Prealgebra 2e · free preview

9.6 Solve Geometry Applications: Volume and Surface Area

Learning objectives: Find volume and surface area of rectangular solids; Find volume and surface area of spheres; Find volume and surface area of cylinders; Find volume of cones

1. Learning objectives

Learning objectives

Learning objectives

  • Find volume and surface area of rectangular solids
  • Find volume and surface area of spheres
  • Find volume and surface area of cylinders
  • Find volume of cones

In this section, we will finish our study of geometry applications. We find the volume and surface area of some three-dimensional figures. Since we will be solving applications, we will once again show our Problem-Solving Strategy for Geometry Applications.

Problem Solving Strategy for Geometry Applications

  1. Step 1. Read the problem and make sure you understand all the words and ideas. Draw the figure and label it with the given information.
  1. Step 2. Identify what you are looking for.
  1. Step 3. Name what you are looking for. Choose a variable to represent that quantity.
  1. Step 4. Translate into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.
  1. Step 5. Solve the equation using good algebra techniques.
  1. Step 6. Check the answer in the problem and make sure it makes sense.
  1. Step 7. Answer the question with a complete sentence.

2. Find Volume and Surface Area of Rectangular Solids

Find Volume and Surface Area of Rectangular Solids

A cheerleading coach is having the squad paint wooden crates with the school colors to stand on at the games. (See Figure 9.28). The amount of paint needed to cover the outside of each box is the surface area, a square measure of the total area of all the sides. The amount of space inside the crate is the volume, a cubic measure.

Each crate is in the shape of a rectangular solid. Its dimensions are the length, width, and height. The rectangular solid shown in Figure 9.29 has length 44 units, width 22 units, and height 33 units. Can you tell how many cubic units there are altogether? Let’s look layer by layer.

Altogether there are 2424 cubic units. Notice that 2424 is the length × width × height.\mathrm{length}\,\times\,\mathrm{width}\,\times\,\mathrm{height}.

The volume, V,V, of any rectangular solid is the product of the length, width, and height.

V=LWHV=LWH

We could also write the formula for volume of a rectangular solid in terms of the area of the base. The area of the base, B,B, is equal to length×width.\mathrm{length}\times\mathrm{width}.

B=L⋅WB=L\cdot{}W

We can substitute BB for L⋅WL\cdot{}W in the volume formula to get another form of the volume formula.

We now have another version of the volume formula for rectangular solids. Let’s see how this works with the 4 × 2 × 34\,\times\,2\,\times\,3 rectangular solid we started with. See Figure 9.29.

To find the surface area of a rectangular solid, think about finding the area of each of its faces. How many faces does the rectangular solid above have? You can see three of them.

Afront=L×WAside=L×WAtop=L×WAfront=4⋅3Aside=2⋅3Atop=4⋅2Afront=12Aside=6Atop=8\begin{array}{lcclccl} {A}_{\mathrm{front}}=L\times{}W & & & {A}_{\mathrm{side}}=L\times{}W & & & {A}_{\mathrm{top}}=L\times{}W \\ {A}_{\mathrm{front}}=4\cdot{}3 & & & {A}_{\mathrm{side}}=2\cdot{}3 & & & {A}_{\mathrm{top}}=4\cdot{}2 \\ {A}_{\mathrm{front}}=12 & & & {A}_{\mathrm{side}}=6 & & & {A}_{\mathrm{top}}=8 \\ \end{array}

Notice for each of the three faces you see, there is an identical opposite face that does not show.

S=(front+back)+(leftside+rightside)+(top+bottom)S=(2⋅front)+(2⋅leftside)+(2⋅top)S=2⋅12+2⋅6+2⋅8S=24+12+16S=52 sq.units\begin{array}{c} S=(\mathrm{front}+\mathrm{back})+(\mathrm{left side}+\mathrm{right side})+(\mathrm{top}+\mathrm{bottom}) \\ S=(2\cdot\mathrm{front})+(2\cdot\mathrm{left side})+(2\cdot\mathrm{top}) \\ S=2\cdot{}12+2\cdot{}6+2\cdot{}8 \\ S=24+12+16 \\ S=52\,\mathrm{sq. units} \\ \end{array}

The surface area SS of the rectangular solid shown in Figure 9.30 is 5252 square units.

In general, to find the surface area of a rectangular solid, remember that each face is a rectangle, so its area is the product of its two dimensions, either length and width, length and height, or width and height (see Figure 9.31). Find the area of each face that you see and then multiply each area by two to account for the face on the opposite side.

