Prealgebra 2e · free preview

5.3 Decimals and Fractions

Learning objectives: Convert fractions to decimals; Order decimals and fractions; Simplify expressions using the order of operations; Find the circumference and area of circles

1. Learning objectives

Learning objectives

Learning objectives

  • Convert fractions to decimals
  • Order decimals and fractions
  • Simplify expressions using the order of operations
  • Find the circumference and area of circles

2. Convert Fractions to Decimals

Convert Fractions to Decimals

In Decimals, we learned to convert decimals to fractions. Now we will do the reverse—convert fractions to decimals. Remember that the fraction bar indicates division. So 45\frac{4}{5} can be written 4÷54\mathrm{÷}5 or 54.54. This means that we can convert a fraction to a decimal by treating it as a division problem.

To convert a fraction to a decimal, divide the numerator of the fraction by the denominator of the fraction.

3. Example 5.28

Example 5.28

Example 5.28

Write the fraction 34\frac{3}{4} as a decimal.

Solution

  1. Rewrite the fraction as division. Set 34=3.00÷4\frac{3}{4}=3.00\div4, keeping a decimal point in the dividend so the place values are explicit. The displayed long-division setup shows 3.003.00 divided by 44 with the quotient placed above the division line.
  2. Perform the first decimal-place step. Bring down one zero so 3030 tenths are divided by 44, obtaining 77 tenths with remainder 22 tenths. Thus the first digit after the decimal point is 77.
  3. Check the remaining places. Regroup the 22 remaining tenths as 2020 hundredths, and divide 20÷4=520\div4=5 with no remainder, so the quotient terminates after two decimal places.
  4. State the decimal result. The long division shown with 2828 above 2020, then 2020 above 00, agrees with the result 34=0.75\frac{3}{4}=0.75.

Takeaway: Writing the dividend with a decimal point makes the place-value steps in the division visible and confirms the quotient.

4. Example 5.29

Example 5.29

Example 5.29

Write the fraction −72-\frac{7}{2} as a decimal.

Solution

  1. Separate the sign from the fraction. Rewrite −7/2-7/2 as (−1)(7/2)(-1)(7/2), so the magnitude can be found first and the negative sign applied afterward.
  2. Divide to find the magnitude. Compute 7.0÷2.0=3.57.0\div2.0=3.5; the displayed long division first gives 7÷2=37\div2=3 with remainder 11, then brings down the zero so 10÷2=510\div2=5 with no remainder.
  3. Apply the negative sign. Since the quotient 3.53.5 is positive, multiplying by −1-1 gives −3.5-3.5.
  4. State the decimal result. The result is −7/2=−3.5-7/2=-3.5, which differs from the positive quotient shown in the division picture because the original fraction carries a negative sign.

Takeaway: Find the positive quotient by long division and then use the external negative sign to determine the answer's direction.

5. Repeating Decimals

Repeating Decimals

So far, in all the examples converting fractions to decimals the division resulted in a remainder of zero. This is not always the case. Let’s see what happens when we convert the fraction 43\frac{4}{3} to a decimal. First, notice that 43\frac{4}{3} is an improper fraction. Its value is greater than 1.1. The equivalent decimal will also be greater than 1.1.

We divide 44 by 3.3.

No matter how many more zeros we write, there will always be a remainder of 1,1, and the threes in the quotient will go on forever. The number 1.333…\mathrm{1.333…} is called a repeating decimal. Remember that the “…” means that the pattern repeats.

Definition · Repeating Decimal

A repeating decimal is a decimal in which the last digit or group of digits repeats endlessly.

How do you know how many ‘repeats’ to write? Instead of writing 1.333…1.333\ldots we use a shorthand notation by placing a line over the digits that repeat. The repeating decimal 1.333…1.333\ldots is written 1.3−.1.\overset{-}{3}. The line above the 33 tells you that the 33 repeats endlessly. So 1.333…=1.3−\mathrm{1.333…}=1.\overset{-}{3}

For other decimals, two or more digits might repeat. Table 5.5 shows some more examples of repeating decimals.

