Elementary Algebra 2e · free preview

6.7 Integer Exponents and Scientific Notation

Learning objectives: Use the definition of a negative exponent; Simplify expressions with integer exponents; Convert from decimal notation to scientific notation; Convert scientific notation to decimal form; Multiply and divide using scientific notation

1. Learning objectives

Learning objectives

Learning objectives

  • Use the definition of a negative exponent
  • Simplify expressions with integer exponents
  • Convert from decimal notation to scientific notation
  • Convert scientific notation to decimal form
  • Multiply and divide using scientific notation

2. Use the Definition of a Negative Exponent

Use the Definition of a Negative Exponent

We saw that the Quotient Property for Exponents introduced earlier in this chapter, has two forms depending on whether the exponent is larger in the numerator or the denominator.

If aa is a real number, a≠0a\ne{}0, and m and nm\,\mathrm{and}\,n are whole numbers, then

aman=am−n,m>n and aman=1an−m,n>m\begin{array}{l} \frac{{a}^{m}}{{a}^{n}}={a}^{m-n},m>n\,\mathrm{and}\,\frac{{a}^{m}}{{a}^{n}}=\frac{1}{{a}^{n-m}},n>m \\ \end{array}

What if we just subtract exponents regardless of which is larger?

Let’s consider x2x5\frac{{x}^{2}}{{x}^{5}}.

We subtract the exponent in the denominator from the exponent in the numerator.

x2x5x2−5x−3\begin{array}{c} \frac{{x}^{2}}{{x}^{5}} \\ {x}^{2-5} \\ {x}^{-3} \\ \end{array}

We can also simplify x2x5\frac{{x}^{2}}{{x}^{5}} by dividing out common factors:

This implies that x−3=1x3{x}^{-3}=\frac{1}{{x}^{3}} and it leads us to the definition of a negative exponent.

If nn is an integer and a≠0a\ne{}0, then a−n=1an{a}^{-n}=\frac{1}{{a}^{n}}.

The negative exponent tells us we can re-write the expression by taking the reciprocal of the base and then changing the sign of the exponent.

Any expression that has negative exponents is not considered to be in simplest form. We will use the definition of a negative exponent and other properties of exponents to write the expression with only positive exponents.

For example, if after simplifying an expression we end up with the expression x−3{x}^{-3}, we will take one more step and write 1x3\frac{1}{{x}^{3}}. The answer is considered to be in simplest form when it has only positive exponents.

3. Example 6.89

Example 6.89

Example 6.89

Simplify: ⓐ 4−2{4}^{-2} ⓑ 10−3.{10}^{-3}.

Solution

ⓐ4−2{4}^{-2}
Use the definition of a negative exponent, a−n=1an{a}^{-n}=\frac{1}{{a}^{n}}.142\frac{1}{{4}^{2}}
Simplify.116\frac{1}{16}
ⓑ10−3{10}^{-3}
Use the definition of a negative exponent, a−n=1an{a}^{-n}=\frac{1}{{a}^{n}}.1103\frac{1}{{10}^{3}}
Simplify.11000\frac{1}{1000}

In Example 6.89 we raised an integer to a negative exponent. What happens when we raise a fraction to a negative exponent? We’ll start by looking at what happens to a fraction whose numerator is one and whose denominator is an integer raised to a negative exponent.

1a−n\frac{1}{{a}^{-n}}
Use the definition of a negative exponent, a−n=1an{a}^{-n}=\frac{1}{{a}^{n}}.11an\frac{1}{\frac{1}{{a}^{n}}}
Simplify the complex fraction.1⋅an11\cdot\frac{{a}^{n}}{1}
Multiply.an{a}^{n}

This leads to the Property of Negative Exponents.

If nn is an integer and a≠0a\ne{}0, then 1a−n=an\frac{1}{{a}^{-n}}={a}^{n}.

4. Example 6.90

Example 6.90

Example 6.90

Simplify: ⓐ 1y−4\frac{1}{{y}^{-4}} ⓑ 13−2.\frac{1}{{3}^{-2}}.

Solution

ⓐ1y−4\frac{1}{{y}^{-4}}
Use the property of a negative exponent, 1a−n=an\frac{1}{{a}^{-n}}={a}^{n}.y4{y}^{4}
ⓑ13−2\frac{1}{{3}^{-2}}
Use the property of a negative exponent, 1a−n=an\frac{1}{{a}^{-n}}={a}^{n}.32{3}^{2}
Simplify.99

Suppose now we have a fraction raised to a negative exponent. Let’s use our definition of negative exponents to lead us to a new property.