S=2LH+2LW+2WHS=2LH+2LW+2WH

For a rectangular solid with length L,L, width W,W, and height H:H:

3. Example 9.47

Example 9.47

Example 9.47

For a rectangular solid with length 1414 cm, height 1717 cm, and width 99 cm, find the ⓐ volume and ⓑ surface area.

Solution

  1. State the volume formula. A rectangular solid has volume V=LWHV=LWH. Substituting the dimensions gives V=(14)(9)(17)=126(17)=2142V=(14)(9)(17)=126(17)=2142 cubic centimeters.
  2. State the surface-area formula. Use S=2LH+2LW+2WHS=2LH+2LW+2WH, so S=2(14)(17)+2(14)(9)+2(9)(17)S=2(14)(17)+2(14)(9)+2(9)(17).
  3. Evaluate the surface area. The three doubled face areas are 476476, 252252, and 306306 square centimeters, which sum to 10341034 square centimeters.
  4. Check the units. Volume describes the enclosed space and has cubic units, while surface area describes the exterior faces and has square units.
  5. State both answers. The volume is 21422142 cubic centimeters, and the surface area is 10341034 square centimeters.

Takeaway: Use V=LWHV=LWH for a rectangular solid's volume and S=2LH+2LW+2WHS=2LH+2LW+2WH for its surface area; the dimensions 1414 by 99 by 1717 give 21422142 cubic centimeters and 10341034 square centimeters.

4. Example 9.48

Example 9.48

Example 9.48

A rectangular crate has a length of 3030 inches, width of 2525 inches, and height of 2020 inches. Find its ⓐ volume and ⓑ surface area.

Solution

  1. Calculate the volume. Use V=LWHV=LWH with the crate dimensions to obtain V=(30)(25)(20)=750(20)=15000V=(30)(25)(20)=750(20)=15000 cubic inches.
  2. Set up the surface area. The formula S=2LH+2LW+2WHS=2LH+2LW+2WH becomes S=2(30)(20)+2(30)(25)+2(25)(20)S=2(30)(20)+2(30)(25)+2(25)(20).
  3. Evaluate the three face pairs. The contributions are 12001200, 15001500, and 10001000 square inches, giving S=1200+1500+1000=3700S=1200+1500+1000=3700 square inches.
  4. Check the units. The enclosed volume is measured in cubic inches, while the six exterior faces are measured in square inches.
  5. State both answers. The crate has volume 1500015000 cubic inches and surface area 37003700 square inches.

Takeaway: A crate with dimensions 3030 by 2525 by 2020 has volume 1500015000 cubic inches and surface area 37003700 square inches.

5. Volume and Surface Area of a Cube

Volume and Surface Area of a Cube

A cube is a rectangular solid whose length, width, and height are equal. See Volume and Surface Area of a Cube, below. Substituting, s for the length, width and height into the formulas for volume and surface area of a rectangular solid, we get:

V=LWHS=2LH+2LW+2WHV=s⋅s⋅sS=2s⋅s+2s⋅s+2s⋅sV=s3S=2s2+2s2+2s2S=6s2\begin{array}{lcccl} V=LWH & & & & S=2LH+2LW+2WH \\ V=s\cdot{}s\cdot{}s & & & & S=2s\cdot{}s+2s\cdot{}s+2s\cdot{}s \\ V={s}^{3} & & & & S=2{s}^{2}+2{s}^{2}+2{s}^{2} \\ & & & & S=6{s}^{2} \\ \end{array}

So for a cube, the formulas for volume and surface area are V=s3V={s}^{3} and S=6s2.S=6{s}^{2}.

For any cube with sides of length s,s,

6. Example 9.49

Example 9.49

Example 9.49

A cube is 2.52.5 inches on each side. Find its ⓐ volume and ⓑ surface area.

Solution

  1. Calculate the cube volume. A cube has side length ss, so V=s3V=s^3. Substituting s=2.5s=2.5 gives V=(2.5)3=15.625V=(2.5)^3=15.625 cubic inches.
  2. Calculate the cube surface area. The formula S=6s2S=6s^2 gives S=6(2.5)2=6(6.25)=37.5S=6(2.5)^2=6(6.25)=37.5 square inches.
  3. Check the formulas. The volume is the side length multiplied by itself three times, while the surface area counts six congruent square faces.
  4. State both answers. The cube has volume 15.62515.625 cubic inches and surface area 37.537.5 square inches.

