Prealgebra 2e · free preview

9.3 Use Properties of Angles, Triangles, and the Pythagorean Theorem

Learning objectives: Use the properties of angles; Use the properties of triangles; Use the Pythagorean Theorem

1. Learning objectives

Learning objectives

Learning objectives

  • Use the properties of angles
  • Use the properties of triangles
  • Use the Pythagorean Theorem

So far in this chapter, we have focused on solving word problems, which are similar to many real-world applications of algebra. In the next few sections, we will apply our problem-solving strategies to some common geometry problems.

2. Use the Properties of Angles

Use the Properties of Angles

Are you familiar with the phrase ‘do a 180′?180\mathrm{'?} It means to turn so that you face the opposite direction. It comes from the fact that the measure of an angle that makes a straight line is 180180 degrees. See Figure 9.5.

An angle is formed by two rays that share a common endpoint. Each ray is called a side of the angle and the common endpoint is called the vertex. An angle is named by its vertex. In Figure 9.6, ∠A∠A is the angle with vertex at point A.A. The measure of ∠A∠A is written m∠A.m\mathrm{∠}A.

We measure angles in degrees, and use the symbol ∘^{\circ} to represent degrees. We use the abbreviation mm for the measure of an angle. So if ∠A∠A is 27∘,\mathrm{27^{\circ}}, we would write m∠A=27.m\mathrm{∠}A=27.

If the sum of the measures of two angles is 180∘,\mathrm{180^{\circ}}, then they are called supplementary angles. In Figure 9.7, each pair of angles is supplementary because their measures add to 180∘.\mathrm{180^{\circ}}. Each angle is the supplement of the other.

If the sum of the measures of two angles is 90∘,\mathrm{90^{\circ}}, then the angles are complementary angles. In Figure 9.8, each pair of angles is complementary, because their measures add to 90∘.\mathrm{90^{\circ}}. Each angle is the complement of the other.

If the sum of the measures of two angles is 180∘,\mathrm{180^{\circ}}, then the angles are supplementary.

If ∠A∠A and ∠B∠B are supplementary, then m∠A+m∠B=180∘.m∠A+m∠B=\mathrm{180^{\circ}.} If the sum of the measures of two angles is 90∘,\mathrm{90^{\circ}}, then the angles are complementary.

If ∠A∠A and ∠B∠B are complementary, then m∠A+m∠B=90∘.m∠A+m∠B=\mathrm{90^{\circ}.}

In this section and the next, you will be introduced to some common geometry formulas. We will adapt our Problem Solving Strategy for Geometry Applications. The geometry formula will name the variables and give us the equation to solve.

In addition, since these applications will all involve geometric shapes, it will be helpful to draw a figure and then label it with the information from the problem. We will include this step in the Problem Solving Strategy for Geometry Applications.

Use a Problem Solving Strategy for Geometry Applications.

  1. Step 1. Read the problem and make sure you understand all the words and ideas. Draw a figure and label it with the given information.
  2. Step 2. Identify what you are looking for.
  3. Step 3. Name what you are looking for and choose a variable to represent it.
  4. Step 4. Translate into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.
  5. Step 5. Solve the equation using good algebra techniques.
  6. Step 6. Check the answer in the problem and make sure it makes sense.
  7. Step 7. Answer the question with a complete sentence.

The next example will show how you can use the Problem Solving Strategy for Geometry Applications to answer questions about supplementary and complementary angles.

3. Example 9.16

Example 9.16

Example 9.16

An angle measures 40∘.\mathrm{40^{\circ}}. Find ⓐ its supplement, and ⓑ its complement.

Solution

  1. Find the supplement. A supplementary angle makes a total angle of 180circ180^{\\circ}. Let ss be the supplement of the 40circ40^{\\circ} angle, so s+40=180s+40=180. Subtracting 4040 gives s=140s=140. The figures show the straight-line diagram, this equation, and the check 140+40=180140+40=180.
  2. Find the complement. A complementary angle makes a total angle of 90circ90^{\\circ}. Let cc be the complement of the 40circ40^{\\circ} angle, so c+40=90c+40=90. Subtracting 4040 gives c=50c=50.
  3. Check and state both measures. The complement figures confirm that 50+40=9050+40=90, so ⓐ the supplement is 140circ140^{\\circ} and ⓑ the complement is 50circ50^{\\circ}.

Takeaway: Supplementary angles sum to 180circ180^{\\circ}, whereas complementary angles sum to 90circ90^{\\circ}.