(34)−2{(\frac{3}{4})}^{-2}
Use the definition of a negative exponent, a−n=1an{a}^{-n}=\frac{1}{{a}^{n}}.1(34)2\frac{1}{{(\frac{3}{4})}^{2}}
Simplify the denominator.1916\frac{1}{\frac{9}{16}}
Simplify the complex fraction.169\frac{16}{9}
But we know that 169\frac{16}{9} is (43)2{(\frac{4}{3})}^{2}.
This tells us that:(34)−2=(43)2{(\frac{3}{4})}^{-2}={(\frac{4}{3})}^{2}

Table

6.4

To get from the original fraction raised to a negative exponent to the final result, we took the reciprocal of the base—the fraction—and changed the sign of the exponent.

This leads us to the Quotient to a Negative Power Property.

If a and ba\,\mathrm{and}\,b are real numbers, a≠0,b≠0,a\ne{}0,b\ne{}0, and nn is an integer, then (ab)−n=(ba)n{(\frac{a}{b})}^{-n}={(\frac{b}{a})}^{n}.

5. Example 6.91

Example 6.91

Example 6.91

Simplify: ⓐ (57)−2{(\frac{5}{7})}^{-2} ⓑ (−2xy)−3.{(-\frac{2x}{y})}^{-3}.

Solution

ⓐ(57)−2{(\frac{5}{7})}^{-2}
Use the Quotient to a Negative Exponent Property, (ab)−n=(ba)n{(\frac{a}{b})}^{-n}={(\frac{b}{a})}^{n}.
Take the reciprocal of the fraction and change the sign of the exponent.(75)2{(\frac{7}{5})}^{2}
Simplify.4925\frac{49}{25}
ⓑ(−2xy)−3{(-\frac{2x}{y})}^{-3}
Use the Quotient to a Negative Exponent Property, (ab)−n=(ba)n{(\frac{a}{b})}^{-n}={(\frac{b}{a})}^{n}.
Take the reciprocal of the fraction and change the sign of the exponent.(−y2x)3{(-\frac{y}{2x})}^{3}
Simplify.−y38x3-\frac{{y}^{3}}{8{x}^{3}}

When simplifying an expression with exponents, we must be careful to correctly identify the base.

6. Example 6.92

Example 6.92

Example 6.92

Simplify: ⓐ (−3)−2{(-3)}^{-2} ⓑ −3−2-{3}^{-2} ⓒ (−13)−2{(-\frac{1}{3})}^{-2} ⓓ −(13)−2.-{(\frac{1}{3})}^{-2}.

Solution

ⓐ Here the exponent applies to the base −3-3.(−3)−2{(-3)}^{-2}
Take the reciprocal of the base and change the sign of the exponent.1(−3)−2\frac{1}{{(-3)}^{-2}}
Simplify.19\frac{1}{9}
ⓑ The expression −3−2-{3}^{-2} means "find the opposite of 3−2{3}^{-2}." Here the exponent applies to the base (−13){(-\frac{1}{3})}^{}.−3−2-{3}^{-2}
Rewrite as a product with −1-1.−1⋅3−2-1\cdot{3}^{-2}
Take the reciprocal of the base and change the sign of the exponent.−1⋅132-1\cdot\frac{1}{{3}^{2}}
Simplify.−19-\frac{1}{9}
ⓒ Here the exponent applies to the base (−13){(-\frac{1}{3})}^{}.(−13)−2{(-\frac{1}{3})}^{-2}
Take the reciprocal of the base and change the sign of the exponent.(−31)2{(-\frac{3}{1})}^{2}
Simplify.99
ⓓ The expression −(13)−2-{(\frac{1}{3})}^{-2} means "find the opposite of (13)−2{(\frac{1}{3})}^{-2}." Here the exponent applies to the base (13)(\frac{1}{3}).
Rewrite as a product with −1-1.−1⋅(13)−2-1\cdot{(\frac{1}{3})}^{-2}
Take the reciprocal of the base and change the sign of the exponent.−1⋅(31)2-1\cdot{(\frac{3}{1})}^{2}
Simplify.−9-9

We must be careful to follow the Order of Operations. In the next example, parts (a) and (b) look similar, but the results are different.

7. Example 6.93

Example 6.93

Example 6.93

Simplify: ⓐ 4⋅2−14\cdot{2}^{-1} ⓑ (4⋅2)−1.{(4\cdot{}2)}^{-1}.

