{rllccrll} 5\cdot{}3 & = & 15 & & & -5(3) & = & -15 \\ 5(-3) & = & -15 & & & (-5)(-3) & = & 15 \\ \end{array}

Notice that for multiplication of two signed numbers, when the:

  • signs are the same, the product is positive.
  • signs are different, the product is negative.

We’ll put this all together in the chart below.

For multiplication of two signed numbers:

Same signsProductExample
Two positivesTwo negativesPositivePositive7⋅4=28−8(−6)=48\begin{array}{rll} 7\cdot{}4 & = & 28 \\ -8(-6) & = & 48 \\ \end{array}
Different signsProductExample
---------
Positive · negativeNegative · positiveNegativeNegative7(−9)=−63−5⋅10=−50\begin{array}{rll} 7(-9) & = & -63 \\ -5\cdot{}10 & = & -50 \\ \end{array}

3. Example 1.46

Example 1.46

Example 1.46

Multiply: ⓐ −9⋅3-9\cdot{}3 ⓑ −2(−5)-2(-5) ⓒ 4(−8)4(-8) ⓓ 7⋅6.7\cdot{}6.

Solution

ⓐ Multiply, noting that the signs are different so the product is negative.−9⋅3−27\begin{array}{c} -9\cdot{}3 \\ -27 \\ \end{array}
ⓑ Multiply, noting that the signs are the same so the product is positive.−2(−5)10\begin{array}{c} -2(-5) \\ 10 \\ \end{array}
ⓒ Multiply, with different signs.4(−8)−32\begin{array}{c} 4(-8) \\ -32 \\ \end{array}
ⓓ Multiply, with same signs.7⋅642\begin{array}{c} 7\cdot{}6 \\ 42 \\ \end{array}

Table

1.8

When we multiply a number by 1, the result is the same number. What happens when we multiply a number by −1?-1? Let’s multiply a positive number and then a negative number by −1-1 to see what we get.

−1⋅4−1(−3)Multiply.−43−4 istheoppositeof 4.3 istheoppositeof −3.\begin{array}{ccccccc} & & & -1\cdot{}4 & & & -1(-3) \\ \mathrm{Multiply.} & & & -4 & & & 3 \\ & & & -4\,\mathrm{is the opposite of}\,4. & & & 3\,\mathrm{is the opposite of}\,-3. \\ \end{array}

Each time we multiply a number by −1,-1, we get its opposite!

−1a=−a-1a=-a

Multiplying a number by −1-1 gives its opposite.

4. Example 1.47

Example 1.47

Example 1.47

Multiply: ⓐ −1⋅7-1\cdot{}7 ⓑ −1(−11).-1(-11).

Solution

ⓐ Multiply, noting that the signs are different so the product is negative.−1⋅7−7−7 istheoppositeof 7.\begin{array}{c} -1\cdot{}7 \\ -7 \\ -7\,\mathrm{is the opposite of}\,7. \\ \end{array}
ⓑ Multiply, noting that the signs are the same so the product is positive.−1(−11)1111 istheoppositeof −11.\begin{array}{c} -1(-11) \\ 11 \\ 11\,\mathrm{is the opposite of}\,-11. \\ \end{array}

Table

1.9

5. Divide Integers

Divide Integers

What about division? Division is the inverse operation of multiplication. So, 15÷3=515\mathrm{÷}3=5 because 5⋅3=15.5\cdot{}3=15. In words, this expression says that 15 can be divided into three groups of five each because adding five three times gives 15. Look at some examples of multiplying integers, to figure out the rules for dividing integers.

5⋅3=15 so 15÷3=5−5(3)=−15 so −15÷3=−5(−5)(−3)=15 so 15÷(−3)=−55(−3)=−15 so −15÷(−3)=5\begin{array}{rllllccccrllll} 5\cdot{}3 & = & 15\,\mathrm{so}\,15\mathrm{÷}3 & = & 5 & & & & & -5(3) & = & -15\,\mathrm{so}\,-15\mathrm{÷}3 & = & -5 \\ (-5)(-3) & = & 15\,\mathrm{so}\,15\mathrm{÷}(-3) & = & -5 & & & & & 5(-3) & = & -15\,\mathrm{so}\,-15\mathrm{÷}(-3) & = & 5 \\ \end{array}

Division follows the same rules as multiplication!

