Elementary Algebra 2e · free preview

6.5 Divide Monomials

Learning objectives: Simplify expressions using the Quotient Property for Exponents; Simplify expressions with zero exponents; Simplify expressions using the quotient to a Power Property; Simplify expressions by applying several properties; Divide monomials

1. Learning objectives

Learning objectives

Learning objectives

  • Simplify expressions using the Quotient Property for Exponents
  • Simplify expressions with zero exponents
  • Simplify expressions using the quotient to a Power Property
  • Simplify expressions by applying several properties
  • Divide monomials

2. Simplify Expressions Using the Quotient Property for Exponents

Simplify Expressions Using the Quotient Property for Exponents

Earlier in this chapter, we developed the properties of exponents for multiplication. We summarize these properties below.

If a and ba\,\mathrm{and}\,b are real numbers, and m and nm\,\mathrm{and}\,n are whole numbers, then

Product Propertyam⋅an=am+n{a}^{m}\cdot{a}^{n}={a}^{m+n}
Power Property(am)n=am⋅n{({a}^{m})}^{n}={a}^{m\cdot{}n}
Product to a Power(ab)m=ambm{(ab)}^{m}={a}^{m}{b}^{m}

Now we will look at the exponent properties for division. A quick memory refresher may help before we get started. You have learned to simplify fractions by dividing out common factors from the numerator and denominator using the Equivalent Fractions Property. This property will also help you work with algebraic fractions—which are also quotients.

If a,b, and ca,b,\,\mathrm{and}\,c are whole numbers where b≠0,c≠0b\ne{}0,c\ne{}0,

then ab=a⋅cb⋅c and a⋅cb⋅c=ab\mathrm{then}\,\frac{a}{b}=\frac{a\cdot{}c}{b\cdot{}c}\,\mathrm{and}\,\frac{a\cdot{}c}{b\cdot{}c}=\frac{a}{b}

As before, we’ll try to discover a property by looking at some examples.

Considerx5x2\frac{{x}^{5}}{{x}^{2}}andx2x3\frac{{x}^{2}}{{x}^{3}}
What do they mean?x⋅x⋅x⋅x⋅xx⋅x\frac{x\cdot{}x\cdot{}x\cdot{}x\cdot{}x}{x\cdot{}x}x⋅xx⋅x⋅x\frac{x\cdot{}x}{x\cdot{}x\cdot{}x}
Use the Equivalent Fractions Property.x⋅x⋅x⋅x⋅xx⋅x\frac{x\cdot{}x\cdot{}x\cdot{}x\cdot{}x}{x\cdot{}x}x⋅x⋅1x⋅x⋅x\frac{x\cdot{}x\cdot{}1}{x\cdot{}x\cdot{}x}
Simplify.x3{x}^{3}1x\frac{1}{x}

Notice, in each case the bases were the same and we subtracted exponents.

When the larger exponent was in the numerator, we were left with factors in the numerator.

When the larger exponent was in the denominator, we were left with factors in the denominator—notice the numerator of 1.

We write:

x5x2x2x3x5−21x3−2x31x\begin{array}{cccc} \frac{{x}^{5}}{{x}^{2}} & & & \frac{{x}^{2}}{{x}^{3}} \\ {x}^{5-2} & & & \frac{1}{{x}^{3-2}} \\ {x}^{3} & & & \frac{1}{x} \\ \end{array}

This leads to the Quotient Property for Exponents.

If aa is a real number, a≠0a\ne{}0, and m and nm\,\mathrm{and}\,n are whole numbers, then

aman=am−n,m>n and aman=1an−m,n>m\frac{{a}^{m}}{{a}^{n}}={a}^{m-n},m>n\,\mathrm{and}\,\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}},n>m

A couple of examples with numbers may help to verify this property.

3432=34−2 5253=153−2819=32 25125=1519=9✓ 15=15✓\begin{array}{rllccrll} \frac{{3}^{4}}{{3}^{2}} & = & {3}^{4-2} & & & \,\frac{{5}^{2}}{{5}^{3}} & = & \frac{1}{{5}^{3-2}} \\ \frac{81}{9} & = & {3}^{2} & & & \,\frac{25}{125} & = & \frac{1}{{5}^{1}} \\ 9 & = & 9\mathrm{✓} & & & \,\frac{1}{5} & = & \frac{1}{5}\mathrm{✓} \\ \end{array}

3. Example 6.59

Example 6.59

Example 6.59

Simplify: ⓐ x9x7\frac{{x}^{9}}{{x}^{7}} ⓑ 31032.\frac{{3}^{10}}{{3}^{2}}.