1.333…=1.3−\mathrm{1.333…}=1.\overset{-}{3}33 is the repeating digit
4.1666…=4.16−\mathrm{4.1666…}=4.1\overset{-}{6}66 is the repeating digit
4.161616…=4.16−−−\mathrm{4.161616…}=4.\overset{---}{16}1616 is the repeating block
0.271271271…=0.271−−−−−−\mathrm{0.271271271…}=0.\overset{\mathrm{------}}{271}271271 is the repeating block

Table

5.5

6. Example 5.30

Example 5.30

Example 5.30

Write 4322\frac{43}{22} as a decimal.

Solution

  1. Begin the long division. Dividing 4343 by 2222 gives 11 with remainder 2121, so the whole-number part of the quotient is 11.
  2. Find the tenths digit. The remainder 2121 is ten times 210210, and 210÷22=9210\div 22=9 with remainder 1212, so the first decimal digit is 99.
  3. Continue the quotient. The remainder 1212 is ten times 120120, and 120÷22=5120\div 22=5 with remainder 1010, giving the next digit 55.
  4. Detect the repeating cycle. Multiplying the remainder 1010 by ten again gives 100100, and 100÷22=4100\div 22=4 with remainder 1212, which repeats the earlier remainder.
  5. Write the repeating decimal. The repeating block is 5454, so 4322=1.954‾\frac{43}{22}=1.9\overline{54}.

Takeaway: Long division repeats after the remainder 1212 returns, producing the block 5454 in 1.954‾1.9\overline{54}.

It is useful to convert between fractions and decimals when we need to add or subtract numbers in different forms. To add a fraction and a decimal, for example, we would need to either convert the fraction to a decimal or the decimal to a fraction.

7. Example 5.31

Example 5.31

Example 5.31

Simplify: 78+6.4.\frac{7}{8}+6.4.

Solution

  1. Convert the fraction to a decimal. Divide 77 by 88 using long division. The displayed work shows 70÷8=870÷8=8 with remainder 66, then 60÷8=760÷8=7 with remainder 44, and finally 40÷8=540÷8=5 with remainder 00, confirming that 7/8=0.8757/8=0.875.
  2. Align the decimal places. Rewrite the addition as 0.875+6.4000.875+6.400, so the decimal points and the ones, tenths, and hundredths columns line up exactly.
  3. Add the fractional places. The thousandths column gives 5+0=55+0=5, the hundredths column gives 7+0=77+0=7, and the tenths column gives 8+4=128+4=12, so carry 11 to the ones column.
  4. Complete the addition. The ones column then gives 1+6=71+6=7, producing 6.400+0.875=7.2756.400+0.875=7.275.
  5. State the simplified result. The expression simplifies to 7/8+6.4=7.2757/8+6.4=7.275, agreeing with the quotient 0.8750.875 shown in the long-division picture.

Takeaway: Converting the fraction to a decimal and aligning place values makes the combined addition both visible and exact.

8. Order Decimals and Fractions

Order Decimals and Fractions

In Decimals, we compared two decimals and determined which was larger. To compare a decimal to a fraction, we will first convert the fraction to a decimal and then compare the decimals.

9. Example 5.32

Example 5.32

Example 5.32

Order 38__0.4\frac{3}{8}\mathrm{\_\_}0.4 using << or >.\mathrm{>.}

Solution

  1. Convert the fraction to a decimal. Since 88 has eight equal parts in one whole, 38=0.375\frac{3}{8}=0.375.
  2. Use a common form. The comparison becomes 0.375<0.40.375<0.4 after rewriting 0.40.4 as 0.4000.400 if desired.
  3. Compare the tenths digits. Both numbers have tenths digit 33, so the hundredths digits must be compared next.
  4. Compare the hundredths digits. The hundredths digit 77 in 0.3750.375 is less than the hundredths digit 00 in 0.4000.400.
  5. Restore the original fraction. The ordered statement is therefore 38<0.4\frac{3}{8}<0.4.

Takeaway: Converting 38\frac{3}{8} to 0.3750.375 shows that it is less than 0.40.4 because 375375 is less than 400400.

When ordering negative numbers, remember that larger numbers are to the right on the number line and any positive number is greater than any negative number.