Did you notice that the words complementary and supplementary are in alphabetical order just like 9090 and 180180 are in numerical order?

4. Example 9.17

Example 9.17

Example 9.17

Two angles are supplementary. The larger angle is 30∘\mathrm{30^{\circ}} more than the smaller angle. Find the measure of both angles.

Solution

  1. Express the angle measures. Let aa be the measure of the smaller angle in degrees. The larger angle measures a+30a+30 degrees, as the first figures show.
  2. Use the supplementary-angle property. The two angles satisfy a+(a+30)=180a+(a+30)=180. Combining like terms gives 2a+30=1802a+30=180, matching the figures that display the equation.
  3. Solve for the smaller angle. Subtracting 3030 gives 2a=1502a=150, and dividing by 22 gives a=75a=75. The larger angle is a+30=75+30=105a+30=75+30=105 degrees.
  4. Check the measures. The figures verify that 75+105=18075+105=180 and that the larger angle is 30circ30^{\\circ} greater. The measures of the angles are 75circ75^{\\circ} and 105circ105^{\\circ}.

Takeaway: For supplementary angles, use the 180circ180^{\\circ} sum to form the equation and then verify the stated difference.

5. Use the Properties of Triangles

Use the Properties of Triangles

What do you already know about triangles? Triangle have three sides and three angles. Triangles are named by their vertices. The triangle in Figure 9.9 is called ΔABC,\Delta{}ABC, read ‘triangle ABC\mathrm{ABC}’. We label each side with a lower case letter to match the upper case letter of the opposite vertex.

The three angles of a triangle are related in a special way. The sum of their measures is 180∘.\mathrm{180^{\circ}}.

m∠A+m∠B+m∠C=180∘m∠A+m∠B+m∠C=\mathrm{180^{\circ}}

For any ΔABC,\Delta{}ABC, the sum of the measures of the angles is 180∘.\mathrm{180^{\circ}}.

m∠A+m∠B+m∠C=180∘m∠A+m∠B+m∠C=\mathrm{180^{\circ}}

6. Example 9.18

Example 9.18

Example 9.18

The measures of two angles of a triangle are 55∘\mathrm{55^{\circ}} and 82∘.\mathrm{82^{\circ}}. Find the measure of the third angle.

Solution

  1. Write the angle-sum equation. Let xx be the measure in degrees of the third angle. The triangle-angle property gives 55+82+x=18055+82+x=180, which is shown in the figures with the triangle labeled 55circ55^{\\circ}, 82circ82^{\\circ}, and xx.
  2. Combine the known angles. Since 55+82=13755+82=137, the equation becomes 137+x=180137+x=180.
  3. Solve for the unknown angle. Subtracting 137137 from both sides gives x=43x=43.
  4. Check the angle sum. The figures verify 55+82+43=18055+82+43=180, so the measure of the third angle is 43circ43^{\\circ}.

Takeaway: The three interior angles of every triangle total 180circ180^{\\circ}, regardless of the triangle's shape.

7. Right Triangles

Right Triangles

Some triangles have special names. We will look first at the right triangle. A right triangle has one 90∘\mathrm{90^{\circ}} angle, which is often marked with the symbol shown in Figure 9.10.

If we know that a triangle is a right triangle, we know that one angle measures 90∘\mathrm{90^{\circ}} so we only need the measure of one of the other angles in order to determine the measure of the third angle.

8. Example 9.19

Example 9.19

Example 9.19

One angle of a right triangle measures 28∘.\mathrm{28^{\circ}}. What is the measure of the third angle?

Solution

  1. Identify all three angles. A right triangle has one 90circ90^{\\circ} angle, and another angle measures 28circ28^{\\circ}. Let xx be the third angle's measure in degrees, as the triangle diagram shows.
  2. Apply the triangle angle sum. The angles satisfy x+90+28=180x+90+28=180, and combining the known measures gives x+118=180x+118=180.
  3. Solve for the third angle. Subtracting 118118 from both sides gives x=62x=62. The figures display the equation and the result.
  4. Check the angle sum. Since 90+28+62=18090+28+62=180, the third angle measures 62circ62^{\\circ}.

Takeaway: In a right triangle, the two acute angles together measure 90circ90^{\\circ} because the full angle sum is 180circ180^{\\circ}.

In the examples so far, we could draw a figure and label it directly after reading the problem. In the next example, we will have to define one angle in terms of another. So we will wait to draw the figure until we write expressions for all the angles we are looking for.