Takeaway: For a cube with side ss, use V=s3V=s^3 and S=6s2S=6s^2; a side of 2.52.5 inches gives volume 15.62515.625 and surface area 37.537.5 square inches.

7. Example 9.50

Example 9.50

Example 9.50

A notepad cube measures 22 inches on each side. Find its ⓐ volume and ⓑ surface area.

Solution

  1. Calculate the cube volume. With side length s=2s=2 inches, use V=s3V=s^3 to obtain V=23=8V=2^3=8 cubic inches.
  2. Calculate the cube surface area. Use S=6s2S=6s^2 to obtain S=6(22)=6(4)=24S=6(2^2)=6(4)=24 square inches.
  3. Check the formulas. The three factors in s3s^3 describe the cube's length, width, and height, while 6s26s^2 counts its six square faces.
  4. State both answers. The notepad cube has volume 88 cubic inches and surface area 2424 square inches.

Takeaway: A cube's volume is s3s^3 and its surface area is 6s26s^2, so a side of 22 inches gives volume 88 cubic inches and surface area 2424 square inches.

8. Find the Volume and Surface Area of Spheres

Find the Volume and Surface Area of Spheres

A sphere is the shape of a basketball, like a three-dimensional circle. Just like a circle, the size of a sphere is determined by its radius, which is the distance from the center of the sphere to any point on its surface. The formulas for the volume and surface area of a sphere are given below.

Showing where these formulas come from, like we did for a rectangular solid, is beyond the scope of this course. We will approximate π\pi with 3.14.3.14.

For a sphere with radius r:r:

9. Example 9.51

Example 9.51

Example 9.51

A sphere has a radius 66 inches. Find its ⓐ volume and ⓑ surface area.

Solution

  1. Calculate the sphere volume. Use V=43πr3V=\frac{4}{3}\pi r^3 with r=6r=6 to get V≈43(3.14)(63)=904.32V\approx\frac{4}{3}(3.14)(6^3)=904.32 cubic inches.
  2. Calculate the sphere surface area. Use S=4πr2S=4\pi r^2 to get S≈4(3.14)(62)=452.16S\approx4(3.14)(6^2)=452.16 square inches.
  3. Check the powers and units. The volume uses r3r^3 and cubic inches, whereas the surface area uses r2r^2 and square inches.
  4. State both answers. The sphere has volume approximately 904.32904.32 cubic inches and surface area approximately 452.16452.16 square inches.

Takeaway: For a sphere of radius rr, use V=43πr3V=\frac{4}{3}\pi r^3 and S=4πr2S=4\pi r^2; radius 66 inches gives approximately 904.32904.32 cubic inches and 452.16452.16 square inches.

10. Example 9.52

Example 9.52

Example 9.52

A globe of Earth is in the shape of a sphere with radius 1414 inches. Find its ⓐ volume and ⓑ surface area. Round the answer to the nearest hundredth.

Solution

  1. Calculate the sphere volume. Substitute r=14r=14 into V=43πr3V=\frac{4}{3}\pi r^3 to get V≈43(3.14)(143)=11488.21V\approx\frac{4}{3}(3.14)(14^3)=11488.21 cubic inches after rounding.
  2. Calculate the sphere surface area. Substitute r=14r=14 into S=4πr2S=4\pi r^2 to get S≈4(3.14)(142)=2461.76S\approx4(3.14)(14^2)=2461.76 square inches after rounding.
  3. Check the powers and units. The volume formula cubes the radius and uses cubic inches, while the surface-area formula squares it and uses square inches.
  4. State both answers. The globe has volume approximately 11488.2111488.21 cubic inches and surface area approximately 2461.762461.76 square inches.

Takeaway: A sphere of radius 1414 inches has volume approximately 11488.2111488.21 cubic inches and surface area approximately 2461.762461.76 square inches.

11. Find the Volume and Surface Area of a Cylinder

Find the Volume and Surface Area of a Cylinder

If you have ever seen a can of soda, you know what a cylinder looks like. A cylinder is a solid figure with two parallel circles of the same size at the top and bottom. The top and bottom of a cylinder are called the bases. The height hh of a cylinder is the distance between the two bases. For all the cylinders we will work with here, the sides and the height, hh , will be perpendicular to the bases.

Rectangular solids and cylinders are somewhat similar because they both have two bases and a height. The formula for the volume of a rectangular solid, V=BhV=Bh , can also be used to find the volume of a cylinder.