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.

  1. ⓐ Since 9 > 7, there are more factors of x in the numerator. Use the Quotient Property, aman=am−n\frac{{a}^{m}}{{a}^{n}}={a}^{m-n}. Simplify.
  1. ⓑ Since 10 > 2, there are more factors of x in the numerator. Use the Quotient Property, aman=am−n\frac{{a}^{m}}{{a}^{n}}={a}^{m-n}. Simplify. Notice that when the larger exponent is in the numerator, we are left with factors in the numerator.

4. Example 6.60

Example 6.60

Example 6.60

Simplify: ⓐ b8b12\frac{{b}^{8}}{{b}^{12}} ⓑ 7375.\frac{{7}^{3}}{{7}^{5}}.

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.

  1. ⓐ Since 12 > 8, there are more factors of b in the denominator. Use the Quotient Property, aman=1an−m\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}}. Simplify.
  1. ⓑ Since 5 > 3, there are more factors of 3 in the denominator. Use the Quotient Property, aman=1an−m\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}}. Simplify. Simplify. Notice that when the larger exponent is in the denominator, we are left with factors in the denominator.

Notice the difference in the two previous examples:

  • If we start with more factors in the numerator, we will end up with factors in the numerator.
  • If we start with more factors in the denominator, we will end up with factors in the denominator.

The first step in simplifying an expression using the Quotient Property for Exponents is to determine whether the exponent is larger in the numerator or the denominator.

5. Example 6.61

Example 6.61

Example 6.61

Simplify: ⓐ a5a9\frac{{a}^{5}}{{a}^{9}} ⓑ x11x7.\frac{{x}^{11}}{{x}^{7}}.

Solution

  1. ⓐ Is the exponent of aa larger in the numerator or denominator? Since 9 > 5, there are more a′sa's in the denominator and so we will end up with factors in the denominator. Use the Quotient Property, aman=1an−m\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}}. Simplify.
  1. ⓑ Notice there are more factors of xx in the numerator, since 11 > 7. So we will end up with factors in the numerator. Use the Quotient Property, aman=1an−m\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}}. Simplify.

6. Simplify Expressions with an Exponent of Zero

Simplify Expressions with an Exponent of Zero

A special case of the Quotient Property is when the exponents of the numerator and denominator are equal, such as an expression like amam\frac{{a}^{m}}{{a}^{m}}. From your earlier work with fractions, you know that:

22=1 1717=1 −43−43=1\frac{2}{2}=1\,\frac{17}{17}=1\,\frac{-43}{-43}=1

In words, a number divided by itself is 1. So, xx=1\frac{x}{x}=1, for any x (x≠0)x\,(x\ne{}0), since any number divided by itself is 1.

The Quotient Property for Exponents shows us how to simplify aman\frac{{a}^{m}}{{a}^{n}} when m>nm>n and when n<mn<m by subtracting exponents. What if m=nm=n?

Consider 88\frac{8}{8}, which we know is 1.

88=1\begin{array}{c} \frac{8}{8}=1 \\ \end{array}
Write 88 as 23{2}^{3}.2323=1\begin{array}{c} \frac{{2}^{3}}{{2}^{3}}=1 \\ \end{array}
Subtract exponents.23−3=1\begin{array}{c} {2}^{3-3}=1 \\ \end{array}
Simplify.20=1\begin{array}{c} {2}^{0}=1 \\ \end{array}

Now we will simplify amam\frac{{a}^{m}}{{a}^{m}} in two ways to lead us to the definition of the zero exponent. In general, for a≠0a\ne{}0:

We see amam\frac{{a}^{m}}{{a}^{m}} simplifies to a0{a}^{0} and to 1. So a0=1{a}^{0}=1.

If aa is a non-zero number, then a0=1{a}^{0}=1.

Any nonzero number raised to the zero power is 1.

In this text, we assume any variable that we raise to the zero power is not zero.