10. Example 5.33

Example 5.33

Example 5.33

Order −0.5___−34-0.5\mathrm{\_\_\_}-\frac{3}{4} using << or >.\mathrm{>.}

Solution

  1. Convert the negative fraction. The value −34-\frac{3}{4} is equivalent to −0.75-0.75, so compare −0.5-0.5 with −0.75-0.75.
  2. Compare their distances from zero. The first number is 0.50.5 from zero, while the second is 0.750.75 from zero.
  3. Apply the negative-number rule. The negative number farther from zero is smaller, so −0.75<−0.5-0.75<-0.5.
  4. Check with a number line. The point for −0.5-0.5 lies to the right of the point for −0.75-0.75, confirming the ordering.
  5. Restore the original fraction. The required inequality is −0.5>−34-0.5>-\frac{3}{4}.

Takeaway: Because −0.5-0.5 is closer to zero than −0.75-0.75, it lies farther right and satisfies −0.5>−34-0.5>-\frac{3}{4}.

11. Example 5.34

Example 5.34

Example 5.34

Write the numbers 1320,0.61,1116\frac{13}{20},0.61,\frac{11}{16} in order from smallest to largest.

Solution

  1. Convert the first fraction. Dividing 1313 by 2020 gives 1320=0.65\frac{13}{20}=0.65, so the three values are now 0.650.65, 0.610.61, and 0.68750.6875.
  2. Convert the second fraction. Dividing 1111 by 1616 gives 1116=0.6875\frac{11}{16}=0.6875, allowing every value to be compared by place value.
  3. Find the smallest value. The number 0.610.61 is less than both 0.650.65 and 0.68750.6875, so it comes first.
  4. Find the largest value. Comparing 650650 with 68756875 in thousandths shows that 0.68750.6875 is greater than 0.650.65.
  5. Restore the original forms. The order from smallest to largest is 0.61<1320<11160.61<\frac{13}{20}<\frac{11}{16}.

Takeaway: The decimal equivalents 0.650.65 and 0.68750.6875 establish the order 0.61<1320<11160.61<\frac{13}{20}<\frac{11}{16}.

12. Simplify Expressions Using the Order of Operations

Simplify Expressions Using the Order of Operations

The order of operations introduced in Use the Language of Algebra also applies to decimals. Do you remember what the phrase “Please excuse my dear Aunt Sally” stands for?

13. Example 5.35

Example 5.35

Example 5.35

Simplify the expressions:

  1. ⓐ  7(18.3−21.7)\,7(18.3-21.7)
  2. ⓑ  23(8.3−3.8)\,\frac{2}{3}(8.3-3.8)

Solution

  1. Simplify the first parenthesis. Subtracting inside 7(18.3−21.7)7(18.3-21.7) gives 18.3−21.7=−3.418.3-21.7=-3.4.
  2. Multiply the first result. The expression becomes 7(−3.4)=−23.87(-3.4)=-23.8, since multiplying a positive number by a negative number gives a negative product.
  3. Simplify the second parenthesis. Subtracting inside 23(8.3−3.8)\frac{2}{3}(8.3-3.8) gives 8.3−3.8=4.58.3-3.8=4.5.
  4. Write the decimal as a fraction. The second expression becomes 23(4.51)=23(92)\frac{2}{3}\left(\frac{4.5}{1}\right)=\frac{2}{3}\left(\frac{9}{2}\right).
  5. Multiply and simplify. Canceling common factors gives 23⋅92=93=3\frac{2}{3}\cdot\frac{9}{2}=\frac{9}{3}=3.

Takeaway: Evaluating each parenthesis first gives the two distinct results −23.8-23.8 and 33 for the expressions.

14. Example 5.36

Example 5.36

Example 5.36

Simplify each expression:

  1. ⓐ  6÷0.6+(0.2)4−(0.1)2\,6\mathrm{÷}0.6+(0.2)4-{(0.1)}^{2}
  2. ⓑ  (110)2+(3.5)(0.9)\,{(\frac{1}{10})}^{2}+(3.5)(0.9)

Solution

  1. Square the first exponent. In 6÷0.6+(0.2)4−(0.1)26\div0.6+(0.2)4-(0.1)^2, the square (0.1)2(0.1)^2 equals 0.010.01.
  2. Divide and multiply. The expression becomes 10+(0.2)4−0.0110+(0.2)4-0.01, and the product (0.2)4(0.2)4 equals 0.80.8.
  3. Finish the first expression. Adding and subtracting from left to right gives 10+0.8−0.01=10.7910+0.8-0.01=10.79.
  4. Simplify the second expression. The square (110)2(\frac{1}{10})^2 is 1100=0.01\frac{1}{100}=0.01, and the product (3.5)(0.9)(3.5)(0.9) equals 3.153.15.
  5. Add the second expression. Its value is 0.01+3.15=3.160.01+3.15=3.16, so the two results are 10.7910.79 and 3.163.16.