For division of two signed numbers, when the:

  • signs are the same, the quotient is positive.
  • signs are different, the quotient is negative.

And remember that we can always check the answer of a division problem by multiplying.

For multiplication and division of two signed numbers:

  • If the signs are the same, the result is positive.
  • If the signs are different, the result is negative.
Same signsResult
Two positivesTwo negativesPositivePositive
If the signs are the same, the result is positive.
Different signsResult
------
Positive and negativeNegative and positiveNegativeNegative
If the signs are different, the result is negative.

6. Example 1.48

Example 1.48

Example 1.48

Divide: ⓐ −27÷3-27\mathrm{÷}3 ⓑ −100÷(−4).-100\mathrm{÷}(-4).

Solution

ⓐ Divide. With different signs, the quotient is negative.−27÷3−9\begin{array}{c} -27\mathrm{÷}3 \\ -9 \\ \end{array}
ⓑ Divide. With signs that are the same, the quotient is positive.−100÷(−4)25\begin{array}{c} -100\mathrm{÷}(-4) \\ 25 \\ \end{array}

Table

1.10

7. Simplify Expressions with Integers

Simplify Expressions with Integers

What happens when there are more than two numbers in an expression? The order of operations still applies when negatives are included. Remember My Dear Aunt Sally?

Let’s try some examples. We’ll simplify expressions that use all four operations with integers—addition, subtraction, multiplication, and division. Remember to follow the order of operations.

8. Example 1.49

Example 1.49

Example 1.49

Simplify: 7(−2)+4(−7)−6.7(-2)+4(-7)-6.

Solution

7(−2)+4(−7)−67(-2)+4(-7)-6
Multiply first.−14+(−28)−6-14+(-28)-6
Add.−42−6-42-6
Subtract.−48-48

Table

1.11

9. Example 1.50

Example 1.50

Example 1.50

Simplify: ⓐ (−2)4{(-2)}^{4} ⓑ −24.-{2}^{4}.

Solution

ⓐ Write in expanded form. Multiply. Multiply. Multiply.(−2)4(−2)(−2)(−2)(−2)4(−2)(−2)−8(−2)16\begin{array}{c} {(-2)}^{4} \\ (-2)(-2)(-2)(-2) \\ 4(-2)(-2) \\ -8(-2) \\ 16 \\ \end{array}
ⓑ Write in expanded form. We are asked to find the opposite of 24.\,{2}^{4}. Multiply. Multiply. Multiply.−24−(2⋅2⋅2⋅2)−(4⋅2⋅2)−(8⋅2)−16\begin{array}{c} -{2}^{4} \\ -(2\cdot{}2\cdot{}2\cdot{}2) \\ -(4\cdot{}2\cdot{}2) \\ -(8\cdot{}2) \\ -16 \\ \end{array}

Table

1.12

Notice the difference in parts ⓐ and ⓑ. In part ⓐ , the exponent means to raise what is in the parentheses, the (−2)(-2) to the 4th{4}^{\mathrm{th}} power. In part ⓑ , the exponent means to raise just the 2 to the 4th{4}^{\mathrm{th}} power and then take the opposite.

The next example reminds us to simplify inside parentheses first.

10. Example 1.51

Example 1.51

Example 1.51

Simplify: 12−3(9−12).12-3(9-12).

Solution

12−3(9−12)12-3(9-12)
Subtract in parentheses first.12−3(−3)12-3(-3)
Multiply.12−(−9)12-(-9)
Subtract.2121

Table

1.13

11. Example 1.52

Example 1.52

Example 1.52

Simplify: 8(−9)÷(−2)3.8(-9)\mathrm{÷}{(-2)}^{3}.

Solution

8(−9)÷(−2)38(-9)\mathrm{÷}{(-2)}^{3}
Exponents first.8(−9)÷(−8)8(-9)\mathrm{÷}(-8)
Multiply.−72÷(−8)-72\mathrm{÷}(-8)
Divide.99

Table

1.14

12. Example 1.53

Example 1.53

Example 1.53

Simplify: −30÷2+(−3)(−7).-30\mathrm{÷}2+(-3)(-7).