For the rectangular solid, the area of the base, BB , is the area of the rectangular base, length × width. For a cylinder, the area of the base, B,B, is the area of its circular base, πr2.\pi{r}^{2}. Figure 9.33 compares how the formula V=BhV=Bh is used for rectangular solids and cylinders.

To understand the formula for the surface area of a cylinder, think of a can of vegetables. It has three surfaces: the top, the bottom, and the piece that forms the sides of the can. If you carefully cut the label off the side of the can and unroll it, you will see that it is a rectangle. See Figure 9.34.

The distance around the edge of the can is the circumference of the cylinder’s base it is also the length LL of the rectangular label. The height of the cylinder is the width WW of the rectangular label. So the area of the label can be represented as

To find the total surface area of the cylinder, we add the areas of the two circles to the area of the rectangle.

The surface area of a cylinder with radius rr and height h,h, is

S=2πr2+2πrhS=2\pi{r}^{2}+2\pi{}rh

For a cylinder with radius rr and height h:h:

12. Example 9.53

Example 9.53

Example 9.53

A cylinder has height 55 inches and radius 33 inches. Find the ⓐ volume and ⓑ surface area.

Solution

  1. Calculate the cylinder volume. Use V=πr2hV=\pi r^2h with r=3r=3 and h=5h=5 to get V≈(3.14)(32)(5)=141.3V\approx(3.14)(3^2)(5)=141.3 cubic inches.
  2. Calculate the cylinder surface area. Use S=2πr2+2πrhS=2\pi r^2+2\pi rh to get S≈2(3.14)(32)+2(3.14)(3)(5)=150.72S\approx2(3.14)(3^2)+2(3.14)(3)(5)=150.72 square inches.
  3. Check the two bases and curved surface. The first term in the surface-area formula counts both circular bases, and the second counts the curved lateral surface.
  4. State both answers. The cylinder has volume approximately 141.3141.3 cubic inches and surface area approximately 150.72150.72 square inches.

Takeaway: For a cylinder, use V=πr2hV=\pi r^2h and S=2πr2+2πrhS=2\pi r^2+2\pi rh; radius 33 and height 55 inches give approximately 141.3141.3 cubic inches and 150.72150.72 square inches.

13. Example 9.54

Example 9.54

Example 9.54

Find the ⓐ volume and ⓑ surface area of a can of soda. The radius of the base is 44 centimeters and the height is 1313 centimeters. Assume the can is shaped exactly like a cylinder.

Solution

  1. Calculate the can volume. Use V=πr2hV=\pi r^2h with r=4r=4 and h=13h=13 to get V≈(3.14)(42)(13)=653.12V\approx(3.14)(4^2)(13)=653.12 cubic centimeters.
  2. Calculate the can surface area. Use S=2πr2+2πrhS=2\pi r^2+2\pi rh to get S≈2(3.14)(42)+2(3.14)(4)(13)=427.04S\approx2(3.14)(4^2)+2(3.14)(4)(13)=427.04 square centimeters.
  3. Check the cylinder structure. The volume uses the circular base area times the height, while the surface area includes two bases and the curved side.
  4. State both answers. The can has volume approximately 653.12653.12 cubic centimeters and surface area approximately 427.04427.04 square centimeters.

Takeaway: A cylindrical can with radius 44 and height 1313 centimeters has volume approximately 653.12653.12 cubic centimeters and surface area approximately 427.04427.04 square centimeters.

14. Find the Volume of Cones

Find the Volume of Cones

The first image that many of us have when we hear the word ‘cone’ is an ice cream cone. There are many other applications of cones (but most are not as tasty as ice cream cones). In this section, we will see how to find the volume of a cone.

In geometry, a cone is a solid figure with one circular base and a vertex. The height of a cone is the distance between its base and the vertex.The cones that we will look at in this section will always have the height perpendicular to the base. See Figure 9.35.

Earlier in this section, we saw that the volume of a cylinder is V=πr2h.V=\pi{}{r}^{2}h. We can think of a cone as part of a cylinder. Figure 9.36 shows a cone placed inside a cylinder with the same height and same base. If we compare the volume of the cone and the cylinder, we can see that the volume of the cone is less than that of the cylinder.

In fact, the volume of a cone is exactly one-third of the volume of a cylinder with the same base and height. The volume of a cone is

Since the base of a cone is a circle, we can substitute the formula of area of a circle, πr2\pi{}{r}^{2} , for BB to get the formula for volume of a cone.

