Elementary Algebra 2e · free preview

2.6 Solve a Formula for a Specific Variable

Learning objectives: Use the Distance, Rate, and Time formula; Solve a formula for a specific variable

1. Learning objectives

Learning objectives

Learning objectives

  • Use the Distance, Rate, and Time formula
  • Solve a formula for a specific variable

2. Use the Distance, Rate, and Time Formula

Use the Distance, Rate, and Time Formula

One formula you will use often in algebra and in everyday life is the formula for distance traveled by an object moving at a constant rate. Rate is an equivalent word for “speed.” The basic idea of rate may already familiar to you. Do you know what distance you travel if you drive at a steady rate of 60 miles per hour for 2 hours? (This might happen if you use your car’s cruise control while driving on the highway.) If you said 120 miles, you already know how to use this formula!

For an object moving at a uniform (constant) rate, the distance traveled, the elapsed time, and the rate are related by the formula:

d=rtwhered=distancer=ratet=time\begin{array}{lcccccrll} d=rt & & & \mathrm{where} & & & d & = & \mathrm{distance} \\ & & & & & & r & = & \mathrm{rate} \\ & & & & & & t & = & \mathrm{time} \\ \end{array}

We will use the Strategy for Solving Applications that we used earlier in this chapter. When our problem requires a formula, we change Step 4. In place of writing a sentence, we write the appropriate formula. We write the revised steps here for reference.

Solve an application (with a formula).

  1. Step 1. Read the problem. Make sure all the words and ideas are understood.
  2. Step 2. Identify what we are looking for.
  3. Step 3. Name what we are looking for. Choose a variable to represent that quantity.
  4. Step 4. Translate into an equation. Write the appropriate formula for the situation. Substitute in the given information.
  5. Step 5. Solve the equation using good algebra techniques.
  6. Step 6. Check the answer in the problem and make sure it makes sense.
  7. Step 7. Answer the question with a complete sentence.

You may want to create a mini-chart to summarize the information in the problem. See the chart in this first example.

3. Example 2.58

Example 2.58

Example 2.58

Jamal rides his bike at a uniform rate of 12 miles per hour for 3123\frac{1}{2} hours. What distance has he traveled?

Solution

4. Example 2.59

Example 2.59

Example 2.59

Rey is planning to drive from his house in San Diego to visit his grandmother in Sacramento, a distance of 520 miles. If he can drive at a steady rate of 65 miles per hour, how many hours will the trip take?

Solution

5. Solve a Formula for a Specific Variable

Solve a Formula for a Specific Variable

You are probably familiar with some geometry formulas. A formula is a mathematical description of the relationship between variables. Formulas are also used in the sciences, such as chemistry, physics, and biology. In medicine they are used for calculations for dispensing medicine or determining body mass index. Spreadsheet programs rely on formulas to make calculations. It is important to be familiar with formulas and be able to manipulate them easily.

In Example 2.58 and Example 2.59, we used the formula d=rtd=rt. This formula gives the value of dd, distance, when you substitute in the values of r and tr\,\mathrm{and}\,t, the rate and time. But in Example 2.59, we had to find the value of tt. We substituted in values of d and rd\,\mathrm{and}\,r and then used algebra to solve for tt. If you had to do this often, you might wonder why there is not a formula that gives the value of tt when you substitute in the values of d and rd\,\mathrm{and}\,r. We can make a formula like this by solving the formula d=rtd=rt for tt.

To solve a formula for a specific variable means to isolate that variable on one side of the equals sign with a coefficient of 1. All other variables and constants are on the other side of the equals sign. To see how to solve a formula for a specific variable, we will start with the distance, rate and time formula.

6. Example 2.60

Example 2.60

Example 2.60

Solve the formula d=rtd=rt for tt:

  1. ⓐ when d=520d=520 and r=65r=65
  2. ⓑ in general

Solution

We will write the solutions side-by-side to demonstrate that solving a formula in general uses the same steps as when we have numbers to substitute.