Takeaway: Applying powers, then multiplication and division, and finally addition and subtraction produces 10.7910.79 and 3.163.16.

15. Find the Circumference and Area of Circles

Find the Circumference and Area of Circles

The properties of circles have been studied for over 2,0002,000 years. All circles have exactly the same shape, but their sizes are affected by the length of the radius, a line segment from the center to any point on the circle. A line segment that passes through a circle’s center connecting two points on the circle is called a diameter. The diameter is twice as long as the radius. See Figure 5.6.

The size of a circle can be measured in two ways. The distance around a circle is called its circumference.

Archimedes discovered that for circles of all different sizes, dividing the circumference by the diameter always gives the same number. The value of this number is pi, symbolized by Greek letter π\pi (pronounced pie). However, the exact value of π\pi cannot be calculated since the decimal never ends or repeats (we will learn more about numbers like this in The Properties of Real Numbers.)

If we want the exact circumference or area of a circle, we leave the symbol π\pi in the answer. We can get an approximate answer by substituting 3.143.14 as the value of π.\pi{}. We use the symbol ≈\approx to show that the result is approximate, not exact.

r isthelengthoftheradius.d isthelengthofthediameter.\begin{array}{l} r\,\mathrm{is the length of the radius.} \\ d\,\mathrm{is the length of the diameter.} \\ \end{array}
Thecircumferenceis 2πr.C=2πrTheareais πr2.A= πr2\begin{array}{lccl} \mathrm{The circumference is}\,2\pi{}r. & & & C=2\pi{}r \\ \mathrm{The area is}\,\pi{}{r}^{2}. & & & A=\,\pi{}{r}^{2} \\ \end{array}

Since the diameter is twice the radius, another way to find the circumference is to use the formula C= πd.C=\,\pi{}d.

Suppose we want to find the exact area of a circle of radius 1010 inches. To calculate the area, we would evaluate the formula for the area when r=10r=10 inches and leave the answer in terms of π.\mathrm{π.}

A= πr2A= π(102)A=π⋅100\begin{array}{l} A=\,\pi{}{r}^{2} \\ A=\,\pi{}({10}^{2}) \\ A=\pi\cdot{}100 \\ \end{array}

We write π\pi after the 100.100. So the exact value of the area is A=100πA=100\pi{} square inches.

To approximate the area, we would substitute π≈3.14.\pi\approx{}3.14.

A=100π≈100⋅3.14≈314 squareinches\begin{array}{ccl} A & = & 100\pi{} \\ & \approx & 100\cdot{}3.14 \\ & \approx & 314\,\mathrm{square inches} \\ \end{array}

Remember to use square units, such as square inches, when you calculate the area.

16. Example 5.37

Example 5.37

Example 5.37

A circle has radius 1010 centimeters. Approximate its ⓐ circumference and ⓑ area.

Solution

  1. Choose the circumference formula. For a radius of 1010 centimeters, the circumference is found with C=2πrC=2\pi r.
  2. Substitute the given values. Using π≈3.14\pi\approx3.14 and r=10r=10 gives C≈2(3.14)(10)C\approx2(3.14)(10) centimeters.
  3. Multiply the factors. Since 2(3.14)=6.282(3.14)=6.28 and 6.28(10)=62.86.28(10)=62.8, the circumference is approximately 62.862.8 centimeters.
  4. Choose the area formula. The area is found with A=πr2A=\pi r^2, so substitute the values to obtain A≈(3.14)(10)2A\approx(3.14)(10)^2.
  5. Evaluate the area. Squaring the radius gives 100100, and 3.14(100)=3143.14(100)=314, so the area is approximately 314314 square centimeters.

Takeaway: With radius 1010 and π≈3.14\pi\approx3.14, the circle's measurements are 62.862.8 centimeters around and 314314 square centimeters inside.

17. Example 5.38

Example 5.38

Example 5.38

A circle has radius 42.542.5 centimeters. Approximate its ⓐ circumference and ⓑ area.