In this course, we will only find the volume of a cone, and not its surface area.

For a cone with radius rr and height hh.

15. Example 9.55

Example 9.55

Example 9.55

Find the volume of a cone with height 66 inches and radius of its base 22 inches.

Solution

  1. State the cone volume formula. Use V=13πr2hV = \frac{1}{3}\pi r^2h, where rr is the base radius and hh is the perpendicular height.
  2. Substitute the dimensions. With r=2r = 2 inches and h=6h = 6 inches, the formula becomes V=13π(2)2(6)V = \frac{1}{3}\pi(2)^2(6).
  3. Simplify the product. Since (2)2(6)=24(2)^2(6) = 24, we obtain V=8πV = 8\pi. Using π≈3.14\pi \approx 3.14 gives V≈25.12V \approx 25.12 cubic inches.
  4. Confirm the diagram. The figure shows a cone with base radius 22 inches and height 66 inches, matching the values used in the formula. Therefore the cone's volume is approximately 25.1225.12 cubic inches.

Takeaway: The volume of a cone equals one third of πr2h\pi r^2h because it has one third the volume of the matching cylinder.

16. Example 9.56

Example 9.56

Example 9.56

Marty’s favorite gastro pub serves french fries in a paper wrap shaped like a cone. What is the volume of a conic wrap that is 88 inches tall and 55 inches in diameter? Round the answer to the nearest hundredth.

Solution

  1. Find the radius from the diameter. The circular opening is 55 inches across, so r=52=2.5r = \frac{5}{2} = 2.5 inches; the cone's height is h=8h = 8 inches.
  2. State and substitute the cone formula. Use V=13πr2hV = \frac{1}{3}\pi r^2h to write V=13(3.14)(2.5)2(8)V = \frac{1}{3}(3.14)(2.5)^2(8).
  3. Evaluate the expression. The squared radius is 6.256.25, and 13(3.14)(6.25)(8)≈52.33\frac{1}{3}(3.14)(6.25)(8) \approx 52.33.
  4. Interpret the diagram. The illustration depicts an inverted cone with height 88 inches and a circular opening measuring 55 inches, the quantity identified as the diameter in the problem. Thus the conic wrap's volume is approximately 52.3352.33 cubic inches.

Takeaway: Convert a cone's diameter to radius before substituting, because the volume formula contains r2r^2.

17. Summary of Geometry Formulas

Summary of Geometry Formulas

The following charts summarize all of the formulas covered in this chapter.

Section 9.6 Exercises

Find Volume and Surface Area of Rectangular Solids

In the following exercises, find ⓐ the volume and ⓑ the surface area of the rectangular solid with the given dimensions.

In the following exercises, solve.

In the following exercises, find ⓐ the volume and ⓑ the surface area of the cube with the given side length.

In the following exercises, solve.

Find the Volume and Surface Area of Spheres

In the following exercises, find ⓐ the volume and ⓑ the surface area of the sphere with the given radius. Round answers to the nearest hundredth.

In the following exercises, solve. Round answers to the nearest hundredth.

Find the Volume and Surface Area of a Cylinder

In the following exercises, find ⓐ the volume and ⓑ the surface area of the cylinder with the given radius and height. Round answers to the nearest hundredth.

In the following exercises, solve. Round answers to the nearest hundredth.

Find the Volume of Cones

In the following exercises, find the volume of the cone with the given dimensions. Round answers to the nearest hundredth.

In the following exercises, solve. Round answers to the nearest hundredth.

Everyday Math

Writing Exercises

18. Self Check

Self Check

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

ⓑ After reviewing this checklist, what will you do to become confident for all objectives?

19. Practice 1

  1. Find the ⓐ volume and ⓑ surface area of rectangular solid with the: length 88 feet, width 99 feet, and height 1111 feet.
  1. Find the ⓐ volume and ⓑ surface area of rectangular solid with the: length 1515 feet, width 1212 feet, and height 88 feet.
  1. A rectangular box has length 99 feet, width 44 feet, and height 66 feet. Find its ⓐ volume and ⓑ surface area.

20. Practice 2

  1. For a cube with side 4.5 meters, find the ⓐ volume and ⓑ surface area of the cube.
  1. For a cube with side 7.3 yards, find the ⓐ volume and ⓑ surface area of the cube.
  1. A packing box is a cube measuring 44 feet on each side. Find its ⓐ volume and ⓑ surface area.

