Elementary Algebra 2e · free preview

9.1 Simplify and Use Square Roots

Learning objectives: Simplify expressions with square roots; Estimate square roots; Approximate square roots; Simplify variable expressions with square roots

1. Learning objectives

Learning objectives

Learning objectives

  • Simplify expressions with square roots
  • Estimate square roots
  • Approximate square roots
  • Simplify variable expressions with square roots

2. Simplify Expressions with Square Roots

Simplify Expressions with Square Roots

Remember that when a number nn is multiplied by itself, we write n2{n}^{2} and read it “n squared.” For example, 152{15}^{2} reads as “15 squared,” and 225 is called the square of 15, since 152=225{15}^{2}=225.

If n2=m{n}^{2}=m, then mm is the square of nn.

Sometimes we will need to look at the relationship between numbers and their squares in reverse. Because 225 is the square of 15, we can also say that 15 is a square root of 225. A number whose square is mm is called a square root of mm.

If n2=m{n}^{2}=m, then nn is a square root of mm.

Notice (−15)2=225{(-15)}^{2}=225 also, so −15-15 is also a square root of 225. Therefore, both 15 and −15-15 are square roots of 225.

So, every positive number has two square roots—one positive and one negative. What if we only wanted the positive square root of a positive number? The radical sign, m\sqrt{m}, denotes the positive square root. The positive square root is also called the principal square root.

We also use the radical sign for the square root of zero. Because 02=0{0}^{2}=0, 0=0\sqrt{0}=0. Notice that zero has only one square root.

m\sqrt{m} is read as “the square root of mm.” If m=n2m={n}^{2}, then m=n\sqrt{m}=n, for n≥0n\ge{}0.

The square root of mm, m\sqrt{m}, is the non-negative number whose square is mm.

Since 15 is the positive square root of 225, we write 225=15\sqrt{225}=15. Fill in Figure 9.2 to make a table of square roots you can refer to as you work this chapter.

We know that every positive number has two square roots and the radical sign indicates the positive one. We write 225=15\sqrt{225}=15. If we want to find the negative square root of a number, we place a negative in front of the radical sign. For example, −225=−15-\sqrt{225}=-15.

3. Example 9.1

Example 9.1

Example 9.1

Simplify: ⓐ 36\sqrt{36} ⓑ 196\sqrt{196} ⓒ −81-\sqrt{81} ⓓ −289-\sqrt{289}.

Solution

ⓐ

36\sqrt{36}
Since 62=36{6}^{2}=366

ⓑ

196\sqrt{196}
Since 142=196{14}^{2}=19614

ⓒ

−81-\sqrt{81}
The negative is in front of the radical sign.−9

ⓓ

−289-\sqrt{289}
The negative is in front of the radical sign.−17

4. Example 9.2

Example 9.2

Example 9.2

Simplify: ⓐ −169\sqrt{-169} ⓑ −64-\sqrt{64}.

Solution

ⓐ

−169\sqrt{-169}
There is no real number whose square is −169.−169\sqrt{-169} is not a real number.

ⓑ

−64-\sqrt{64}
The negative is in front of the radical.−8

When using the order of operations to simplify an expression that has square roots, we treat the radical as a grouping symbol.

5. Example 9.3

Example 9.3

Example 9.3

Simplify: ⓐ 25+144\sqrt{25}+\sqrt{144} ⓑ 25+144\sqrt{25+144}.

Solution

ⓐ

25+144\sqrt{25}+\sqrt{144}
Use the order of operations.5+125+12
Simplify.17

ⓑ

25+144\sqrt{25+144}
Simplify under the radical sign.169\sqrt{169}
Simplify.13
Notice the different answers in parts ⓐ and ⓑ !

6. Estimate Square Roots

Estimate Square Roots

So far we have only considered square roots of perfect square numbers. The square roots of other numbers are not whole numbers. Look at Table 9.1 below.

NumberSquare Root
44\sqrt{4} = 2
55\sqrt{5}
66\sqrt{6}
77\sqrt{7}
88\sqrt{8}
99\sqrt{9} = 3

Table

9.1

The square roots of numbers between 4 and 9 must be between the two consecutive whole numbers 2 and 3, and they are not whole numbers. Based on the pattern in the table above, we could say that 5\sqrt{5} must be between 2 and 3. Using inequality symbols, we write:

2<5<32<\sqrt{5}<3

7. Example 9.4

Example 9.4

Example 9.4

Estimate 60\sqrt{60} between two consecutive whole numbers.

Solution

Think of the perfect square numbers closest to 60. Make a small table of these perfect squares and their squares roots.

8. Approximate Square Roots

Approximate Square Roots

There are mathematical methods to approximate square roots, but nowadays most people use a calculator to find them. Find the x\sqrt{x} key on your calculator. You will use this key to approximate square roots.