Solution

ⓐ Do exponents before multiplication.4⋅2−14\cdot{2}^{-1}
Use a−n=1an{a}^{-n}=\frac{1}{{a}^{n}}.4⋅1214\cdot\frac{1}{{2}^{1}}
Simplify.22
ⓑ(4⋅2)−1{(4\cdot{}2)}^{-1}
Simplify inside the parentheses first.(8)−1{(8)}^{-1}
Use a−n=1an{a}^{-n}=\frac{1}{{a}^{n}}.181\frac{1}{{8}^{1}}
Simplify.18\frac{1}{8}

When a variable is raised to a negative exponent, we apply the definition the same way we did with numbers. We will assume all variables are non-zero.

8. Example 6.94

Example 6.94

Example 6.94

Simplify: ⓐ x−6{x}^{-6} ⓑ (u4)−3.{({u}^{4})}^{-3}.

Solution

  1. ⓐ  x−6Usethedefinitionofanegativeexponent, a−n=1an. 1x6\begin{array}{cccl} & & & \,{x}^{-6} \\ \mathrm{Use the definition of a negative exponent,}\,{a}^{-n}=\frac{1}{{a}^{n}}. & & & \,\frac{1}{{x}^{6}} \\ \end{array}
  1. ⓑ  (u4)−3Usethedefinitionofanegativeexponent, a−n=1an. 1(u4)3Simplify. 1u12\begin{array}{cccl} & & & \,{({u}^{4})}^{-3} \\ \mathrm{Use the definition of a negative exponent,}\,{a}^{-n}=\frac{1}{{a}^{n}}. & & & \,\frac{1}{{({u}^{4})}^{3}} \\ \mathrm{Simplify.} & & & \,\frac{1}{{u}^{12}} \\ \end{array}

When there is a product and an exponent we have to be careful to apply the exponent to the correct quantity. According to the Order of Operations, we simplify expressions in parentheses before applying exponents. We’ll see how this works in the next example.

9. Example 6.95

Example 6.95

Example 6.95

Simplify: ⓐ 5y−15{y}^{-1} ⓑ (5y)−1{(5y)}^{-1} ⓒ (−5y)−1.{(-5y)}^{-1}.

Solution

ⓐ

5y−15{y}^{-1}
Notice the exponent applies to just the base y.Take the reciprocal of y and change the sign of the exponent.5⋅1y15\cdot\frac{1}{{y}^{1}}
Simplify.5y\frac{5}{y}

ⓑ

(5y)−1{(5y)}^{-1}
Here the parentheses make the exponent apply to the base 5*y*.Take the reciprocal of 5*y* and change the sign of the exponent.1(5y)1\frac{1}{{(5y)}^{1}}
Simplify.15y\frac{1}{5y}

ⓒ

(−5y)−1{(-5y)}^{-1}
The base here is −5*y*.Take the reciprocal of −5*y* and change the sign of the exponent.1(−5y)1\frac{1}{{(-5y)}^{1}}
Simplify.1−5y\frac{1}{-5y}
Use a−b=−ab.\frac{a}{-b}=-\frac{a}{b}.−15y-\frac{1}{5y}

With negative exponents, the Quotient Rule needs only one form aman=am−n\frac{{a}^{m}}{{a}^{n}}={a}^{m-n}, for a≠0a\ne{}0. When the exponent in the denominator is larger than the exponent in the numerator, the exponent of the quotient will be negative.

10. Simplify Expressions with Integer Exponents

Simplify Expressions with Integer Exponents

All of the exponent properties we developed earlier in the chapter with whole number exponents apply to integer exponents, too. We restate them here for reference.

If a and ba\,\mathrm{and}\,b are real numbers, and m and nm\,\mathrm{and}\,n are integers, then

ProductPropertyam⋅an=am+nPowerProperty(am)n=am⋅nProducttoaPower(ab)m=ambmQuotientPropertyaman=am−n,a≠0ZeroExponentPropertya0=1,a≠0QuotienttoaPowerProperty(ab)m=ambm,  b≠0PropertiesofNegativeExponentsa−n=1an and 1a−n=anQuotienttoaNegativeExponent(ab)−n=(ba)n\begin{array}{lccrll} \mathrm{Product Property} & & & {a}^{m}\cdot{a}^{n} & = & {a}^{m+n} \\ \mathrm{Power Property} & & & {({a}^{m})}^{n} & = & {a}^{m\cdot{}n} \\ \mathrm{Product to a Power} & & & {(ab)}^{m} & = & {a}^{m}{b}^{m} \\ \mathrm{Quotient Property} & & & \frac{{a}^{m}}{{a}^{n}} & = & {a}^{m-n},a\ne{}0 \\ \mathrm{Zero Exponent Property} & & & {a}^{0} & = & 1,a\ne{}0 \\ \mathrm{Quotient to a Power Property} & & & {(\frac{a}{b})}^{m} & = & \frac{{a}^{m}}{{b}^{m}},\,\,b\ne{}0 \\ \mathrm{Properties of Negative Exponents} & & & {a}^{-n} & = & \frac{1}{{a}^{n}}\,\mathrm{and}\,\frac{1}{{a}^{-n}}={a}^{n} \\ \mathrm{Quotient to a Negative Exponent} & & & {(\frac{a}{b})}^{-n} & = & {(\frac{b}{a})}^{n} \\ \end{array}