21. Practice 3

  1. A wall is made up of cube-shaped bricks. Each cube is 1616 inches on each side. Find the ⓐ volume and ⓑ surface area of each cube.
  1. Find the ⓐ volume and ⓑ surface area of a sphere with radius 3 centimeters.
  1. Find the ⓐ volume and ⓑ surface area of each sphere with a radius of 11 foot

22. Practice 4

  1. A beach ball is in the shape of a sphere with radius of 99 inches. Find its ⓐ volume and ⓑ surface area.
  1. A Roman statue depicts Atlas holding a globe with radius of 1.51.5 feet. Find the ⓐ volume and ⓑ surface area of the globe.
  1. Find the ⓐ volume and ⓑ surface area of the cylinder with radius 4 cm and height 7cm.

23. Practice 5

  1. Find the ⓐ volume and ⓑ surface area of the cylinder with given radius 2 ft and height 8 ft.
  1. Find the ⓐ volume and ⓑ surface area of a can of paint with radius 8 centimeters and height 19 centimeters. Assume the can is shaped exactly like a cylinder.
  1. Find the ⓐ volume and ⓑ surface area of a cylindrical drum with radius 2.7 feet and height 4 feet. Assume the drum is shaped exactly like a cylinder.

24. Practice 6

  1. Find the volume of a cone with height 77 inches and radius 33 inches
  1. Find the volume of a cone with height 99 centimeters and radius 55 centimeters
  1. How many cubic inches of candy will fit in a cone-shaped piñata that is 1818 inches long and 1212 inches across its base? Round the answer to the nearest hundredth.

25. Practice 7

  1. What is the volume of a cone-shaped party hat that is 1010 inches tall and 77 inches across at the base? Round the answer to the nearest hundredth.
  1. length 22 meters, width 1.51.5 meters, height 33 meters
  1. length 3.53.5 yards, width 2.12.1 yards, height 2.42.4 yards

26. Practice 8

  1. Moving van A rectangular moving van has length 1616 feet, width 88 feet, and height 88 feet. Find its ⓐ volume and ⓑ surface area.
  1. Carton A rectangular carton has length 21.321.3 cm, width 24.224.2 cm, and height 6.56.5 cm. Find its ⓐ volume and ⓑ surface area.
  1. 55 centimeters

27. Practice 9

  1. 10.410.4 feet
  1. Science center Each side of the cube at the Discovery Science Center in Santa Ana is 6464 feet long. Find its ⓐ volume and ⓑ surface area.
  1. Base of statue The base of a statue is a cube with sides 2.82.8 meters long. Find its ⓐ volume and ⓑ surface area.

28. Practice 10

  1. 33 centimeters
  1. 7.57.5 feet
  1. Exercise ball An exercise ball has a radius of 1515 inches. Find its ⓐ volume and ⓑ surface area.

29. Practice 11

  1. Golf ball A golf ball has a radius of 4.54.5 centimeters. Find its ⓐ volume and ⓑ surface area.
  1. radius 33 feet, height 99 feet
  1. radius 1.51.5 meters, height 4.24.2 meters

30. Practice 12

  1. Coffee can A can of coffee has a radius of 55 cm and a height of 1313 cm. Find its ⓐ volume and ⓑ surface area.
  1. Barber shop pole A cylindrical barber shop pole has a diameter of 66 inches and height of 2424 inches. Find its ⓐ volume and ⓑ surface area.
  1. height 99 feet and radius 22 feet

31. Practice 13

  1. height 12.412.4 centimeters and radius 55 cm
  1. Teepee What is the volume of a cone-shaped teepee tent that is 1010 feet tall and 1010 feet across at the base?
  1. Silo What is the volume of a cone-shaped silo that is 5050 feet tall and 7070 feet across at the base?

32. Practice 14

  1. Street light post The post of a street light is shaped like a truncated cone, as shown in the picture below. It is a large cone minus a smaller top cone. The large cone is 3030 feet tall with base radius 11 foot. The smaller cone is 1010 feet tall with base radius of 0.50.5 feet. To the nearest tenth,
  1. ⓐ find the volume of the large cone.
  1. ⓑ find the volume of the small cone.
  1. ⓒ find the volume of the post by subtracting the volume of the small cone from the volume of the large cone.
  1. The formulas for the volume of a cylinder and a cone are similar. Explain how you can remember which formula goes with which shape.

Practice this interactively

Free account · instant grading · spaced review that schedules itself.

Start this course for free