7. Example 6.62

Example 6.62

Example 6.62

Simplify: ⓐ 90{9}^{0} ⓑ n0.{n}^{0}.

Solution

The definition says any non-zero number raised to the zero power is 1.

ⓐ Use the definition of the zero exponent.901\begin{array}{c} {9}^{0} \\ 1 \\ \end{array}
ⓑ Use the definition of the zero exponent.n01\begin{array}{c} {n}^{0} \\ 1 \\ \end{array}

Now that we have defined the zero exponent, we can expand all the Properties of Exponents to include whole number exponents.

What about raising an expression to the zero power? Let’s look at (2x)0{(2x)}^{0}. We can use the product to a power rule to rewrite this expression.

(2x)0{(2x)}^{0}
Use the product to a power rule.20x0{2}^{0}{x}^{0}
Use the zero exponent property.1⋅11\cdot{}1
Simplify.11

Table

6.1

This tells us that any nonzero expression raised to the zero power is one.

8. Example 6.63

Example 6.63

Example 6.63

Simplify: ⓐ (5b)0{(5b)}^{0} ⓑ (−4a2b)0.{(-4{a}^{2}b)}^{0}.

Solution

ⓐ(5b)0{(5b)}^{0}
Use the definition of the zero exponent.11
ⓑ(−4a2b)0{(-4{a}^{2}b)}^{0}
Use the definition of the zero exponent.11

9. Simplify Expressions Using the Quotient to a Power Property

Simplify Expressions Using the Quotient to a Power Property

Now we will look at an example that will lead us to the Quotient to a Power Property.

(xy)3{(\frac{x}{y})}^{3}
This means:xy⋅xy⋅xy\frac{x}{y}\cdot\frac{x}{y}\cdot\frac{x}{y}
Multiply the fractions.x⋅x⋅xy⋅y⋅y\frac{x\cdot{}x\cdot{}x}{y\cdot{}y\cdot{}y}
Write with exponents.x3y3\frac{{x}^{3}}{{y}^{3}}

Notice that the exponent applies to both the numerator and the denominator.

We write:(xy)3{(\frac{x}{y})}^{3}
x3y3\frac{{x}^{3}}{{y}^{3}}

This leads to the Quotient to a Power Property for Exponents.

If aa and bb are real numbers, b≠0b\ne{}0, and mm is a counting number, then

(ab)m=ambm{(\frac{a}{b})}^{m}=\frac{{a}^{m}}{{b}^{m}}

To raise a fraction to a power, raise the numerator and denominator to that power.

An example with numbers may help you understand this property:

(23)3=233323⋅23⋅23=827827=827✓\begin{array}{rll} {(\frac{2}{3})}^{3} & = & \frac{{2}^{3}}{{3}^{3}} \\ \frac{2}{3}\cdot\frac{2}{3}\cdot\frac{2}{3} & = & \frac{8}{27} \\ \frac{8}{27} & = & \frac{8}{27}\mathrm{✓} \\ \end{array}

10. Example 6.64

Example 6.64

Example 6.64

Simplify: ⓐ (37)2{(\frac{3}{7})}^{2} ⓑ (b3)4{(\frac{b}{3})}^{4} ⓒ (kj)3.{(\frac{k}{j})}^{3}.

Solution

ⓐ

ⓑ

ⓒ

11. Simplify Expressions by Applying Several Properties

Simplify Expressions by Applying Several Properties

We’ll now summarize all the properties of exponents so they are all together to refer to as we simplify expressions using several properties. Notice that they are now defined for whole number exponents.

If a and ba\,\mathrm{and}\,b are real numbers, and m and nm\,\mathrm{and}\,n are whole numbers, then

Product Propertyam⋅an=am+n{a}^{m}\cdot{a}^{n}={a}^{m+n}
Power Property(am)n=am⋅n{({a}^{m})}^{n}={a}^{m\cdot{}n}
Product to a Power(ab)m=ambm{(ab)}^{m}={a}^{m}{b}^{m}
Quotient Propertyaman=am−n,a≠0,m>naman=1an−m,a≠0,n>m\begin{array}{rll} \frac{{a}^{m}}{{a}^{n}} & = & {a}^{m-n},a\ne{}0,m>n \\ \frac{{a}^{m}}{{a}^{n}} & = & \frac{1}{{a}^{n-m}},a\ne{}0,n>m \\ \end{array}
Zero Exponent Definitionao=1,a≠0{a}^{o}=1,a\ne{}0
Quotient to a Power Property(ab)m=ambm,b≠0{(\frac{a}{b})}^{m}=\frac{{a}^{m}}{{b}^{m}},b\ne{}0

12. Example 6.65

Example 6.65

Example 6.65

Simplify: (y4)2y6.\frac{{({y}^{4})}^{2}}{{y}^{6}}.