9. Example 9.20

Example 9.20

Example 9.20

The measure of one angle of a right triangle is 20∘\mathrm{20^{\circ}} more than the measure of the smallest angle. Find the measures of all three angles.

Solution

  1. Express the acute angle measures. Let aa be the measure in degrees of the smallest angle. The other acute angle is a+20a+20 degrees, and the right angle is 90circ90^{\\circ}. The figures label all three angles in this way.
  2. Form the triangle angle equation. The sum of the angles gives a+(a+20)+90=180a+(a+20)+90=180. Combining like terms produces 2a+110=1802a+110=180, as shown in the figures.
  3. Solve for the smallest angle. Subtracting 110110 gives 2a=702a=70, and dividing by 22 gives a=35a=35. The second acute angle is 35+20=5535+20=55 degrees.
  4. Check the three measures. The figures verify that 35+55+90=18035+55+90=180. The angles measure 35circ35^{\\circ}, 55circ55^{\\circ}, and 90circ90^{\\circ}.

Takeaway: The two acute angles of a right triangle total 90circ90^{\\circ}, which provides a quick check on their measures.

10. Similar Triangles

Similar Triangles

When we use a map to plan a trip, a sketch to build a bookcase, or a pattern to sew a dress, we are working with similar figures. In geometry, if two figures have exactly the same shape but different sizes, we say they are similar figures. One is a scale model of the other. The corresponding sides of the two figures have the same ratio, and all their corresponding angles have the same measures.

The two triangles in Figure 9.11 are similar. Each side of ΔABC\Delta{}ABC is four times the length of the corresponding side of ΔXYZ\Delta{}XYZ and their corresponding angles have equal measures.

If two triangles are similar, then their corresponding angle measures are equal and their corresponding side lengths are in the same ratio.

The length of a side of a triangle may be referred to by its endpoints, two vertices of the triangle. For example, in ΔABC:\Delta{}ABC:

 thelength a canalsobewritten BCthelength b canalsobewritten ACthelength c canalsobewritten AB\,\begin{array}{l} \mathrm{the length}\,a\,\mathrm{can also be written}\,BC \\ \mathrm{the length}\,b\,\mathrm{can also be written}\,AC \\ \mathrm{the length}\,c\,\mathrm{can also be written}\,AB \\ \end{array}

We will often use this notation when we solve similar triangles because it will help us match up the corresponding side lengths.

11. Example 9.21

Example 9.21

Example 9.21

ΔABC\Delta{}ABC and ΔXYZ\Delta{}XYZ are similar triangles. The lengths of two sides of each triangle are shown. Find the lengths of the third side of each triangle.

Solution

  1. Set up corresponding-side proportions. From the similar triangles, the ratio of corresponding sides is frac43\\frac{4}{3}. For the larger triangle, the proportion is frac43=fraca4.5\\frac{4}{3}=\\frac{a}{4.5}; for the smaller triangle, it is frac43=frac3.2y\\frac{4}{3}=\\frac{3.2}{y}. The first figure displays these ratios.
  2. Solve for the larger missing side. Cross-multiplication gives 3a=4(4.5)=183a=4(4.5)=18, so a=6a=6. The second figure shows this calculation.
  3. Solve for the smaller missing side. Cross-multiplication gives 4y=3(3.2)=9.64y=3(3.2)=9.6, so y=2.4y=2.4.
  4. Check the proportions. The final figure verifies both cross-products: 4(4.5)=3(6)4(4.5)=3(6) and 4(2.4)=3(3.2)4(2.4)=3(3.2). The missing side lengths are 66 and 2.42.4.

Takeaway: In similar triangles, match corresponding sides before cross-multiplying a proportion for a missing length.

12. Use the Pythagorean Theorem

Use the Pythagorean Theorem

The Pythagorean Theorem is a special property of right triangles that has been used since ancient times. It is named after the Greek philosopher and mathematician Pythagoras who lived around 500500 BCE.

Remember that a right triangle has a 90∘\mathrm{90^{\circ}} angle, which we usually mark with a small square in the corner. The side of the triangle opposite the 90∘\mathrm{90^{\circ}} angle is called the hypotenuse, and the other two sides are called the legs. See Figure 9.12.

The Pythagorean Theorem tells how the lengths of the three sides of a right triangle relate to each other. It states that in any right triangle, the sum of the squares of the two legs equals the square of the hypotenuse.

In any right triangle ΔABC,\Delta{}ABC,

a2+b2=c2{a}^{2}+{b}^{2}={c}^{2}

where cc is the length of the hypotenuse aa and bb are the lengths of the legs.