Solution

  1. Choose the circumference formula. The formula is C=2πrC=2\pi r, and the radius is 42.542.5 centimeters.
  2. Substitute the given values. Using π≈3.14\pi\approx3.14 gives C≈2(3.14)(42.5)C\approx2(3.14)(42.5) centimeters.
  3. Multiply for the circumference. The product 2(3.14)(42.5)=266.92(3.14)(42.5)=266.9, so the circumference is approximately 266.9266.9 centimeters.
  4. Substitute into the area formula. The formula A=πr2A=\pi r^2 gives A≈(3.14)(42.5)2A\approx(3.14)(42.5)^2 square centimeters.
  5. Square and multiply. Since 42.52=1806.2542.5^2=1806.25 and 3.14(1806.25)=5671.6253.14(1806.25)=5671.625, the area is approximately 5671.6255671.625 square centimeters.

Takeaway: For radius 42.542.5 centimeters, the approximate circumference is 266.9266.9 centimeters and the area is 5671.6255671.625 square centimeters.

18. Approximate $\pi$ with a Fraction

Approximate π\pi with a Fraction

Convert the fraction 227\frac{22}{7} to a decimal. If you use your calculator, the decimal number will fill up the display and show 3.14285714.3.14285714. But if we round that number to two decimal places, we get 3.14,3.14, the decimal approximation of π.\pi{}. When we have a circle with radius given as a fraction, we can substitute 227\frac{22}{7} for π\pi instead of 3.14.3.14. And, since 227\frac{22}{7} is also an approximation of π,\pi{}, we will use the ≈\approx symbol to show we have an approximate value.

19. Example 5.39

Example 5.39

Example 5.39

A circle has radius 1415\frac{14}{15} meter. Approximate its ⓐ circumference and ⓑ area.

Solution

  1. Choose the circumference formula. With r=1415r=\frac{14}{15} meter, the circumference is C=2πrC=2\pi r.
  2. Substitute the fraction for pi. Using π≈227\pi\approx\frac{22}{7} gives C≈2(227)(1415)C\approx2(\frac{22}{7})(\frac{14}{15}) meters.
  3. Cancel and multiply. Canceling 1414 with 77 yields C≈2(22)15=8815C\approx\frac{2(22)}{15}=\frac{88}{15} meters.
  4. Substitute into the area formula. The area is A≈(227)(1415)2A\approx(\frac{22}{7})(\frac{14}{15})^2 square meters.
  5. Simplify the area product. Canceling gives A≈22(14)15(15)=616225A\approx\frac{22(14)}{15(15)}=\frac{616}{225} square meters.

Takeaway: Using π≈227\pi\approx\frac{22}{7} and radius 1415\frac{14}{15} meter gives 8815\frac{88}{15} meters of circumference and 616225\frac{616}{225} square meters of area.

20. Section 5.3 Exercises

Section 5.3 Exercises

Section 5.3 Exercises

Convert Fractions to Decimals

In the following exercises, convert each fraction to a decimal.

In the following exercises, simplify the expression.

Order Decimals and Fractions

In the following exercises, order each pair of numbers, using << or >.\mathrm{>.}

In the following exercises, write each set of numbers in order from least to greatest.

Simplify Expressions Using the Order of Operations

In the following exercises, simplify.

Mixed Practice

In the following exercises, simplify. Give the answer as a decimal.

Find the Circumference and Area of Circles

In the following exercises, approximate the ⓐ circumference and ⓑ area of each circle. If measurements are given in fractions, leave answers in fraction form.

Everyday Math

Writing Exercises

21. Self Check

Self Check

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ What does this checklist tell you about your mastery of this section? What steps will you take to improve?

22. Practice 1

  1. Write the fraction as a decimal: −94.-\frac{9}{4}.
  1. Write the fraction as a decimal: −112.-\frac{11}{2}.
  1. Write as a decimal: 2711.\frac{27}{11}.