Solution

(y4)2y6\frac{{({y}^{4})}^{2}}{{y}^{6}}
Multiply the exponents in the numerator.y8y6\frac{{y}^{8}}{{y}^{6}}
Subtract the exponents.y2{y}^{2}

13. Example 6.66

Example 6.66

Example 6.66

Simplify: b12(b2)6.\frac{{b}^{12}}{{({b}^{2})}^{6}}.

Solution

b12(b2)6\frac{{b}^{12}}{{({b}^{2})}^{6}}
Multiply the exponents in the numerator.b12b12\frac{{b}^{12}}{{b}^{12}}
Subtract the exponents.b0{b}^{0}
Simplify.11

14. Example 6.67

Example 6.67

Example 6.67

Simplify: (y9y4)2.{(\frac{{y}^{9}}{{y}^{4}})}^{2}.

Solution

(y9y4)2{(\frac{{y}^{9}}{{y}^{4}})}^{2}
Remember parentheses come before exponents. Notice the bases are the same, so we can simplify inside the parentheses. Subtract the exponents.(y5)2{({y}^{5})}^{2}
Multiply the exponents.y10{y}^{10}

15. Example 6.68

Example 6.68

Example 6.68

Simplify: (j2k3)4.{(\frac{{j}^{2}}{{k}^{3}})}^{4}.

Solution

Here we cannot simplify inside the parentheses first, since the bases are not the same.

(j2k3)4{(\frac{{j}^{2}}{{k}^{3}})}^{4}
Raise the numerator and denominator to the fourth power using the Quotient to a Power Property, (ab)m=ambm{(\frac{a}{b})}^{m}=\frac{{a}^{m}}{{b}^{m}}.
Use the Power Property and simplify.j8k12\frac{{j}^{8}}{{k}^{12}}

16. Example 6.69

Example 6.69

Example 6.69

Simplify: (2m25n)4.{(\frac{2{m}^{2}}{5n})}^{4}.

Solution

(2m25n)4{(\frac{2{m}^{2}}{5n})}^{4}
Raise the numberator and denominator to the fourth power, using the Quotient to a Power Property, (ab)m=ambm{(\frac{a}{b})}^{m}=\frac{{a}^{m}}{{b}^{m}}.(2m2)4(5n)4\frac{{(2{m}^{2})}^{4}}{{(5n)}^{4}}
Raise each factor to the fourth power.(2m2)4(5n)4\frac{{(2{m}^{2})}^{4}}{{(5n)}^{4}}
Use the Power Property and simplify.16m8625n4\frac{16{m}^{8}}{625{n}^{4}}

17. Example 6.70

Example 6.70

Example 6.70

Simplify: (x3)4(x2)5(x6)5.\frac{{({x}^{3})}^{4}{({x}^{2})}^{5}}{{({x}^{6})}^{5}}.

Solution

(x3)4(x2)5(x6)5\frac{{({x}^{3})}^{4}{({x}^{2})}^{5}}{{({x}^{6})}^{5}}
Use the Power Property, (am)n=am⋅n{({a}^{m})}^{n}={a}^{m\cdot{}n}.(x12)(x10)(x30)\frac{({x}^{12})({x}^{10})}{({x}^{30})}
Add the exponents in the numerator.x22x30\frac{{x}^{22}}{{x}^{30}}
Use the Quotient Property, aman=1an−m\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}}.1x8\frac{1}{{x}^{8}}

18. Example 6.71

Example 6.71

Example 6.71

Simplify: (10p3)2(5p)3(2p5)4.\frac{{(10{p}^{3})}^{2}}{{(5p)}^{3}{(2{p}^{5})}^{4}}.