To solve problems that use the Pythagorean Theorem, we will need to find square roots. In Simplify and Use Square Roots we introduced the notation m\sqrt{m} and defined it in this way:

If m=n2, then m=n for n≥0\mathrm{If}\,m={n}^{2},\,\mathrm{then}\,\sqrt{m}=n\,\mathrm{for}\,n\ge{}0

For example, we found that 25\sqrt{25} is 55 because 52=25.{5}^{2}=25.

We will use this definition of square roots to solve for the length of a side in a right triangle.

13. Example 9.22

Example 9.22

Example 9.22

Use the Pythagorean Theorem to find the length of the hypotenuse.

Solution

  1. Identify the side roles. The triangle has legs of lengths 33 and 44, and the hypotenuse is cc. The diagram shows the 33 - 44 - 55 right triangle.
  2. Apply the Pythagorean Theorem. The formula is a2+b2=c2a^2+b^2=c^2, so substituting gives 32+42=c23^2+4^2=c^2.
  3. Evaluate and solve. Squaring the legs gives 9+16=c29+16=c^2, hence 25=c225=c^2. Taking the positive square root gives c=5c=5. The calculation figures show these steps.
  4. Check the result. Since 32+42=9+16=25=523^2+4^2=9+16=25=5^2, the hypotenuse is 55 units long.

Takeaway: The hypotenuse is the side opposite the right angle and must be the unknown in a2+b2=c2a^2+b^2=c^2.

14. Example 9.23

Example 9.23

Example 9.23

Use the Pythagorean Theorem to find the length of the longer leg.

Solution

  1. Identify the missing leg. The right triangle has one leg of length 55, the other leg bb, and hypotenuse 1313. The diagram marks the right angle between the legs.
  2. Apply the Pythagorean Theorem. Using a2+b2=c2a^2+b^2=c^2, substitute the known lengths to get 52+b2=1325^2+b^2=13^2.
  3. Solve for the missing length. Simplifying gives 25+b2=16925+b^2=169, so b2=144b^2=144. Taking the positive square root gives b=12b=12, as the solution figure shows.
  4. Check the result. Since 52+122=25+144=169=1325^2+12^2=25+144=169=13^2, the longer leg is 1212 units.

Takeaway: When a leg is unknown, subtract the known leg's square from the hypotenuse's square before taking a square root.

15. Example 9.24

Example 9.24

Example 9.24

Kelvin is building a gazebo and wants to brace each corner by placing a 10−inch\mathrm{10-inch} wooden bracket diagonally as shown. How far below the corner should he fasten the bracket if he wants the distances from the corner to each end of the bracket to be equal? Approximate to the nearest tenth of an inch.

Solution

  1. Identify the equal legs. The bracket is the hypotenuse, measuring 1010 inches. The distances from the corner to its ends are equal, so each leg has length xx inches, as the diagram shows.
  2. Apply the Pythagorean Theorem. Since a2+b2=c2a^2+b^2=c^2, substituting equal legs and the hypotenuse gives x2+x2=102x^2+x^2=10^2.
  3. Solve for the distance below the corner. Combining terms gives 2x2=1002x^2=100, so x2=50x^2=50 and x=sqrt50approx7.1x=\\sqrt{50}\\approx7.1. The calculation figures show these steps.
  4. Check the approximation. Since (7.1)2+(7.1)2approx100=102(7.1)^2+(7.1)^2\\approx100=10^2, Kelvin should fasten the bracket approximately 7.17.1 inches below the corner.

Takeaway: For an isosceles right triangle with hypotenuse cc, each leg is fraccsqrt2\\frac{c}{\\sqrt{2}}.

16. Section 9.3 Exercises

Section 9.3 Exercises

Section 9.3 Exercises

Use the Properties of Angles

In the following exercises, find ⓐ the supplement and ⓑ the complement of the given angle.

In the following exercises, use the properties of angles to solve.

Use the Properties of Triangles

In the following exercises, solve using properties of triangles.

Find the Length of the Missing Side

In the following exercises, ΔABC\Delta{}ABC is similar to ΔXYZ.\Delta{}XYZ. Find the length of the indicated side.

On a map, San Francisco, Las Vegas, and Los Angeles form a triangle whose sides are shown in the figure below. The actual distance from Los Angeles to Las Vegas is 270270 miles.

Use the Pythagorean Theorem

In the following exercises, use the Pythagorean Theorem to find the length of the hypotenuse.

