Prealgebra 2e · free preview

9.2 Solve Money Applications

Learning objectives: Solve coin word problems; Solve ticket and stamp word problems

1. Learning objectives

Learning objectives

Learning objectives

  • Solve coin word problems
  • Solve ticket and stamp word problems

2. Solve Coin Word Problems

Solve Coin Word Problems

Imagine taking a handful of coins from your pocket or purse and placing them on your desk. How would you determine the value of that pile of coins?

If you can form a step-by-step plan for finding the total value of the coins, it will help you as you begin solving coin word problems.

One way to bring some order to the mess of coins would be to separate the coins into stacks according to their value. Quarters would go with quarters, dimes with dimes, nickels with nickels, and so on. To get the total value of all the coins, you would add the total value of each pile.

How would you determine the value of each pile? Think about the dime pile—how much is it worth? If you count the number of dimes, you'll know how many you have—the number of dimes.

But this does not tell you the value of all the dimes. Say you counted 1717 dimes, how much are they worth? Each dime is worth $0.10\text{\textdollar 0.10}—that is the value of one dime. To find the total value of the pile of 1717 dimes, multiply 1717 by $0.10\text{\textdollar 0.10} to get $1.70.\text{\textdollar 1.70}. This is the total value of all 1717 dimes.

17⋅$0.10=$1.70number⋅value=totalvalue\begin{array}{c} 17\cdot\text{\textdollar 0.10}=\text{\textdollar 1.70} \\ \mathrm{number}\cdot\mathrm{value}=\mathrm{total value} \\ \end{array}

For coins of the same type, the total value can be found as follows:

number⋅value=totalvalue\mathrm{number}\cdot\mathrm{value}=\mathrm{total value}

where number is the number of coins, value is the value of each coin, and total value is the total value of all the coins.

You could continue this process for each type of coin, and then you would know the total value of each type of coin. To get the total value of all the coins, add the total value of each type of coin.

Let's look at a specific case. Suppose there are 1414 quarters, 1717 dimes, 2121 nickels, and 3939 pennies. We'll make a table to organize the information – the type of coin, the number of each, and the value.

TypeNumber\mathrm{Number}Value(\textdollar)\mathrm{Value (\textdollar )}TotalValue($)\mathrm{Total Value (\$)}
Quarters14140.250.253.503.50
Dimes17170.100.101.701.70
Nickels21210.050.051.051.05
Pennies39390.010.010.390.39
6.646.64

Table

9.1

The total value of all the coins is $6.64.\text{\textdollar 6.64}. Notice how Table 9.1 helped us organize all the information. Let's see how this method is used to solve a coin word problem.

3. Example 9.11

Example 9.11

Example 9.11

Adalberto has $2.25\text{\textdollar 2.25} in dimes and nickels in his pocket. He has nine more nickels than dimes. How many of each type of coin does he have?

Solution

  1. Express both coin counts. Let dd be the number of dimes. Since Adalberto has nine more nickels than dimes, the number of nickels is d+9d+9.
  2. Write the total-value equation. The dimes contribute 0.10d0.10d dollars and the nickels contribute 0.05(d+9)0.05(d+9) dollars, so add them to obtain 0.10d+0.05(d+9)=2.250.10d+0.05(d+9)=2.25.
  3. Solve the equation. Distributing gives 0.10d+0.05d+0.45=2.250.10d+0.05d+0.45=2.25, hence 0.15d=1.800.15d=1.80 and d=12d=12. The number of nickels is d+9=21d+9=21.
  4. Check both conditions. Twelve dimes are worth 12(0.10)=1.2012(0.10)=1.20 dollars, and twenty-one nickels are worth 21(0.05)=1.0521(0.05)=1.05 dollars. Their total is 2.252.25 dollars, and the nickel count exceeds the dime count by 99.
  5. State the coin counts. Adalberto has 1212 dimes and 2121 nickels.

Takeaway: Writing the number of nickels as d+9d+9 gives 0.10d+0.05(d+9)=2.250.10d+0.05(d+9)=2.25, so Adalberto has 1212 dimes and 2121 nickels.

Solve a coin word problem.

  1. Step 1. Read the problem. Make sure you understand all the words and ideas, and create a table to organize the information.
  2. Step 2. Identify what you are looking for.
  3. Step 3. Name what you are looking for. Choose a variable to represent that quantity. Use variable expressions to represent the number of each type of coin and write them in the table. Multiply the number times the value to get the total value of each type of coin.
  4. Step 4. Translate into an equation. Write the equation by adding the total values of all the types of coins.
  5. Step 5. Solve the equation using good algebra techniques.
  6. Step 6. Check the answer in the problem and make sure it makes sense.
  7. Step 7. Answer the question with a complete sentence.