23. Practice 2

  1. Write as a decimal: 5122.\frac{51}{22}.
  1. Order each of the following pairs of numbers, using << or >.\mathrm{>.}

1720__0.82\frac{17}{20}\mathrm{\_\_}0.82

  1. Order each of the following pairs of numbers, using << or >.\mathrm{>.}

34__0.785\frac{3}{4}\mathrm{\_\_}0.785

24. Practice 3

  1. Order each of the following pairs of numbers, using << or >:\mathrm{>:}

−58__−0.58-\frac{5}{8}\mathrm{\_\_}-0.58

  1. Order each of the following pairs of numbers, using << or >:\mathrm{>:}

−0.53__−1120-0.53\mathrm{\_\_}-\frac{11}{20}

  1. Write each set of numbers in order from smallest to largest: 78,45,0.82.\frac{7}{8},\frac{4}{5},0.82.

25. Practice 4

  1. Write each set of numbers in order from smallest to largest: 0.835,1316,34.0.835,\frac{13}{16},\frac{3}{4}.
  1. Simplify: ⓐ  8(14.6−37.5)\,8(14.6-37.5) ⓑ  35(9.6−2.1).\,\frac{3}{5}(9.6-2.1).
  1. Simplify: ⓐ  25(25.69−56.74)\,25(25.69-56.74) ⓑ  27(11.9−4.2).\,\frac{2}{7}(11.9-4.2).

26. Practice 5

  1. A circle has radius 5050 inches. Approximate its ⓐ circumference and ⓑ area.
  1. A circle has radius 100100 feet. Approximate its ⓐ circumference and ⓑ area.
  1. A circle has radius 51.851.8 centimeters. Approximate its ⓐ circumference and ⓑ area.

27. Practice 6

  1. A circle has radius 26.426.4 meters. Approximate its ⓐ circumference and ⓑ area.
  1. A circle has radius 521\frac{5}{21} meters. Approximate its ⓐ circumference and ⓑ area.
  1. A circle has radius 1033\frac{10}{33} inches. Approximate its ⓐ circumference and ⓑ area.

28. Practice 7

  1. −38-\frac{3}{8}
  1. −31025-\frac{310}{25}
  1. 59\frac{5}{9}

29. Practice 8

  1. 1511\frac{15}{11}
  1. 15111\frac{15}{111}
  1. 18___0.8\frac{1}{8}\mathrm{\_\_\_}0.8

30. Practice 9

  1. 25___0.25\frac{2}{5}\mathrm{\_\_\_}\mathrm{0.25}
  1. 0.725 ___ 340.725\,\mathrm{\_\_\_}\,\frac{3}{4}
  1. 0.66 ___ 230.66\,\mathrm{\_\_\_}\,\frac{2}{3}

31. Practice 10

  1. −0.75___−45-0.75\mathrm{\_\_\_}-\frac{4}{5}
  1. −34___−0.925-\frac{3}{4}\mathrm{\_\_\_}-0.925
  1. 35,916,0.55\frac{3}{5},\frac{9}{16},0.55

32. Practice 11

  1. 0.702,1320,580.702,\frac{13}{20},\frac{5}{8}
  1. −0.3,−13,−720-0.3,-\frac{1}{3},-\frac{7}{20}
  1. −34,−79,−0.7-\frac{3}{4},-\frac{7}{9},-0.7

33. Practice 12

  1. 10(25.1−43.8)10(25.1-43.8)
  1. −910⋅815+0.25-\frac{9}{10}\cdot\frac{8}{15}+0.25
  1. 314−6.53\frac{1}{4}-6.5

34. Practice 13

  1. 3.6(98−2.72)3.6(\frac{9}{8}-2.72)
  1. radius=5in.\mathrm{radius}=\mathrm{5 in.}
  1. radius=9ft.\mathrm{radius}=\mathrm{9 ft.}

35. Practice 14

  1. radius=46cm\mathrm{radius}=\mathrm{46 cm}
  1. radius=18.6m\mathrm{radius}=\mathrm{18.6 m}
  1. radius=710 mile\mathrm{radius}=\frac{7}{10}\,\mathrm{mile}

36. Practice 15

  1. radius=38 yard\mathrm{radius}=\frac{3}{8}\,\mathrm{yard}
  1. diameter=56 m\mathrm{diameter}=\frac{5}{6}\,m
  1. diameter=34 m\mathrm{diameter}=\frac{3}{4}\,m

37. Practice 16

  1. Kelly wants to buy a pair of boots that are on sale for 23\frac{2}{3} of the original price. The original price of the boots is $84.99.\text{\textdollar 84.99}. What is the sale price of the shoes?
  1. Is it easier for you to convert a decimal to a fraction or a fraction to a decimal? Explain.

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