ⓐ when d=520d=520 and r=65r=65ⓑ in general
Write the formula. d=rt\,d=rtWrite the formula.d=rtd=rt
Substitute.520=65t520=65t
Divide, to isolate tt.52065=65t65\frac{520}{65}=\frac{65t}{65}Divide, to isolate tt.dr=rtr\frac{d}{r}=\frac{rt}{r}
Simplify. 8=t\,8=tSimplify.dr=t\frac{d}{r}=t

We say the formula t=drt=\frac{d}{r} is solved for tt.

7. Example 2.61

Example 2.61

Example 2.61

Solve the formula A=12bhA=\frac{1}{2}bh for hh:

ⓐ when A=90A=90 and b=15b=15 ⓑ in general

Solution

We can now find the height of a triangle, if we know the area and the base, by using the formula h=2Abh=\frac{2A}{b}.

The formula I=PrtI=Prt is used to calculate simple interest, I, for a principal, P, invested at rate, r, for t years.

8. Example 2.62

Example 2.62

Example 2.62

Solve the formula I=PrtI=Prt to find the principal, PP:

ⓐ when I=I=5,600,r=4\%,t=7\,\mathrm{years}\,$ ⓑ in general

Solution

Later in this class, and in future algebra classes, you’ll encounter equations that relate two variables, usually x and y. You might be given an equation that is solved for y and need to solve it for x, or vice versa. In the following example, we’re given an equation with both x and y on the same side and we’ll solve it for y.

9. Example 2.63

Example 2.63

Example 2.63

Solve the formula 3x+2y=183x+2y=18 for y:

ⓐ when x=4x=4 ⓑ in general

Solution

In Examples 1.60 through 1.64 we used the numbers in part ⓐ as a guide to solving in general in part ⓑ. Now we will solve a formula in general without using numbers as a guide.

10. Example 2.64

Example 2.64

Example 2.64

Solve the formula P=a+b+cP=a+b+c for aa.

Solution

11. Example 2.65

Example 2.65

Example 2.65

Solve the formula 6x+5y=136x+5y=13 for y.

Solution

The fraction is simplified. We cannot divide 13−6x13-6x by 5.

12. Section 2.6 Exercises

Section 2.6 Exercises

Section 2.6 Exercises

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Solve a Formula for a Specific Variable

In the following exercises, use the formula d=rtd=rt.

In the following exercises, use the formula A=12bhA=\frac{1}{2}bh.

In the following exercises, use the formula I = Prt.

In the following exercises, solve.

Everyday Math

Writing Exercises

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ What does this checklist tell you about your mastery of this section? What steps will you take to improve?

13. Practice 1

  1. Lindsay drove for 5125\frac{1}{2} hours at 60 miles per hour. How much distance did she travel?
  1. Trinh walked for 2132\frac{1}{3} hours at 3 miles per hour. How far did she walk?
  1. Lee wants to drive from Phoenix to his brother’s apartment in San Francisco, a distance of 770 miles. If he drives at a steady rate of 70 miles per hour, how many hours will the trip take?

14. Practice 2

  1. Yesenia is 168 miles from Chicago. If she needs to be in Chicago in 3 hours, at what rate does she need to drive?
  1. Solve the formula d=rtd=rt for rr:

ⓐ when d=180 and t=4d=180\,\mathrm{and}\,t=4 ⓑ in general

  1. Solve the formula d=rtd=rt for rr:

ⓐ when d=780 and t=12d=780\,\mathrm{and}\,t=12 ⓑ in general

15. Practice 3

  1. Use the formula A=12bhA=\frac{1}{2}bh to solve for hh:

ⓐ when A=170A=170 and b=17b=17 ⓑ in general

  1. Use the formula A=12bhA=\frac{1}{2}bh to solve for bb:

ⓐ when A=62A=62 and h=31h=31 ⓑ in general

  1. Use the formula I=PrtI=Prt to find the principal, PP:

ⓐ when I=I=2,160,r=6\%,t=3\,\mathrm{years}\,$ ⓑ in general

16. Practice 4

  1. Use the formula I=PrtI=Prt to find the principal,PP:

ⓐ when I=I=5,400,r=12\%,t=5\,\mathrm{years}\,$ ⓑ in general

  1. Solve the formula 3x+4y=103x+4y=10 for y:

ⓐ when x=143x=\frac{14}{3} ⓑ in general

  1. Solve the formula 5x+2y=185x+2y=18 for y:

ⓐ when x=4x=4 ⓑ in general

17. Practice 5

  1. Solve the formula P=a+b+cP=a+b+c for b.
  1. Solve the formula P=a+b+cP=a+b+c for c.
  1. Solve the formula 4x+7y=94x+7y=9 for y.

18. Practice 6

  1. Solve the formula 5x+8y=15x+8y=1 for y.
  1. Socorro drove for 4564\frac{5}{6} hours at 60 miles per hour. How much distance did she travel?
  1. Francie rode her bike for 2122\frac{1}{2} hours at 12 miles per hour. How far did she ride?

19. Practice 7

  1. Megan is taking the bus from New York City to Montreal. The distance is 380 miles and the bus travels at a steady rate of 76 miles per hour. How long will the bus ride be?
  1. Kareem wants to ride his bike from St. Louis to Champaign, Illinois. The distance is 180 miles. If he rides at a steady rate of 16 miles per hour, how many hours will the trip take?
  1. Alejandra is driving to Cincinnati, 450 miles away. If she wants to be there in 6 hours, at what rate does she need to drive?

20. Practice 8

  1. Philip got a ride with a friend from Denver to Las Vegas, a distance of 750 miles. If the trip took 10 hours, how fast was the friend driving?
  1. Solve for tt ⓐ when d=240 and r=60d=240\,\mathrm{and}\,r=60 ⓑ in general
  1. Solve for ttⓐ when d=175 and r=50d=175\,\mathrm{and}\,r=50ⓑ in general

21. Practice 9

  1. Solve for rrⓐ when d=420 and t=6d=420\,\mathrm{and}\,t=6ⓑ in general
  1. Solve for rrⓐ when d=180 and t=4.5d=180\,\mathrm{and}\,t=4.5ⓑ in general
  1. Solve for hhⓐ when A=176 and b=22A=176\,\mathrm{and}\,b=22ⓑ in general

22. Practice 10

  1. Solve for bbⓐ when A=65 and h=13A=65\,\mathrm{and}\,h=13ⓑ in general
  1. Solve for the principal, P forⓐ I=I=3,950,r=6\%,$t=5 years t=5\,\mathrm{years}\,ⓑ in general
  1. Solve for the time, t forⓐ I=I=624,P=6,000,6,000,r=5.2%r=5.2\%ⓑ in general

23. Practice 11

  1. Solve the formula 5x+2y=105x+2y=10 for yⓐ when x=4x=4ⓑ in general
  1. Solve the formula 4x+y=54x+y=5 for yⓐ when x=−3x=-3ⓑ in general
  1. Solve a+b=90a+b=90 for aa.

24. Practice 12

  1. Solve 180=a+b+c180=a+b+c for cc.
  1. Solve the formula 9x+y=139x+y=13 for y.
  1. Solve the formula −5x+y=−1-5x+y=-1 for y.

25. Practice 13

  1. Solve the formula 3x+2y=113x+2y=11 for y.
  1. Solve the formula x−y=−3x-y=-3 for y.
  1. Solve the formula P=2L+2WP=2L+2W for WW.

26. Practice 14

  1. Solve the formula C=πdC=\pi{}d for π\pi.
  1. Solve the formula V=LWHV=LWH for HH.
  1. Converting temperature Yon was visiting the United States and he saw that the temperature in Seattle one day was 50o50^{o} Fahrenheit. Solve for C in the formula F=95C+32F=\frac{9}{5}C+32 to find the Celsius temperature.

27. Practice 15

  1. Solve the equation 5x−2y=105x-2y=10 for xxⓐ when y=10y=10ⓑ in generalⓒ Which solution is easier for you, ⓐ or ⓑ ? Why?

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