Solution

−30÷2+(−3)(−7)-30\mathrm{÷}2+(-3)(-7)
Multiply and divide left to right, so divide first.−15+(−3)(−7)-15+(-3)(-7)
Multiply.−15+21-15+21
Add.66

Table

1.15

13. Evaluate Variable Expressions with Integers

Evaluate Variable Expressions with Integers

Remember that to evaluate an expression means to substitute a number for the variable in the expression. Now we can use negative numbers as well as positive numbers.

14. Example 1.54

Example 1.54

Example 1.54

When n=−5,n=-5, evaluate: ⓐ n+1n+1 ⓑ −n+1.-n+1.

Solution

ⓐ

ⓑ

15. Example 1.55

Example 1.55

Example 1.55

Evaluate (x+y)2{(x+y)}^{2} when x=−18x=-18 and y=24.y=24.

Solution

16. Example 1.56

Example 1.56

Example 1.56

Evaluate 20−z20-z when ⓐ z=12z=12 and ⓑ z=−12.z=-12.

Solution

ⓐ

ⓑ

17. Example 1.57

Example 1.57

Example 1.57

Evaluate: 2x2+3x+82{x}^{2}+3x+8 when x=4.x=4.

Solution

Substitute 4 for x.4\,\mathrm{for}\,x. Use parentheses to show multiplication.

18. Translate Phrases to Expressions with Integers

Translate Phrases to Expressions with Integers

Our earlier work translating English to algebra also applies to phrases that include both positive and negative numbers.

19. Example 1.58

Example 1.58

Example 1.58

Translate and simplify: the sum of 8 and −12,-12, increased by 3.

Solution

the sum of 8 and −12,-12, increased by 3.
Translate.[8+(−12)]+3[8+(-12)]+3
Simplify. Be careful not to confuse the brackets with an absolute value sign.(−4)+3(-4)+3
Add.−1-1

Table

1.16

When we first introduced the operation symbols, we saw that the expression may be read in several ways. They are listed in the chart below.

a−ba-b
aa minus bb the difference of aa and bbbb subtracted from aabb less than aa

Be careful to get a and b in the right order!

20. Example 1.59

Example 1.59

Example 1.59

Translate and then simplify ⓐ the difference of 13 and −21-21 ⓑ subtract 24 from −19.-19.

Solution

ⓐ Translate. Simplify.the difference of 13 and −2113−(−21)34\begin{array}{c} \mathrm{the}\,\mathrm{difference}\,\mathrm{of}\,13\,\mathrm{and}\,-21 \\ 13-(-21) \\ 34 \\ \end{array}
ⓑ Translate. Remember, "subtract bb from aa means a−ba-b. Simplify.subtract 24 from −19−19−24−43\begin{array}{c} \mathrm{subtract}\,24\,\mathrm{from}\,-19 \\ -19-24 \\ -43 \\ \end{array}

Table

1.17

Once again, our prior work translating English to algebra transfers to phrases that include both multiplying and dividing integers. Remember that the key word for multiplication is “product” and for division is “quotient.”

21. Example 1.60

Example 1.60

Example 1.60

Translate to an algebraic expression and simplify if possible: the product of −2-2 and 14.

Solution

theproduct of −2 and 14\mathrm{the product}\,\mathrm{of}\,-2\,\mathrm{and}\,14
Translate.(−2)(14)(-2)(14)
Simplify.−28-28

Table

1.18

22. Example 1.61

Example 1.61

Example 1.61

Translate to an algebraic expression and simplify if possible: the quotient of −56-56 and −7.-7.

Solution

thequotient of −56 and −7\mathrm{the quotient}\,\mathrm{of}\,-56\,\mathrm{and}\,-7
Translate.−56÷(−7)-56\mathrm{÷}(-7)
Simplify.88

Table

1.19

23. Use Integers in Applications

Use Integers in Applications

We’ll outline a plan to solve applications. It’s hard to find something if we don’t know what we’re looking for or what to call it! So when we solve an application, we first need to determine what the problem is asking us to find. Then we’ll write a phrase that gives the information to find it. We’ll translate the phrase into an expression and then simplify the expression to get the answer. Finally, we summarize the answer in a sentence to make sure it makes sense.