When you use your calculator to find the square root of a number that is not a perfect square, the answer that you see is not the exact square root. It is an approximation, accurate to the number of digits shown on your calculator’s display. The symbol for an approximation is ≈\approx and it is read ‘approximately.’

Suppose your calculator has a 10-digit display. You would see that

 5≈2.236067978\,\sqrt{5}\approx{}2.236067978

If we wanted to round 5\sqrt{5} to two decimal places, we would say

5≈2.24\sqrt{5}\approx{}2.24

How do we know these values are approximations and not the exact values? Look at what happens when we square them:

(2.236067978)2=5.000000002(2.24)2=5.0176\begin{array}{rll} {(2.236067978)}^{2} & = & 5.000000002 \\ {(2.24)}^{2} & = & 5.0176 \\ \end{array}

Their squares are close to 5, but are not exactly equal to 5.

Using the square root key on a calculator and then rounding to two decimal places, we can find:

4=25≈2.246≈2.457≈2.658≈2.839=3\begin{array}{rll} \sqrt{4} & = & 2 \\ \sqrt{5} & \approx & 2.24 \\ \sqrt{6} & \approx & 2.45 \\ \sqrt{7} & \approx & 2.65 \\ \sqrt{8} & \approx & 2.83 \\ \sqrt{9} & = & 3 \\ \end{array}

9. Example 9.5

Example 9.5

Example 9.5

Round 17\sqrt{17} to two decimal places.

Solution

17\sqrt{17}
Use the calculator square root key.4.123105626...
Round to two decimal places.4.12
17≈4.12\sqrt{17}\approx{}4.12

10. Simplify Variable Expressions with Square Roots

Simplify Variable Expressions with Square Roots

What if we have to find a square root of an expression with a variable? Consider 9x2\sqrt{9{x}^{2}}. Can you think of an expression whose square is 9x29{x}^{2}?

(?)2=9x2(3x)2=9x2,so 9x2=3x\begin{array}{rllccc} {(?)}^{2} & = & 9{x}^{2} & & & \\ {(3x)}^{2} & = & 9{x}^{2}, & & & \mathrm{so}\,\sqrt{9{x}^{2}}=3x \\ \end{array}

When we use the radical sign to take the square root of a variable expression, we should specify that x≥0x\ge{}0 to make sure we get the principal square root.

However, in this chapter we will assume that each variable in a square-root expression represents a non-negative number and so we will not write x≥0x\ge{}0 next to every radical.

What about square roots of higher powers of variables? Think about the Power Property of Exponents we used in Chapter 6.

(am)n=am⋅n{({a}^{m})}^{n}={a}^{m\cdot{}n}

If we square am{a}^{m}, the exponent will become 2m2m.

(am)2=a2m{({a}^{m})}^{2}={a}^{2m}

How does this help us take square roots? Let’s look at a few:

25u8=5u4because (5u4)2=25u816r20=4r10because (4r10)2=16r20196q36=14q18because (14q18)2=196q36\begin{array}{rl} \sqrt{25{u}^{8}}=5{u}^{4} & \mathrm{because}\,{(5{u}^{4})}^{2}=25{u}^{8} \\ \sqrt{16{r}^{20}}=4{r}^{10} & \mathrm{because}\,{(4{r}^{10})}^{2}=16{r}^{20} \\ \sqrt{196{q}^{36}}=14{q}^{18} & \mathrm{because}\,{(14{q}^{18})}^{2}=196{q}^{36} \\ \end{array}

11. Example 9.6

Example 9.6

Example 9.6

Simplify: ⓐ x6\sqrt{{x}^{6}} ⓑ y16\sqrt{{y}^{16}}.

Solution

ⓐ

x6\sqrt{{x}^{6}}
Since (x3)2=x6.\mathrm{Since}\,{({x}^{3})}^{2}={x}^{6}.x3{x}^{3}

ⓑ

y16\sqrt{{y}^{16}}
Since (y8)2=y16.\mathrm{Since}\,{({y}^{8})}^{2}={y}^{16}.y8{y}^{8}

12. Example 9.7

Example 9.7

Example 9.7

Simplify: 16n2\sqrt{16{n}^{2}}.

Solution

16n2\sqrt{16{n}^{2}}
Since (4n)2=16n2.\mathrm{Since}\,{(4n)}^{2}=16{n}^{2}.4n4n

13. Example 9.8

Example 9.8

Example 9.8

Simplify: −81c2-\sqrt{81{c}^{2}}.

Solution

−81c2-\sqrt{81{c}^{2}}
Since (9c)2=81c2.\mathrm{Since}\,{(9c)}^{2}=81{c}^{2}.−9c-9c

14. Example 9.9

Example 9.9

Example 9.9

Simplify: 36x2y2\sqrt{36{x}^{2}{y}^{2}}.