You may find it helpful to put all the numbers into the table to make sure they check.

TypeNumberValue ($)Total Value

Table 9.2

4. Example 9.12

Example 9.12

Example 9.12

Maria has $2.43\text{\textdollar 2.43} in quarters and pennies in her wallet. She has twice as many pennies as quarters. How many coins of each type does she have?

Solution

  1. Express both coin counts. Let qq be the number of quarters. Maria has twice as many pennies, so the number of pennies is 2q2q.
  2. Write the total-value equation. The quarter value is 0.25q0.25q dollars and the penny value is 0.01(2q)0.01(2q) dollars, giving 0.25q+0.01(2q)=2.430.25q+0.01(2q)=2.43.
  3. Combine and solve. The equation becomes 0.25q+0.02q=2.430.25q+0.02q=2.43, so 0.27q=2.430.27q=2.43 and q=9q=9. The number of pennies is 2q=182q=18.
  4. Check the money and the ratio. Nine quarters are worth 9(0.25)=2.259(0.25)=2.25 dollars and eighteen pennies are worth 18(0.01)=0.1818(0.01)=0.18 dollars. The total is 2.432.43 dollars, and 18=2(9)18=2(9).
  5. State the coin counts. Maria has 99 quarters and 1818 pennies.

Takeaway: Writing the number of pennies as 2q2q gives 0.25q+0.01(2q)=2.430.25q+0.01(2q)=2.43, so Maria has 99 quarters and 1818 pennies.

5. Example 9.13

Example 9.13

Example 9.13

Danny has $2.14\text{\textdollar 2.14} worth of pennies and nickels in his piggy bank. The number of nickels is two more than ten times the number of pennies. How many nickels and how many pennies does Danny have?

Solution

  1. Express the related coin counts. Let pp be the number of pennies. The number of nickels is ten times the penny count plus two, so it is 10p+210p+2.
  2. Write the total-value equation. The pennies contribute 0.01p0.01p dollars and the nickels contribute 0.05(10p+2)0.05(10p+2) dollars. Thus 0.01p+0.05(10p+2)=2.140.01p+0.05(10p+2)=2.14.
  3. Combine and solve. Distributing gives 0.01p+0.50p+0.10=2.140.01p+0.50p+0.10=2.14, hence 0.51p=2.040.51p=2.04 and p=4p=4. The number of nickels is 10(4)+2=4210(4)+2=42.
  4. Check the money and relationship. Four pennies are worth 0.040.04 dollars and forty-two nickels are worth 2.102.10 dollars, totaling 2.142.14 dollars. Also, 42=10(4)+242=10(4)+2, so the stated relationship holds.
  5. State the coin counts. Danny has 44 pennies and 4242 nickels.

Takeaway: Writing the number of nickels as 10p+210p+2 gives 0.01p+0.05(10p+2)=2.140.01p+0.05(10p+2)=2.14, so Danny has 44 pennies and 4242 nickels.

6. Solve Ticket and Stamp Word Problems

Solve Ticket and Stamp Word Problems

The strategies we used for coin problems can be easily applied to some other kinds of problems too. Problems involving tickets or stamps are very similar to coin problems, for example. Like coins, tickets and stamps have different values; so we can organize the information in tables much like we did for coin problems.

7. Example 9.14

Example 9.14

Example 9.14

At a school concert, the total value of tickets sold was $1,506.\text{\textdollar 1,506}. Student tickets sold for $6\text{\textdollar 6} each and adult tickets sold for $9\text{\textdollar 9} each. The number of adult tickets sold was 55 less than three times the number of student tickets sold. How many student tickets and how many adult tickets were sold?

Solution

  1. Express the ticket counts. Let ss be the number of student tickets. The number of adult tickets is five less than three times ss, so it is 3s−53s-5.
  2. Write the total-value equation. Student tickets contribute 6s6s dollars and adult tickets contribute 9(3s−5)9(3s-5) dollars, so 6s+9(3s−5)=15066s+9(3s-5)=1506.
  3. Solve for the student count. Distributing and combining gives 6s+27s−45=15066s+27s-45=1506, hence 33s=155133s=1551 and s=47s=47. The adult count is 3(47)−5=1363(47)-5=136.
  4. Check the ticket values. The student tickets are worth 47(6)=28247(6)=282 dollars and the adult tickets are worth 136(9)=1224136(9)=1224 dollars. Their total is 15061506 dollars, and 136=3(47)−5136=3(47)-5.
  5. State the ticket counts. They sold 4747 student tickets and 136136 adult tickets.