11. Example 6.96

Example 6.96

Example 6.96

Simplify: ⓐ x−4⋅x6{x}^{-4}\cdot{x}^{6} ⓑ y−6⋅y4{y}^{-6}\cdot{y}^{4} ⓒ z−5⋅z−3.{z}^{-5}\cdot{z}^{-3}.

Solution

ⓐ

x−4⋅x6{x}^{-4}\cdot{x}^{6}
Use the Product Property, am⋅an=am+n.{a}^{m}\cdot{a}^{n}={a}^{m+n}.x−4+6{x}^{-4+6}
Simplify.x2{x}^{2}

ⓑ

y−6⋅y4{y}^{-6}\cdot{y}^{4}
Notice the same bases, so add the exponents.y−6+4{y}^{-6+4}
Simplify.y−2{y}^{-2}
Use the definition of a negative exponent, a−n=1an.{a}^{-n}=\frac{1}{{a}^{n}}.1y2\frac{1}{{y}^{2}}

ⓒ

z−5⋅z−3{z}^{-5}\cdot{z}^{-3}
Add the exponents, since the bases are the same.z−5−3{z}^{-5-3}
Simplify.z−8{z}^{-8}
Take the reciprocal and change the sign of the exponent,using the definition of a negative exponent.1z8\frac{1}{{z}^{8}}

In the next two examples, we’ll start by using the Commutative Property to group the same variables together. This makes it easier to identify the like bases before using the Product Property.

12. Example 6.97

Example 6.97

Example 6.97

Simplify: (m4n−3)(m−5n−2).({m}^{4}{n}^{-3})({m}^{-5}{n}^{-2}).

Solution

(m4n−3)(m−5n−2)({m}^{4}{n}^{-3})({m}^{-5}{n}^{-2})
Use the Commutative Property to get like bases together.m4m−5⋅n−2n−3{m}^{4}{m}^{-5}\cdot{n}^{-2}{n}^{-3}
Add the exponents for each base.m−1⋅n−5{m}^{-1}\cdot{n}^{-5}
Take reciprocals and change the signs of the exponents.1m1⋅1n5\frac{1}{{m}^{1}}\cdot\frac{1}{{n}^{5}}
Simplify.1mn5\frac{1}{m{n}^{5}}

In the next two examples, we’ll use the Power Property and the Product to a Power Property.

13. Example 6.98

Example 6.98

Example 6.98

Simplify: (6k3)−2.{(6{k}^{3})}^{-2}.

Solution

(6k3)−2{(6{k}^{3})}^{-2}
Use the Product to a Power Property, (ab)m=ambm.{(ab)}^{m}={a}^{m}{b}^{m}.(6)−2(k3)−2{(6)}^{-2}{({k}^{3})}^{-2}
Use the Power Property, (am)n=am⋅n.{({a}^{m})}^{n}={a}^{m\cdot{}n}.6−2k−6{6}^{-2}{k}^{-6}
Use the Definition of a Negative Exponent, a−n=1an.{a}^{-n}=\frac{1}{{a}^{n}}.162⋅1k6\frac{1}{{6}^{2}}\cdot\frac{1}{{k}^{6}}
Simplify.136k6\frac{1}{36{k}^{6}}

14. Example 6.99

Example 6.99

Example 6.99

Simplify: (5x−3)2.{(5{x}^{-3})}^{2}.

Solution

(5x−3)2{(5{x}^{-3})}^{2}
Use the Product to a Power Property, (ab)m=ambm.{(ab)}^{m}={a}^{m}{b}^{m}.52(x−3)2{5}^{2}{({x}^{-3})}^{2}
Simplify 525^{2} and multiply the exponents of x using the PowerProperty, (am)n=am⋅n.{({a}^{m})}^{n}={a}^{m\cdot{}n}.25⋅x−625\cdot{x}^{-6}
Rewrite x−6{}^{−6} by using the Definition of a Negative Exponent, a−n=1an.{a}^{-n}=\frac{1}{{a}^{n}}.25⋅1x625\cdot\frac{1}{{x}^{6}}
Simplify.25x6\frac{25}{{x}^{6}}

To simplify a fraction, we use the Quotient Property and subtract the exponents.