Solution

(10p3)2(5p)3(2p5)4\frac{{(10{p}^{3})}^{2}}{{(5p)}^{3}{(2{p}^{5})}^{4}}
Use the Product to a Power Property, (ab)m=ambm{(ab)}^{m}={a}^{m}{b}^{m}.(10)2(p3)2(5)3(p)3(2)4(p5)4\frac{{(10)}^{2}{({p}^{3})}^{2}}{{(5)}^{3}{(p)}^{3}{(2)}^{4}{({p}^{5})}^{4}}
Use the Power Property, (am)n=am⋅n{({a}^{m})}^{n}={a}^{m\cdot{}n}.100p6125p3⋅16p20\frac{100{p}^{6}}{125{p}^{3}\cdot{}16{p}^{20}}
Add the exponents in the denominator.100p6125⋅16p23\frac{100{p}^{6}}{125\cdot{}16{p}^{23}}
Use the Quotient Property, aman=1an−m\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}}.100125⋅16p17\frac{100}{125\cdot{}16{p}^{17}}
Simplify.120p17\frac{1}{20{p}^{17}}

19. Divide Monomials

Divide Monomials

You have now been introduced to all the properties of exponents and used them to simplify expressions. Next, you’ll see how to use these properties to divide monomials. Later, you’ll use them to divide polynomials.

20. Example 6.72

Example 6.72

Example 6.72

Find the quotient: 56x7÷8x3.56{x}^{7}\mathrm{÷}8{x}^{3}.

Solution

56x7÷8x356{x}^{7}\mathrm{÷}8{x}^{3}
Rewrite as a fraction.56x78x3\frac{56{x}^{7}}{8{x}^{3}}
Use fraction multiplication.568⋅x7x3\frac{56}{8}\cdot\frac{{x}^{7}}{{x}^{3}}
Simplify and use the Quotient Property.7x47{x}^{4}

21. Example 6.73

Example 6.73

Example 6.73

Find the quotient: 45a2b3−5ab5.\frac{45{a}^{2}{b}^{3}}{-5a{b}^{5}}.

Solution

45a2b3−5ab5\frac{45{a}^{2}{b}^{3}}{-5a{b}^{5}}
Use fraction multiplication.45−5⋅a2a⋅b3b5\frac{45}{-5}\cdot\frac{{a}^{2}}{a}\cdot\frac{{b}^{3}}{{b}^{5}}
Simplify and use the Quotient Property.−9⋅a⋅1b2-9\cdot{}a\cdot\frac{1}{{b}^{2}}
Multiply.−9ab2-\frac{9a}{{b}^{2}}

22. Example 6.74

Example 6.74

Example 6.74

Find the quotient: 24a5b348ab4.\frac{24{a}^{5}{b}^{3}}{48a{b}^{4}}.

Solution

24a5b348ab4\frac{24{a}^{5}{b}^{3}}{48a{b}^{4}}
Use fraction multiplication.2448⋅a5a⋅b3b4\frac{24}{48}\cdot\frac{{a}^{5}}{a}\cdot\frac{{b}^{3}}{{b}^{4}}
Simplify and use the Quotient Property.12⋅a4⋅1b\frac{1}{2}\cdot{a}^{4}\cdot\frac{1}{b}
Multiply.a42b\frac{{a}^{4}}{2b}

Once you become familiar with the process and have practiced it step by step several times, you may be able to simplify a fraction in one step.

23. Example 6.75

Example 6.75

Example 6.75

Find the quotient: 14x7y1221x11y6.\frac{14{x}^{7}{y}^{12}}{21{x}^{11}{y}^{6}}.

Solution

Be very careful to simplify 1421\frac{14}{21} by dividing out a common factor, and to simplify the variables by subtracting their exponents.

14x7y1221x11y6\frac{14{x}^{7}{y}^{12}}{21{x}^{11}{y}^{6}}
Simplify and use the Quotient Property.2y63x4\frac{2{y}^{6}}{3{x}^{4}}

In all examples so far, there was no work to do in the numerator or denominator before simplifying the fraction. In the next example, we’ll first find the product of two monomials in the numerator before we simplify the fraction. This follows the order of operations. Remember, a fraction bar is a grouping symbol.