Takeaway: Writing the number of adult tickets as 3s−53s-5 gives 6s+9(3s−5)=15066s+9(3s-5)=1506, so 4747 student tickets and 136136 adult tickets were sold.

Now we'll do one where we fill in the table all at once.

8. Example 9.15

Example 9.15

Example 9.15

Monica paid $10.44\text{\textdollar 10.44} for stamps she needed to mail the invitations to her sister's baby shower. The number of 49−cent\mathrm{49-cent} stamps was four more than twice the number of 8−cent\mathrm{8-cent} stamps. How many 49−cent\mathrm{49-cent} stamps and how many 8−cent\mathrm{8-cent} stamps did Monica buy?

Solution

  1. Express both stamp counts. Let xx be the number of 88-cent stamps. The number of 4949-cent stamps is four more than twice xx, so it is 2x+42x+4.
  2. Write the total-cost equation. The 88-cent stamps cost 0.08x0.08x dollars and the 4949-cent stamps cost 0.49(2x+4)0.49(2x+4) dollars, giving 0.49(2x+4)+0.08x=10.440.49(2x+4)+0.08x=10.44.
  3. Solve for the smaller count. Expanding gives 0.98x+1.96+0.08x=10.440.98x+1.96+0.08x=10.44, so 1.06x=8.481.06x=8.48 and x=8x=8. The other count is 2(8)+4=202(8)+4=20.
  4. Check the total cost. Eight 88-cent stamps cost 0.640.64 dollars and twenty 4949-cent stamps cost 9.809.80 dollars. The sum is 10.4410.44 dollars, and 20=2(8)+420=2(8)+4.
  5. State the stamp counts. Monica bought 88 eight-cent stamps and 2020 forty-nine-cent stamps.

Takeaway: Writing the number of 49-cent stamps as 2x+42x+4 gives 0.49(2x+4)+0.08x=10.440.49(2x+4)+0.08x=10.44, so Monica bought 2020 expensive stamps and 88 eight-cent stamps.

9. Section 9.2 Exercises

Section 9.2 Exercises

Section 9.2 Exercises

Solve Coin Word Problems

In the following exercises, solve the coin word problems.

Solve Ticket and Stamp Word Problems

In the following exercises, solve the ticket and stamp word problems.

Everyday Math

Writing Exercises

10. Self Check

Self Check

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ After reviewing this checklist, what will you do to become confident for all objectives?

11. Practice 1

  1. Michaela has $2.05\text{\textdollar 2.05} in dimes and nickels in her change purse. She has seven more dimes than nickels. How many coins of each type does she have?
  1. Liliana has $2.10\text{\textdollar 2.10} in nickels and quarters in her backpack. She has 1212 more nickels than quarters. How many coins of each type does she have?

12. Practice 2

  1. Sumanta has $4.20\text{\textdollar 4.20} in nickels and dimes in her desk drawer. She has twice as many nickels as dimes. How many coins of each type does she have?
  1. Alison has three times as many dimes as quarters in her purse. She has $9.35\text{\textdollar 9.35} altogether. How many coins of each type does she have?

13. Practice 3

  1. Jesse has $6.55\text{\textdollar 6.55} worth of quarters and nickels in his pocket. The number of nickels is five more than two times the number of quarters. How many nickels and how many quarters does Jesse have?
  1. Elaine has $7.00\text{\textdollar 7.00} in dimes and nickels in her coin jar. The number of dimes that Elaine has is seven less than three times the number of nickels. How many of each coin does Elaine have?

14. Practice 4

  1. The first day of a water polo tournament, the total value of tickets sold was $17,610.\text{\textdollar 17,610}. One-day passes sold for $20\text{\textdollar 20} and tournament passes sold for $30.\text{\textdollar 30}. The number of tournament passes sold was 3737 more than the number of day passes sold. How many day passes and how many tournament passes were sold?
  1. At the movie theater, the total value of tickets sold was $2,612.50.\text{\textdollar 2,612.50}. Adult tickets sold for $10\text{\textdollar 10} each and senior/child tickets sold for $7.50\text{\textdollar 7.50} each. The number of senior/child tickets sold was 2525 less than twice the number of adult tickets sold. How many senior/child tickets and how many adult tickets were sold?