15. Example 6.100

Example 6.100

Example 6.100

Simplify: r5r−4.\frac{{r}^{5}}{{r}^{-4}}.

Solution

r5r−4\frac{{r}^{5}}{{r}^{-4}}
Use the Quotient Property, aman=am−n.\frac{{a}^{m}}{{a}^{n}}={a}^{m-n}.r5−(−4){r}^{5-(-4)}
Simplify.r9{r}^{9}

16. Convert from Decimal Notation to Scientific Notation

Convert from Decimal Notation to Scientific Notation

Remember working with place value for whole numbers and decimals? Our number system is based on powers of 10. We use tens, hundreds, thousands, and so on. Our decimal numbers are also based on powers of tens—tenths, hundredths, thousandths, and so on. Consider the numbers 4,000 and 0.0040.004. We know that 4,000 means 4 × 1,0004\,\times\,1,000 and 0.004 means 4 × 11,0004\,\times\,\frac{1}{1,000}.

If we write the 1000 as a power of ten in exponential form, we can rewrite these numbers in this way:

4,000 0.0044 × 1,000 4 × 11,0004 × 103 4 × 1103 4 × 10−3\begin{array}{lccl} 4,000 & & & \,0.004 \\ 4\,\times\,1,000 & & & \,4\,\times\,\frac{1}{1,000} \\ 4\,\times\,{10}^{3} & & & \,4\,\times\,\frac{1}{{10}^{3}} \\ & & & \,4\,\times\,{10}^{-3} \\ \end{array}

When a number is written as a product of two numbers, where the first factor is a number greater than or equal to one but less than 10, and the second factor is a power of 10 written in exponential form, it is said to be in scientific notation.

A number is expressed in scientific notation when it is of the form

a × 10n where 1≤a<10 and n is aninteger\begin{array}{cccl} & & & a\,\times\,{10}^{n}\,\mathrm{where}\,1\le{}a<10\,\mathrm{and}\,n\,\mathrm{is an integer} \\ \end{array}

It is customary in scientific notation to use as the  × \,\times\, multiplication sign, even though we avoid using this sign elsewhere in algebra.

If we look at what happened to the decimal point, we can see a method to easily convert from decimal notation to scientific notation.

In both cases, the decimal was moved 3 places to get the first factor between 1 and 10.

Thepowerof10ispositivewhenthenumberislargerthan1:4,000=4 × 103Thepowerof10isnegativewhenthenumberisbetween0and1:0.004=4 × 10−3\begin{array}{lccl} \mathrm{The power of 10 is positive when the number is larger than 1:} & & & 4,000=4\,\times\,{10}^{3} \\ \mathrm{The power of 10 is negative when the number is between 0 and 1:} & & & 0.004=4\,\times\,{10}^{-3} \\ \end{array}

17. Example 6.101

Example 6.101

Example 6.101

How to Convert from Decimal Notation to Scientific Notation

Write in scientific notation: 37,000.

Convert from decimal notation to scientific notation

  1. Step 1. Move the decimal point so that the first factor is greater than or equal to 1 but less than 10.
  2. Step 2. Count the number of decimal places, n, that the decimal point was moved.
  3. Step 3. Write the number as a product with a power of 10. If the original number is: greater than 1, the power of 10 will be 10n10^{n}. between 0 and 1, the power of 10 will be 10−n10^{−n}.
  4. Step 4. Check.

18. Example 6.102

Example 6.102

Example 6.102

Write in scientific notation: 0.0052.0.0052.

Solution

The original number, 0.00520.0052, is between 0 and 1 so we will have a negative power of 10.

19. Convert Scientific Notation to Decimal Form

Convert Scientific Notation to Decimal Form

How can we convert from scientific notation to decimal form? Let’s look at two numbers written in scientific notation and see.

9.12 × 104 9.12 × 10−49.12 × 10,000 9.12 × 0.000191,200 0.000912\begin{array}{cccc} 9.12\,\times\,{10}^{4} & & & \,9.12\,\times\,{10}^{-4} \\ 9.12\,\times\,10,000 & & & \,9.12\,\times\,0.0001 \\ 91,200 & & & \,0.000912 \\ \end{array}

If we look at the location of the decimal point, we can see an easy method to convert a number from scientific notation to decimal form.

9.12 × 104=91,200 9.12 × 10−4=0.000912\begin{array}{cccc} 9.12\,\times\,{10}^{4}=91,200 & & & \,9.12\,\times\,{10}^{-4}=0.000912 \\ \end{array}

In both cases the decimal point moved 4 places. When the exponent was positive, the decimal moved to the right. When the exponent was negative, the decimal point moved to the left.