24. Example 6.76

Example 6.76

Example 6.76

Find the quotient: (6x2y3)(5x3y2)(3x4y5).\frac{(6{x}^{2}{y}^{3})(5{x}^{3}{y}^{2})}{(3{x}^{4}{y}^{5})}.

Solution

(6x2y3)(5x3y2)(3x4y5)\frac{(6{x}^{2}{y}^{3})(5{x}^{3}{y}^{2})}{(3{x}^{4}{y}^{5})}
Simplify the numerator.30x5y53x4y5\frac{30{x}^{5}{y}^{5}}{3{x}^{4}{y}^{5}}
Simplify.10x10x

25. Section 6.5 Exercises

Section 6.5 Exercises

Section 6.5 Exercises

Simplify Expressions Using the Quotient Property for Exponents

In the following exercises, simplify.

Simplify Expressions with Zero Exponents

In the following exercises, simplify.

Simplify Expressions Using the Quotient to a Power Property

In the following exercises, simplify.

Simplify Expressions by Applying Several Properties

In the following exercises, simplify.

Divide Monomials

In the following exercises, divide the monomials.

Mixed Practice

Everyday Math

Writing Exercises

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ On a scale of 1-10, how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?

26. Practice 1

  1. Simplify: ⓐ x15x10\frac{{x}^{15}}{{x}^{10}} ⓑ 61465.\frac{{6}^{14}}{{6}^{5}}.
  1. Simplify: ⓐ y43y37\frac{{y}^{43}}{{y}^{37}} ⓑ 1015107.\frac{{10}^{15}}{{10}^{7}}.
  1. Simplify: ⓐ x18x22\frac{{x}^{18}}{{x}^{22}} ⓑ 12151230.\frac{{12}^{15}}{{12}^{30}}.
  1. Simplify: ⓐ m7m15\frac{{m}^{7}}{{m}^{15}} ⓑ 98919.\frac{{9}^{8}}{{9}^{19}}.
  1. Simplify: ⓐ b19b11\frac{{b}^{19}}{{b}^{11}} ⓑ z5z11.\frac{{z}^{5}}{{z}^{11}}.

27. Practice 2

  1. Simplify: ⓐ p9p17\frac{{p}^{9}}{{p}^{17}} ⓑ w13w9.\frac{{w}^{13}}{{w}^{9}}.
  1. Simplify: ⓐ 150{15}^{0} ⓑ m0.{m}^{0}.
  1. Simplify: ⓐ k0{k}^{0} ⓑ 290.{29}^{0}.
  1. Simplify: ⓐ (11z)0{(11z)}^{0} ⓑ (−11pq3)0.{(-11p{q}^{3})}^{0}.
  1. Simplify: ⓐ (−6d)0{(-6d)}^{0} ⓑ (−8m2n3)0.{(-8{m}^{2}{n}^{3})}^{0}.

28. Practice 3

  1. Simplify: ⓐ (58)2{(\frac{5}{8})}^{2} ⓑ (p10)4{(\frac{p}{10})}^{4} ⓒ (mn)7.{(\frac{m}{n})}^{7}.
  1. Simplify: ⓐ (13)3{(\frac{1}{3})}^{3} ⓑ (−2q)3{(\frac{-2}{q})}^{3} ⓒ (wx)4.{(\frac{w}{x})}^{4}.
  1. Simplify: (m5)4m7.\frac{{({m}^{5})}^{4}}{{m}^{7}}.
  1. Simplify: (k2)6k7.\frac{{({k}^{2})}^{6}}{{k}^{7}}.
  1. Simplify: (r5r3)4.{(\frac{{r}^{5}}{{r}^{3}})}^{4}.

29. Practice 4

  1. Simplify: (v6v4)3.{(\frac{{v}^{6}}{{v}^{4}})}^{3}.
  1. Simplify: (a3b2)4.{(\frac{{a}^{3}}{{b}^{2}})}^{4}.
  1. Simplify: (q7r5)3.{(\frac{{q}^{7}}{{r}^{5}})}^{3}.
  1. Simplify: (7x39y)2.{(\frac{7{x}^{3}}{9y})}^{2}.
  1. Simplify: (3x47y)2.{(\frac{3{x}^{4}}{7y})}^{2}.