24. Example 1.62

Example 1.62

Example 1.62

How to Apply a Strategy to Solve Applications with Integers

In the morning, the temperature in Urbana, Illinois was 11 degrees. By mid-afternoon, the temperature had dropped to −9-9 degrees. What was the difference of the morning and afternoon temperatures?

Apply a Strategy to Solve Applications with Integers.

  1. Step 1. Read the problem. Make sure all the words and ideas are understood
  2. Step 2. Identify what we are asked to find.
  3. Step 3. Write a phrase that gives the information to find it.
  4. Step 4. Translate the phrase to an expression.
  5. Step 5. Simplify the expression.
  6. Step 6. Answer the question with a complete sentence.

25. Example 1.63

Example 1.63

Example 1.63

The Mustangs football team received three penalties in the third quarter. Each penalty gave them a loss of fifteen yards. What is the number of yards lost?

Solution

Step 1. Read the problem. Make sure all the words and ideas are understood.
Step 2. Identify what we are asked to find.the number of yards lost
Step 3. Write a phrase that gives the information to find it.three times a 15-yard penalty
Step 4. Translate the phrase to an expression.3(−15)3(-15)
Step 5. Simplify the expression.−45-45
Step 6. Answer the question with a complete sentence.The team lost 45 yards.

Table

1.20

26. Section 1.4 Exercises

Section 1.4 Exercises

Section 1.4 Exercises

Multiply Integers

In the following exercises, multiply.

Divide Integers

In the following exercises, divide.

Simplify Expressions with Integers

In the following exercises, simplify each expression.

Evaluate Variable Expressions with Integers

In the following exercises, evaluate each expression.

Translate English Phrases to Algebraic Expressions

In the following exercises, translate to an algebraic expression and simplify if possible.

Use Integers in Applications

In the following exercises, solve.

Everyday Math

Writing Exercises

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ On a scale of 1–10, how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?

27. Practice 1

  1. Multiply: ⓐ −6⋅8-6\cdot{}8 ⓑ −4(−7)-4(-7) ⓒ 9(−7)9(-7) ⓓ 5⋅12.5\cdot{}12.
  1. Multiply: ⓐ −8⋅7-8\cdot{}7 ⓑ −6(−9)-6(-9) ⓒ 7(−4)7(-4) ⓓ 3⋅13.3\cdot{}13.
  1. Multiply: ⓐ −1⋅9-1\cdot{}9 ⓑ −1⋅(−17).-1\cdot(-17).
  1. Multiply: ⓐ −1⋅8-1\cdot{}8 ⓑ −1⋅(−16).-1\cdot(-16).

28. Practice 2

  1. Divide: ⓐ −42÷6-42\mathrm{÷}6 ⓑ −117÷(−3).-117\mathrm{÷}(-3).
  1. Divide: ⓐ −63÷7-63\mathrm{÷}7 ⓑ −115÷(−5).-115\mathrm{÷}(-5).
  1. Simplify: 8(−3)+5(−7)−4.8(-3)+5(-7)-4.
  1. Simplify: 9(−3)+7(−8)−1.9(-3)+7(-8)-1.

29. Practice 3

  1. Simplify: ⓐ (−3)4{(-3)}^{4} ⓑ −34.-{3}^{4}.
  1. Simplify: ⓐ (−7)2{(-7)}^{2} ⓑ −72.-{7}^{2}.
  1. When n=−8,n=-8, evaluate ⓐ n+2n+2 ⓑ −n+2.-n+2.
  1. When y=−9,y=-9, evaluate ⓐ y+8y+8 ⓑ −y+8.-y+8.

30. Practice 4

  1. Evaluate: 17−k17-k when ⓐ k=19k=19 and ⓑ k=−19.k=-19.
  1. Evaluate: −5−b-5-b when ⓐ b=14b=14 and ⓑ b=−14.b=-14.
  1. Translate and simplify the sum of 9 and −16,-16, increased by 4.
  1. Translate and simplify the sum of −8-8 and −12,-12, increased by 7.