20. Example 6.103

Example 6.103

Example 6.103

How to Convert Scientific Notation to Decimal Form

Convert to decimal form: 6.2 × 103.6.2\,\times\,{10}^{3}.

The steps are summarized below.

Convert scientific notation to decimal form.

To convert scientific notation to decimal form:

  1. Step 1. Determine the exponent, nn, on the factor 10.
  2. Step 2. Move the decimal nn places, adding zeros if needed. If the exponent is positive, move the decimal point nn places to the right. If the exponent is negative, move the decimal point ∣n∣|n| places to the left.
  3. Step 3. Check.

21. Example 6.104

Example 6.104

Example 6.104

Convert to decimal form: 8.9 × 10−2.8.9\,\times\,{10}^{-2}.

Solution

22. Multiply and Divide Using Scientific Notation

Multiply and Divide Using Scientific Notation

Astronomers use very large numbers to describe distances in the universe and ages of stars and planets. Chemists use very small numbers to describe the size of an atom or the charge on an electron. When scientists perform calculations with very large or very small numbers, they use scientific notation. Scientific notation provides a way for the calculations to be done without writing a lot of zeros. We will see how the Properties of Exponents are used to multiply and divide numbers in scientific notation.

23. Example 6.105

Example 6.105

Example 6.105

Multiply. Write answers in decimal form: (4 × 105)(2 × 10−7).(4\,\times\,{10}^{5})(2\,\times\,{10}^{-7}).

Solution

(4 × 105)(2 × 10−7)UsetheCommutativePropertytorearrangethefactors.4⋅2⋅105⋅10−7Multiply.8 × 10−2Changetodecimalformbymovingthedecimaltwoplacesleft.0.08\begin{array}{cccl} & & & (4\,\times\,{10}^{5})(2\,\times\,{10}^{-7}) \\ \mathrm{Use the Commutative Property to rearrange the factors.} & & & 4\cdot{}2\cdot{10}^{5}\cdot{10}^{-7} \\ \mathrm{Multiply.} & & & 8\,\times\,{10}^{-2} \\ \mathrm{Change to decimal form by moving the decimal two places left.} & & & 0.08 \\ \end{array}

24. Example 6.106

Example 6.106

Example 6.106

Divide. Write answers in decimal form: 9 × 1033 × 10−2.\frac{9\,\times\,{10}^{3}}{3\,\times\,{10}^{-2}}.

Solution

9 × 1033 × 10−2\frac{9\,\times\,{10}^{3}}{3\,\times\,{10}^{-2}}
Separate the factors, rewriting as the product of two fractions.93 × 10310−2\frac{9}{3}\,\times\,\frac{{10}^{3}}{{10}^{-2}}
Divide.3 × 1053\,\times\,{10}^{5}
Change to decimal form by moving the decimal five places right.300,000

25. Section 6.7 Exercises

Section 6.7 Exercises

Section 6.7 Exercises

Use the Definition of a Negative Exponent

In the following exercises, simplify.

Simplify Expressions with Integer Exponents

In the following exercises, simplify.

Convert from Decimal Notation to Scientific Notation

In the following exercises, write each number in scientific notation.

Convert Scientific Notation to Decimal Form

In the following exercises, convert each number to decimal form.

Multiply and Divide Using Scientific Notation

In the following exercises, multiply. Write your answer in decimal form.

In the following exercises, divide. Write your answer in decimal form.

Everyday Math

Writing Exercises

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ Overall, after looking at the checklist, do you think you are well-prepared for the next section? Why or why not?

26. Practice 1

  1. Simplify: ⓐ 2−3{2}^{-3} ⓑ 10−7.{10}^{-7}.
  1. Simplify: ⓐ 3−2{3}^{-2} ⓑ 10−4.{10}^{-4}.
  1. Simplify: ⓐ 1p−8\frac{1}{{p}^{-8}} ⓑ 14−3.\frac{1}{{4}^{-3}}.
  1. Simplify: ⓐ 1q−7\frac{1}{{q}^{-7}} ⓑ 12−4.\frac{1}{{2}^{-4}}.
  1. Simplify: ⓐ (23)−4{(\frac{2}{3})}^{-4} ⓑ (−6mn)−2.{(-\frac{6m}{n})}^{-2}.