30. Practice 5

  1. Simplify: (a2)3(a2)4(a4)5.\frac{{({a}^{2})}^{3}{({a}^{2})}^{4}}{{({a}^{4})}^{5}}.
  1. Simplify: (p3)4(p5)3(p7)6.\frac{{({p}^{3})}^{4}{({p}^{5})}^{3}}{{({p}^{7})}^{6}}.
  1. Simplify: (3r3)2(r3)7(r3)3.\frac{{(3{r}^{3})}^{2}{({r}^{3})}^{7}}{{({r}^{3})}^{3}}.
  1. Simplify: (2x4)5(4x3)2(x3)5.\frac{{(2{x}^{4})}^{5}}{{(4{x}^{3})}^{2}{({x}^{3})}^{5}}.
  1. Find the quotient: 42y9÷6y3.42{y}^{9}\mathrm{÷}6{y}^{3}.

31. Practice 6

  1. Find the quotient: 48z8÷8z2.48{z}^{8}\mathrm{÷}8{z}^{2}.
  1. Find the quotient: −72a7b38a12b4.\frac{-72{a}^{7}{b}^{3}}{8{a}^{12}{b}^{4}}.
  1. Find the quotient: −63c8d37c12d2.\frac{-63{c}^{8}{d}^{3}}{7{c}^{12}{d}^{2}}.
  1. Find the quotient: 16a7b624ab8.\frac{16{a}^{7}{b}^{6}}{24a{b}^{8}}.
  1. Find the quotient: 27p4q7−45p12q.\frac{27{p}^{4}{q}^{7}}{-45{p}^{12}q}.

32. Practice 7

  1. Find the quotient: 28x5y1449x9y12.\frac{28{x}^{5}{y}^{14}}{49{x}^{9}{y}^{12}}.
  1. Find the quotient: 30m5n1148m10n14.\frac{30{m}^{5}{n}^{11}}{48{m}^{10}{n}^{14}}.
  1. Find the quotient: (6a4b5)(4a2b5)12a5b8.\frac{(6{a}^{4}{b}^{5})(4{a}^{2}{b}^{5})}{12{a}^{5}{b}^{8}}.
  1. Find the quotient: (−12x6y9)(−4x5y8)−12x10y12.\frac{(-12{x}^{6}{y}^{9})(-4{x}^{5}{y}^{8})}{-12{x}^{10}{y}^{12}}.
  1. ⓐ y20y10\frac{{y}^{20}}{{y}^{10}} ⓑ 71672\frac{{7}^{16}}{{7}^{2}}

33. Practice 8

  1. ⓐ u24u3\frac{{u}^{24}}{{u}^{3}} ⓑ 91595\frac{{9}^{15}}{{9}^{5}}
  1. ⓐ t10t40\frac{{t}^{10}}{{t}^{40}} ⓑ 8385\frac{{8}^{3}}{{8}^{5}}
  1. ⓐ xx7\frac{x}{{x}^{7}} ⓑ 10103\frac{10}{{10}^{3}}
  1. ⓐ 130{13}^{0} ⓑ k0{k}^{0}
  1. ⓐ −150-{15}^{0} ⓑ −(150)-({15}^{0})

34. Practice 9

  1. ⓐ (6y)0{(6y)}^{0} ⓑ 6y06{y}^{0}
  1. ⓐ 7y07{y}^{0}(17y)0{(17y)}^{0} ⓑ (−93c7d15)0{(-93{c}^{7}{d}^{15})}^{0}
  1. ⓐ 15r0−22s015{r}^{0}-22{s}^{0} ⓑ (15r)0−(22s)0{(15r)}^{0}-{(22s)}^{0}
  1. ⓐ (25)2{(\frac{2}{5})}^{2} ⓑ (x3)4{(\frac{x}{3})}^{4} ⓒ (ab)5{(\frac{a}{b})}^{5}
  1. ⓐ (x2y)3{(\frac{x}{2y})}^{3} ⓑ (103q)4{(\frac{10}{3q})}^{4}

35. Practice 10

  1. (p3)4p5\frac{{({p}^{3})}^{4}}{{p}^{5}}
  1. (x4)5x15\frac{{({x}^{4})}^{5}}{{x}^{15}}
  1. n8(n6)4\frac{{n}^{8}}{{({n}^{6})}^{4}}
  1. (q8q2)3{(\frac{{q}^{8}}{{q}^{2}})}^{3}
  1. (m4m7)4{(\frac{{m}^{4}}{{m}^{7}})}^{4}