Find the Length of the Missing Side

In the following exercises, use the Pythagorean Theorem to find the length of the missing side. Round to the nearest tenth, if necessary.

In the following exercises, solve. Approximate to the nearest tenth, if necessary.

Everyday Math

Writing Exercises

17. Self Check

Self Check

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ What does this checklist tell you about your mastery of this section? What steps will you take to improve?

18. Practice 12

  1. The two smaller angles of a right triangle have equal measures. Find the measures of all three angles.
  1. The angles in a triangle are such that the measure of one angle is twice the measure of the smallest angle, while the measure of the third angle is three times the measure of the smallest angle. Find the measures of all three angles.

19. Practice 1

  1. An angle measures 25∘.\mathrm{25^{\circ}}. Find its: ⓐ supplement ⓑ complement.
  1. An angle measures 77∘.\mathrm{77^{\circ}}. Find its: ⓐ supplement ⓑ complement.

20. Practice 2

  1. Two angles are supplementary. The larger angle is 100∘\mathrm{100^{\circ}} more than the smaller angle. Find the measures of both angles.
  1. Two angles are complementary. The larger angle is 40∘\mathrm{40^{\circ}} more than the smaller angle. Find the measures of both angles.

21. Practice 3

  1. The measures of two angles of a triangle are 31∘\mathrm{31^{\circ}} and 128∘.\mathrm{128^{\circ}}. Find the measure of the third angle.
  1. A triangle has angles of 49∘\mathrm{49^{\circ}} and 75∘.\mathrm{75^{\circ}}. Find the measure of the third angle.

22. Practice 4

  1. One angle of a right triangle measures 56∘.\mathrm{56^{\circ}}. What is the measure of the other angle?
  1. One angle of a right triangle measures 45∘.\mathrm{45^{\circ}}. What is the measure of the other angle?

23. Practice 5

  1. The measure of one angle of a right triangle is 50∘\mathrm{50^{\circ}} more than the measure of the smallest angle. Find the measures of all three angles.
  1. The measure of one angle of a right triangle is 30∘\mathrm{30^{\circ}} more than the measure of the smallest angle. Find the measures of all three angles.

24. Practice 6

  1. John puts the base of a 13−ft\mathrm{13-ft} ladder 55 feet from the wall of his house. How far up the wall does the ladder reach?
  1. Randy wants to attach a 17−ft\mathrm{17-ft} string of lights to the top of the 15−ft\mathrm{15-ft} mast of his sailboat. How far from the base of the mast should he attach the end of the light string?

25. Practice 7

  1. 53∘\mathrm{53^{\circ}}
  1. 29∘\mathrm{29^{\circ}}

26. Practice 8

  1. Find the supplement of a 135∘\mathrm{135^{\circ}} angle.
  1. Find the complement of a 27.5∘27.5^{\circ} angle.

27. Practice 9

  1. Two angles are supplementary. The larger angle is 56∘\mathrm{56^{\circ}} more than the smaller angle. Find the measures of both angles.
  1. Two angles are complementary. The smaller angle is 34∘\mathrm{34^{\circ}} less than the larger angle. Find the measures of both angles.

28. Practice 10

  1. The measures of two angles of a triangle are 26∘\mathrm{26^{\circ}} and 98∘.\mathrm{98^{\circ}}. Find the measure of the third angle.
  1. The measures of two angles of a triangle are 105∘\mathrm{105^{\circ}} and 31∘.\mathrm{31^{\circ}}. Find the measure of the third angle.

29. Practice 11

  1. One angle of a right triangle measures 33∘.\mathrm{33^{\circ}}. What is the measure of the other angle?
  1. One angle of a right triangle measures 22.5∘.22.5^{\circ}. What is the measure of the other angle?

30. Practice 13

  1. Find the distance from Los Angeles to San Francisco.
  1. A 13−foot\mathrm{13-foot} string of lights will be attached to the top of a 12−foot\mathrm{12-foot} pole for a holiday display. How far from the base of the pole should the end of the string of lights be anchored?

31. Practice 14

  1. Chi is planning to put a path of paving stones through her flower garden. The flower garden is a square with sides of 1010 feet. What will the length of the path be?
  1. Building a scale model Joe wants to build a doll house for his daughter. He wants the doll house to look just like his house. His house is 3030 feet wide and 3535 feet tall at the highest point of the roof. If the dollhouse will be 2.52.5 feet wide, how tall will its highest point be?

32. Practice 15

  1. Write three of the properties of triangles from this section and then explain each in your own words.

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