27. Practice 2

  1. Simplify: ⓐ (35)−3{(\frac{3}{5})}^{-3} ⓑ (−a2b)−4.{(-\frac{a}{2b})}^{-4}.
  1. Simplify: ⓐ (−5)−2{(-5)}^{-2} ⓑ −5−2-{5}^{-2} ⓒ (−15)−2{(-\frac{1}{5})}^{-2} ⓓ −(15)−2.-{(\frac{1}{5})}^{-2}.
  1. Simplify: ⓐ (−7)−2{(-7)}^{-2} ⓑ −7−2-{7}^{-2}, ⓒ (−17)−2{(-\frac{1}{7})}^{-2} ⓓ −(17)−2.-{(\frac{1}{7})}^{-2}.
  1. Simplify: ⓐ 6⋅3−16\cdot{3}^{-1} ⓑ (6⋅3)−1.{(6\cdot{}3)}^{-1}.
  1. Simplify: ⓐ 8⋅2−28\cdot{2}^{-2} ⓑ (8⋅2)−2.{(8\cdot{}2)}^{-2}.

28. Practice 3

  1. Simplify: ⓐ y−7{y}^{-7} ⓑ (z3)−5.{({z}^{3})}^{-5}.
  1. Simplify: ⓐ p−9{p}^{-9} ⓑ (q4)−6.{({q}^{4})}^{-6}.
  1. Simplify: ⓐ 8p−18{p}^{-1} ⓑ (8p)−1{(8p)}^{-1} ⓒ (−8p)−1.{(-8p)}^{-1}.
  1. Simplify: ⓐ 11q−1{11q}^{-1} ⓑ (11q)−1{(11q)}^{-1}−(11q)−1-{(11q)}^{-1} ⓒ −111q-\frac{1}{11q}
  1. Simplify: ⓐ x−3⋅x7{x}^{-3}\cdot{x}^{7} ⓑ y−7⋅y2{y}^{-7}\cdot{y}^{2} ⓒ z−4⋅z−5.{z}^{-4}\cdot{z}^{-5}.

29. Practice 4

  1. Simplify: ⓐ a−1⋅a6{a}^{-1}\cdot{a}^{6} ⓑ b−8⋅b4{b}^{-8}\cdot{b}^{4} ⓒ c−8⋅c−7.{c}^{-8}\cdot{c}^{-7}.
  1. Simplify: (p6q−2)(p−9q−1).({p}^{6}{q}^{-2})({p}^{-9}{q}^{-1}).
  1. Simplify: (r5s−3)(r−7s−5).({r}^{5}{s}^{-3})({r}^{-7}{s}^{-5}).
  1. Simplify: (−6c−6d4)(−5c−2d−1).(-6{c}^{-6}{d}^{4})(-5{c}^{-2}{d}^{-1}).
  1. Simplify: (−4x4)−2.{(-4{x}^{4})}^{-2}.

30. Practice 5

  1. Simplify: (2b3)−4.{(2{b}^{3})}^{-4}.
  1. Simplify: (8a−4)2.{(8{a}^{-4})}^{2}.
  1. Simplify: (2c−4)3.{(2{c}^{-4})}^{3}.
  1. Simplify: x8x−3.\frac{{x}^{8}}{{x}^{-3}}.
  1. Simplify: y8y−6.\frac{{y}^{8}}{{y}^{-6}}.

31. Practice 6

  1. Write in scientific notation: 96,000.96,000.
  1. Write in scientific notation: 48,300.48,300.
  1. Write in scientific notation: 0.0078.0.0078.
  1. Write in scientific notation: 0.0129.0.0129.
  1. Convert to decimal form: 1.3 × 103.1.3\,\times\,{10}^{3}.

32. Practice 7

  1. Convert to decimal form: 9.25 × 104.9.25\,\times\,{10}^{4}.
  1. Divide 8 × 1042 × 10−1\frac{8\,\times\,{10}^{4}}{2\,\times\,{10}^{-1}}. Write answers in decimal form.
  1. Divide 8 × 1024 × 10−2\frac{8\,\times\,{10}^{2}}{4\,\times\,{10}^{-2}}. Write answers in decimal form.
  1. ⓐ 3−4{3}^{-4} ⓑ 10−2{10}^{-2}
  1. ⓐ 2−8{2}^{-8} ⓑ 10−2{10}^{-2}

33. Practice 8

  1. ⓐ 1c−5\frac{1}{{c}^{-5}} ⓑ 15−2\frac{1}{{5}^{-2}}
  1. ⓐ 1t−9\frac{1}{{t}^{-9}} ⓑ 110−4\frac{1}{{10}^{-4}}
  1. ⓐ (310)−2{(\frac{3}{10})}^{-2} ⓑ (−2cd)−3{(-\frac{2}{cd})}^{-3}
  1. ⓐ (72)−3{(\frac{7}{2})}^{-3} ⓑ (−3xy2)−3{(-\frac{3}{x{y}^{2}})}^{-3}
  1. ⓐ (−7)−2{(-7)}^{-2} ⓑ −7−2-{7}^{-2} ⓒ (−17)−2{(-\frac{1}{7})}^{-2} ⓓ −(17)−2-{(\frac{1}{7})}^{-2}