36. Practice 11

  1. (ab6)3{(\frac{a}{{b}^{6}})}^{3}
  1. (y4z10)5{(\frac{{y}^{4}}{{z}^{10}})}^{5}
  1. (3m55n)3{(\frac{3{m}^{5}}{5n})}^{3}
  1. (5u72v3)4{(\frac{5{u}^{7}}{2{v}^{3}})}^{4}
  1. (j2j5j4)3{(\frac{{j}^{2}{j}^{5}}{{j}^{4}})}^{3}

37. Practice 12

  1. (q3)6(q2)3(q4)8\frac{{({q}^{3})}^{6}{({q}^{2})}^{3}}{{({q}^{4})}^{8}}
  1. (−2k3)2(6k2)4(9k4)2\frac{{(-2{k}^{3})}^{2}{(6{k}^{2})}^{4}}{{(9{k}^{4})}^{2}}
  1. (−10n2)3(4n5)2(2n8)2\frac{{(-10{n}^{2})}^{3}{(4{n}^{5})}^{2}}{{(2{n}^{8})}^{2}}
  1. 63v10÷9v263{v}^{10}\mathrm{÷}\mathrm{}9{v}^{2}
  1. −72u12÷12u4-72{u}^{12}\mathrm{÷}\mathrm{}12{u}^{4}

38. Practice 13

  1. 54x9y3−18x6y15\frac{54{x}^{9}{y}^{3}}{-18{x}^{6}{y}^{15}}
  1. 20m8n430m5n9\frac{20{m}^{8}{n}^{4}}{30{m}^{5}{n}^{9}}
  1. 45x5y9−60x8y6\frac{45{x}^{5}{y}^{9}}{-60{x}^{8}{y}^{6}}
  1. 65a10b8c542a7b6c8\frac{65{a}^{10}{b}^{8}{c}^{5}}{42{a}^{7}{b}^{6}{c}^{8}}
  1. (−18p4q7)(−6p3q8)−36p12q10\frac{(-18{p}^{4}{q}^{7})(-6{p}^{3}{q}^{8})}{-36{p}^{12}{q}^{10}}

39. Practice 14

  1. (4u2v5)(15u3v)(12u3v)(u4v)\frac{(4{u}^{2}{v}^{5})(15{u}^{3}v)}{(12{u}^{3}v)({u}^{4}v)}
  1. ⓐ 15n10+3n1015{n}^{10}+3{n}^{10} ⓑ 15n10−3n1015{n}^{10}-3{n}^{10} ⓒ 15n10⋅3n1015{n}^{10}\cdot{}3{n}^{10} ⓓ 15n10÷3n1015{n}^{10}\mathrm{÷}3{n}^{10}
  1. ⓐ q5⋅q3{q}^{5}\cdot{q}^{3} ⓑ (q5)3{({q}^{5})}^{3}
  1. ⓐ z6z5\frac{{z}^{6}}{{z}^{5}} ⓑ z5z6\frac{{z}^{5}}{{z}^{6}}
  1. (4y)(12y7)÷8y2(4y)(12{y}^{7})\mathrm{÷}8{y}^{2}

40. Practice 15

  1. 32c114c5+42c96c3\frac{32{c}^{11}}{4{c}^{5}}+\frac{42{c}^{9}}{6{c}^{3}}
  1. 48x66x4−35x97x7\frac{48{x}^{6}}{6{x}^{4}}-\frac{35{x}^{9}}{7{x}^{7}}
  1. 56y4z57y3z3−45y2z25y\frac{56{y}^{4}{z}^{5}}{7{y}^{3}{z}^{3}}-\frac{45{y}^{2}{z}^{2}}{5y}
  1. Memory One gigabyte is approximately 109{10}^{9} bytes. One terabyte is approximately 1012{10}^{12} bytes. How many gigabytes are in one terabyte?
  1. Maurice simplifies the quotient d7d\frac{{d}^{7}}{d} by writing d7d=7\frac{{d}^{7}}{d}=7. What is wrong with his reasoning?

41. Practice 16

  1. Robert thinks x0{x}^{0} simplifies to 0. What would you say to convince Robert he is wrong?

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