Solution

36x2y2\sqrt{36{x}^{2}{y}^{2}}
Since (6xy)2=36x2y2.\mathrm{Since}\,{(6xy)}^{2}=36{x}^{2}{y}^{2}.6xy6xy

15. Example 9.10

Example 9.10

Example 9.10

Simplify: 64p64\sqrt{64{p}^{64}}.

Solution

64p64\sqrt{64{p}^{64}}
Since (8p32)2=64p64.\mathrm{Since}\,{(8{p}^{32})}^{2}=64{p}^{64}.8p328{p}^{32}

16. Example 9.11

Example 9.11

Example 9.11

Simplify: 121a6b8\sqrt{121{a}^{6}{b}^{8}}

Solution

121a6b8\sqrt{121{a}^{6}{b}^{8}}
Since (11a3b4)2=121a6b8.\mathrm{Since}\,{(11{a}^{3}{b}^{4})}^{2}=121{a}^{6}{b}^{8}.11a3b411{a}^{3}{b}^{4}

17. Section 9.1 Exercises

Section 9.1 Exercises

Section 9.1 Exercises

Simplify Expressions with Square Roots

In the following exercises, simplify.

Estimate Square Roots

In the following exercises, estimate each square root between two consecutive whole numbers.

Approximate Square Roots

In the following exercises, approximate each square root and round to two decimal places.

Simplify Variable Expressions with Square Roots

In the following exercises, simplify.

Everyday Math

Writing Exercises

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ On a scale of 1–10, how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?

18. Practice 1

  1. Simplify: ⓐ −49-\sqrt{49} ⓑ 225\sqrt{225}.
  1. Simplify: ⓐ 64\sqrt{64} ⓑ −121-\sqrt{121}.
  1. Simplify: ⓐ −196\sqrt{-196} ⓑ −81-\sqrt{81}.

19. Practice 2

  1. Simplify: ⓐ −49-\sqrt{49} ⓑ −121\sqrt{-121}.
  1. Simplify: ⓐ 9+16\sqrt{9}+\sqrt{16} ⓑ 9+16\sqrt{9+16}.
  1. Simplify: ⓐ 64+225\sqrt{64+225} ⓑ 64+225\sqrt{64}+\sqrt{225}.

20. Practice 3

  1. Estimate the square root 38\sqrt{38} between two consecutive whole numbers.
  1. Estimate the square root 84\sqrt{84} between two consecutive whole numbers.
  1. Round 11\sqrt{11} to two decimal places.

21. Practice 4

  1. Round 13\sqrt{13} to two decimal places.
  1. Simplify: ⓐ y8\sqrt{{y}^{8}} ⓑ z12\sqrt{{z}^{12}}.
  1. Simplify: ⓐ m4\sqrt{{m}^{4}} ⓑ b10\sqrt{{b}^{10}}.

22. Practice 5

  1. Simplify: 64x2\sqrt{64{x}^{2}}.
  1. Simplify: 169y2\sqrt{169{y}^{2}}.
  1. Simplify: −121y2-\sqrt{121{y}^{2}}.

23. Practice 6

  1. Simplify: −100p2-\sqrt{100{p}^{2}}.
  1. Simplify: 100a2b2\sqrt{100{a}^{2}{b}^{2}}.
  1. Simplify: 225m2n2\sqrt{225{m}^{2}{n}^{2}}.

24. Practice 7

  1. Simplify: 49x30\sqrt{49{x}^{30}}.
  1. Simplify: 81w36\sqrt{81{w}^{36}}.
  1. Simplify: 169x10y14\sqrt{169{x}^{10}{y}^{14}}.

25. Practice 8

  1. Simplify: 144p12q20\sqrt{144{p}^{12}{q}^{20}}.
  1. −4-\sqrt{4}
  1. −1-\sqrt{1}

26. Practice 9

  1. −121\sqrt{-121}
  1. −9\sqrt{-9}
  1. 70\sqrt{70}

27. Practice 10

  1. 200\sqrt{200}
  1. y2\sqrt{{y}^{2}}
  1. a14\sqrt{{a}^{14}}

28. Practice 11

  1. 49x2\sqrt{49{x}^{2}}
  1. 121m20\sqrt{121{m}^{20}}
  1. 81x36\sqrt{81{x}^{36}}

29. Practice 12

  1. −81x18-\sqrt{81{x}^{18}}
  1. −64a2-\sqrt{64{a}^{2}}
  1. 144x2y2\sqrt{144{x}^{2}{y}^{2}}

30. Practice 13

  1. 169w8y10\sqrt{169{w}^{8}{y}^{10}}
  1. 9c8d12\sqrt{9{c}^{8}{d}^{12}}
  1. Decorating Denise wants to have a square accent of designer tiles in her new shower. She can afford to buy 625 square centimeters of the designer tiles. How long can a side of the accent be?

31. Practice 14

  1. Why is there no real number equal to −64\sqrt{-64}?

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