34. Practice 9

  1. ⓐ −5−3-{5}^{-3} ⓑ (−15)−3{(-\frac{1}{5})}^{-3} ⓒ −(15)−3-{(\frac{1}{5})}^{-3} ⓓ (−5)−3{(-5)}^{-3}
  1. ⓐ 2⋅5−12\cdot{5}^{-1} ⓑ (2⋅5)−1{(2\cdot{}5)}^{-1}
  1. ⓐ 3⋅4−23\cdot{4}^{-2} ⓑ (3⋅4)−2{(3\cdot{}4)}^{-2}
  1. ⓐ b−5{b}^{-5} ⓑ (k2)−5{({k}^{2})}^{-5}
  1. ⓐ s−8{s}^{-8} ⓑ (a9)−10{({a}^{9})}^{-10}

35. Practice 10

  1. ⓐ 6r−16{r}^{-1} ⓑ (6r)−1{(6r)}^{-1} ⓒ (−6r)−1{(-6r)}^{-1}
  1. ⓐ (2q)−4{(2q)}^{-4} ⓑ 2q−42{q}^{-4} ⓒ −2q−4-2{q}^{-4}
  1. ⓐ s3⋅s−7{s}^{3}\cdot{s}^{-7} ⓑ q−8⋅q3{q}^{-8}\cdot{q}^{3} ⓒ y−2⋅y−5{y}^{-2}\cdot{y}^{-5}
  1. ⓐ y5⋅y−5{y}^{5}\cdot{y}^{-5} ⓑ y⋅y5y\cdot{y}^{5} ⓒ y⋅y−5y\cdot{y}^{-5}
  1. x4⋅x−2⋅x−3{x}^{4}\cdot{x}^{-2}\cdot{x}^{-3}

36. Practice 11

  1. (m3n−3)(m−5n−1)({m}^{3}{n}^{-3})({m}^{-5}{n}^{-1})
  1. (pq−4)(p−6q−3)(p{q}^{-4})({p}^{-6}{q}^{-3})
  1. (−2j−5k8)(7j2k−3)(-2{j}^{-5}{k}^{8})(7{j}^{2}{k}^{-3})
  1. (−5m4n6)(8m−5n−3)(-5{m}^{4}{n}^{6})(8{m}^{-5}{n}^{-3})
  1. (4y3)−3{(4{y}^{3})}^{-3}

37. Practice 12

  1. (2p−5)2{(2{p}^{-5})}^{2}
  1. n5n−2\frac{{n}^{5}}{{n}^{-2}}
  1. y−5y−10\frac{{y}^{-5}}{{y}^{-10}}
  1. 340,000
  1. 1,290,000

38. Practice 13

  1. 1.6 × 10101.6\,\times\,{10}^{10}
  1. (3.5 × 10−4)(1.6 × 10−2)(3.5\,\times\,{10}^{-4})(1.6\,\times\,{10}^{-2})
  1. 5 × 10−21 × 10−10\frac{5\,\times\,{10}^{-2}}{1\,\times\,{10}^{-10}}
  1. 8 × 1064 × 10−1\frac{8\,\times\,{10}^{6}}{4\,\times\,{10}^{-1}}
  1. The population of the world on July 4, 2010 was more than 6,850,000,000. Write the number in scientific notation

39. Practice 14

  1. The probability of winning the 2010 Megamillions lottery was about 0.0000000057. Write the number in scientific notation.
  1. At the start of 2012, the US federal budget had a deficit of more than $1.5 × 10131.5\,\times\,{10}^{13}. Convert this number to decimal form.
  1. Coin production In 1942, the U.S. Mint produced 154,500,000 nickels. Write 154,500,000 in scientific notation.
  1. Debt At the end of fiscal year 2015 the gross United States federal government debt was estimated to be approximately 18,600,000,000,000(18,600,000,000,000 (18.6 trillion), according to the Federal Budget. The population of the United States was approximately 300,000,000 people at the end of fiscal year 2015.
  1. ⓐ Write the debt in scientific notation.
  1. ⓑ Write the population in scientific notation.
  1. ⓒ Find the amount of debt per person by using scientific notation to divide the debt by the population. Write the answer in scientific notation.
  1. When you convert a number from decimal notation to scientific notation, how do you know if the exponent will be positive or negative?

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