31. Practice 5

  1. Translate and simplify ⓐ the difference of 14 and −23-23 ⓑ subtract 21 from −17.-17.
  1. Translate and simplify ⓐ the difference of 11 and −19-19 ⓑ subtract 18 from −11.-11.
  1. Translate to an algebraic expression and simplify if possible: the product of −5-5 and 12.
  1. Translate to an algebraic expression and simplify if possible: the product of 8 and −13.-13.

32. Practice 6

  1. Translate to an algebraic expression and simplify if possible: the quotient of −63-63 and −9.-9.
  1. Translate to an algebraic expression and simplify if possible: the quotient of −72-72 and −9.-9.
  1. In the morning, the temperature in Anchorage, Alaska was 15 degrees. By mid-afternoon the temperature had dropped to 30 degrees below zero. What was the difference in the morning and afternoon temperatures?
  1. The temperature in Denver was −6-6 degrees at lunchtime. By sunset the temperature had dropped to −15-15 degrees. What was the difference in the lunchtime and sunset temperatures?

33. Practice 8

  1. −1⋅6-1\cdot{}6
  1. −24÷6-24\mathrm{÷}6
  1. −180÷15-180\mathrm{÷}15
  1. 5(−6)+7(−2)−35(-6)+7(-2)-3

34. Practice 9

  1. −42-{4}^{2}
  1. 65÷(−5)+(−28)÷(−7)65\mathrm{÷}(-5)+(-28)\mathrm{÷}(-7)
  1. 9−2[3−8(−2)]9-2[3-8(-2)]
  1. y+(−14)y+(-14) when ⓐ y=−33y=-33 ⓑ y=30y=30

35. Practice 10

  1. 1. ⓐ a+3a+3 when a=−7a=-7
  1. ⓑ −a+3-a+3 when a=−7a=-7
  1. m+nm+n whenm=−15,n=7m=-15,n=7
  1. r+sr+s when r=−9,s=−7r=-9,s=-7
  1. −2x+17-2x+17 when
  1. ⓐ x=8x=8
  1. ⓑ x=−8x=-8

36. Practice 11

  1. 10−3m10-3m whenⓐ m=5m=5ⓑ m=−5m=-5
  1. 9a−2b−89a-2b-8 whena=−6 and b=−3a=-6\,\mathrm{and}\,b=-3
  1. the sum of 3 and −15,-15, increased by 7
  1. the difference of 10 and −18-18

37. Practice 12

  1. the difference of −5-5 and −30-30
  1. the product of −3and15\mathrm{-3 and 15}
  1. the quotient of −60-60 and −20-20
  1. the quotient of −6-6 and the sum of a and b

38. Practice 13

  1. the product of −10-10 and the difference of p and qp\,\mathrm{and}\,q
  1. Temperature On January 15,15, the high temperature in Anaheim, California, was 84∘.84^{\circ}. That same day, the high temperature in Embarrass, Minnesota was −12∘.-12^{\circ}. What was the difference between the temperature in Anaheim and the temperature in Embarrass?
  1. Checking Account Mayra has 124inhercheckingaccount.Shewritesacheckfor124 in her checking account. She writes a check for 152. What is the new balance in her checking account?
  1. Checking Account Diontre has a balance of −$38-\$38 in his checking account. He deposits $225 to the account. What is the new balance?

39. Practice 7

  1. The Bears played poorly and had seven penalties in the game. Each penalty resulted in a loss of 15 yards. What is the number of yards lost due to penalties?
  1. Bill uses the ATM on campus because it is convenient. However, each time he uses it he is charged a $2 fee. Last month he used the ATM eight times. How much was his total fee for using the ATM?
  1. −4⋅8-4\cdot{}8
  1. 9(−7)9(-7)

40. Practice 14

  1. Stock market Javier owns 300 shares of stock in one company. On Tuesday, the stock price dropped $12 per share. What was the total effect on Javier’s portfolio?
  1. In your own words, state the rules for multiplying integers.
  1. Why is −24≠(−2)4?-{2}^{4}\ne{(-2)}^{4}?

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