15. Practice 5

  1. Eric paid $16.64\text{\textdollar 16.64} for stamps so he could mail thank you notes for his wedding gifts. The number of 49−cent\mathrm{49-cent} stamps was eight more than twice the number of 8−cent\mathrm{8-cent} stamps. How many 49−cent\mathrm{49-cent} stamps and how many 8−cent\mathrm{8-cent} stamps did Eric buy?
  1. Kailee paid $14.84\text{\textdollar 14.84} for stamps. The number of 49−cent\mathrm{49-cent} stamps was four less than three times the number of 21−cent\mathrm{21-cent} stamps. How many 49−cent\mathrm{49-cent} stamps and how many 21−cent\mathrm{21-cent} stamps did Kailee buy?

16. Practice 6

  1. Jaime has $2.60\text{\textdollar 2.60} in dimes and nickels. The number of dimes is 1414 more than the number of nickels. How many of each coin does he have?
  1. Ngo has a collection of dimes and quarters with a total value of $3.50.\text{\textdollar 3.50}. The number of dimes is 77 more than the number of quarters. How many of each coin does he have?

17. Practice 7

  1. Carolyn has $2.55\text{\textdollar 2.55} in her purse in nickels and dimes. The number of nickels is 99 less than three times the number of dimes. Find the number of each type of coin.
  1. Chi has $11.30\text{\textdollar 11.30} in dimes and quarters. The number of dimes is 33 more than three times the number of quarters. How many dimes and nickels does Chi have?

18. Practice 8

  1. A cash box of $1\text{\textdollar 1} and $5\text{\textdollar 5} bills is worth $45.\text{\textdollar 45}. The number of $1\text{\textdollar 1} bills is 33 more than the number of $5\text{\textdollar 5} bills. How many of each bill does it contain?
  1. In a cash drawer there is $125\text{\textdollar 125} in $5\text{\textdollar 5} and $10\text{\textdollar 10} bills. The number of $10\text{\textdollar 10} bills is twice the number of $5\text{\textdollar 5} bills. How many of each are in the drawer?

19. Practice 9

  1. Mukul has $3.75\text{\textdollar 3.75} in quarters, dimes and nickels in his pocket. He has five more dimes than quarters and nine more nickels than quarters. How many of each coin are in his pocket?
  1. The play took in $550\text{\textdollar 550} one night. The number of 8adultticketswas8 adult tickets was 10lessthantwicethenumberof less than twice the number of \text{\textdollar 5}$ child tickets. How many of each ticket were sold?

20. Practice 10

  1. The movie theater took in $1,220\text{\textdollar 1,220} one Monday night. The number of $7\text{\textdollar 7} child tickets was ten more than twice the number of $9\text{\textdollar 9} adult tickets. How many of each were sold?
  1. Julie went to the post office and bought both $0.49\text{\textdollar 0.49} stamps and $0.34\text{\textdollar 0.34} postcards for her office's bills She spent $62.60.\text{\textdollar 62.60}. The number of stamps was 2020 more than twice the number of postcards. How many of each did she buy?

21. Practice 11

  1. Maria spent $16.80\text{\textdollar 16.80} at the post office. She bought three times as many $0.49\text{\textdollar 0.49} stamps as $0.21\text{\textdollar 0.21} stamps. How many of each did she buy?
  1. Hilda has $210\text{\textdollar 210} worth of $10\text{\textdollar 10} and $12\text{\textdollar 12} stock shares. The numbers of $10\text{\textdollar 10} shares is 55 more than twice the number of $12\text{\textdollar 12} shares. How many of each does she have?

22. Practice 12

  1. Parent Volunteer As the treasurer of her daughter's Girl Scout troop, Laney collected money for some girls and adults to go to a 3−day\mathrm{3-day} camp. Each girl paid $75\text{\textdollar 75} and each adult paid $30.\text{\textdollar 30}. The total amount of money collected for camp was $765.\text{\textdollar 765}. If the number of girls is three times the number of adults, how many girls and how many adults paid for camp?
  1. Suppose you have 66 quarters, 99 dimes, and 44 pennies. Explain how you find the total value of all the coins.

23. Practice 13

  1. In the table used to solve coin problems, one column is labeled “number” and another column is labeled ‘“value.” What is the difference between the number and the value?

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